|
    
- 帖子
- 3852
- 积分
- 13044
- 威望
- 16780
- 金钱
- 36761
- 在线时间
- 1139 小时
         
|
原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm/ P# O4 U$ d9 }. q/ K: i
原始出处:http://www.3ast.com.cm
! r6 n) z ?3 ^5 p4 ]7 r
$ N, f L# T: U( H9 I看不懂的直接绕过2 c% k# I6 @( z4 |# W {" d
加密前为:hwy123456
/ _" s; |) u) {& t) Z加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
0 g% }' B* s4 \ Y6 k: e/ E$ s& U8 w' N8 Z
============================================
- e3 i, p, D) w5 n+ \; o上面是当时自己校内的心情。现在已经解破出来了,分享给大家
" |7 G% f' n" e也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法! f2 B! P* ~6 n
以下是RSA算法文件
2 ~9 G& @8 ^ v, c3 [% l1 a$ @- l' m
文件名RSA.ASP
9 K9 \. @$ a9 A N===============================================
; `9 s* Y! g8 Y+ g) a5 J/ S. _<%
' I, J& g( m' N; KClass clsRSA 0 X* b/ D3 X- i: K; Q
Public PrivateKey
8 ^% y* z( j' I! kPublic PublicKey . ~- V- k$ _* G) a$ u' O4 M2 E
Public Modulus
! X; h Y2 Z1 d# h4 tPublic Function Crypt(pLngMessage, pLngKey)
$ C5 t7 J; }+ r# D$ lOn Error Resume Next
! x/ \' a$ e9 q" S" }Dim lLngMod 3 p& T0 r0 _7 b: A
Dim lLngResult " w( g5 {/ h6 {9 s: s
Dim lLngIndex $ L6 ]+ N3 t2 \0 D* y( a
If pLngKey Mod 2 = 0 Then % {% N( u4 C5 s( D5 M0 v2 g
lLngResult = 1
. e" ^! |: e3 Z4 I; [For lLngIndex = 1 To pLngKey / 2
" j# o+ X$ f1 _1 D- I$ |lLngMod = (pLngMessage ^ 2) Mod Modulus
5 i% W# H; Y( d1 W' Mod may error on key generation
# @0 x7 N( P3 u T3 Z% ~* xlLngResult = (lLngMod * lLngResult) Mod Modulus
6 x$ [8 x: N1 \( Q# CIf Err Then Exit Function
5 p3 i# J1 F& z+ P8 V& {/ GNext
3 E0 w7 w, J& s AElse 1 S; ]9 U- j/ Q6 Z2 p; N
lLngResult = pLngMessage
{4 r9 M4 D4 Z# T2 aFor lLngIndex = 1 To pLngKey / 2
" b. s( M8 P7 Z- Y9 I; `lLngMod = (pLngMessage ^ 2) Mod Modulus
: A C, V. |4 l8 ~On Error Resume Next 1 k0 w% Y q% ^# B% z
' Mod may error on key generation ( o0 t# M* N, J+ `2 Q! _1 `7 e$ v
lLngResult = (lLngMod * lLngResult) Mod Modulus
% s- z% |8 [# R. SIf Err Then Exit Function _+ Q1 {, G: y& K% Z N8 K7 x
Next & J! R/ v- P% w) i( d
End If
/ ^. c. D6 u6 I7 @: xCrypt = lLngResult
5 t1 {/ B- c5 d) z, W9 M$ YEnd Function
6 i6 |! A* ~' t4 F' n! @! l5 v$ q/ i
Public Function Encode(ByVal pStrMessage) # c4 `* f3 q4 ]* R
Dim lLngIndex
, @0 U- j4 ]. V+ E6 q0 O3 i4 S# YDim lLngMaxIndex
8 P' r: G( V: G. \8 GDim lBytAscii
* y3 W' X# \' G2 L. v* JDim lLngEncrypted 6 n8 M0 W' t$ {. f( t* Z
lLngMaxIndex = Len(pStrMessage)
2 @! q8 q1 f4 SIf lLngMaxIndex = 0 Then Exit Function 4 o3 {! L/ G5 b6 |, i4 r
For lLngIndex = 1 To lLngMaxIndex
# w" x$ v! {: E' Q5 I- `' y1 V7 hlBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
0 w6 O/ [6 J* e% H4 q) b) JlLngEncrypted = Crypt(lBytAscii, PublicKey) % V }5 b( @* Q2 Z
Encode = Encode & NumberToHex(lLngEncrypted, 4)
3 c, Y) w3 p+ g* _Next 4 D$ m0 _. M5 S' _5 c7 E+ W
End Function 1 `) G) a1 k3 }. S6 \' a6 @
Public Function Decode(ByVal pStrMessage)
! h9 q% [2 c/ c, E: U& eDim lBytAscii
% i3 i3 [0 o; T, x9 P% O6 }0 e% QDim lLngIndex 6 z, ^ W' j: _7 Q/ Y- F, ^( Y
Dim lLngMaxIndex 0 B2 I) j" ~( D# I7 `7 Y0 B$ f
Dim lLngEncryptedData 1 M1 `3 u( v6 F3 s* A
Decode = ""
% {5 z# ^! p, T. c7 r1 o+ {lLngMaxIndex = Len(pStrMessage) , I: T( o. d: h
For lLngIndex = 1 To lLngMaxIndex Step 4 0 X- }3 r# b7 [3 \$ ]$ T$ Y
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
, I, X0 z( f. J0 MlBytAscii = Crypt(lLngEncryptedData, PrivateKey)
2 N' G/ w' V8 V! p) [Decode = Decode & Chr(lBytAscii)
v/ a8 ~- \& u- B+ m# ONext / [0 W1 @# T' e5 E/ j' T
End Function
( s/ {3 W( R5 u+ k$ p) iPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) $ C( O$ ^: d. J$ P1 {8 Q5 y1 H) C
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) ! v& \0 J! Y" K; H! L
End Function 7 T& f# w2 L+ N% `" Z+ N
Private Function HexToNumber(ByRef pStrHex)
4 \* Z& }% f5 V! d- ?4 `HexToNumber = CLng("&h" & pStrHex)
3 l( e: H7 ?$ r& d8 _4 bEnd Function
/ ~+ |: t, b- M/ | rEnd Class ; q9 Q% _' B, B/ |4 [- d' q) B
function Encryptstr(Message) 1 V- A: h+ \; N: U/ t# Z7 M
Dim LngKeyE $ H) w: x$ w% l! O+ K: T o
Dim LngKeyD . l& M: ]) }, A# l
Dim LngKeyN 9 w% A5 Q. r1 g7 v* C
Dim StrMessage
7 B5 Z8 J2 v1 K ]8 e- \! V& vDim ObjRSA " k3 j5 |/ O8 s7 o6 n& b) [2 Z
LngKeyE = "32823"
7 K2 e2 z7 x' DLngKeyD = "20643"
! l& u1 w. Q( }2 |- a' ^/ E" |LngKeyN = "29893"
, T- q3 m) }2 Z+ B9 MStrMessage = Message
+ v# j( l* N# v" ^5 j3 G/ r$ u0 V4 ?Set ObjRSA = New clsRSA : x# i) k2 b: t( {& D; A
ObjRSA.PublicKey = LngKeyE 1 x- ?8 D. z+ P0 J7 E" L
ObjRSA.Modulus = LngKeyN
0 X7 w' A o9 G9 e7 G1 ?, W9 rEncryptstr = ObjRSA.Encode(StrMessage) " \* v2 K3 u7 c7 w
Set ObjRSA = Nothing . ^5 D" z8 C1 p+ m( R
end function
. K* f" \6 P3 O: x, R. QFunction Decryptstr(Message) $ h0 k+ C) m5 S$ ~# \8 ~3 {
Dim LngKeyE
- t8 S* a5 w& t% G) d" VDim LngKeyD
# s# R4 R+ z; w4 y2 p$ u1 SDim LngKeyN 7 t# S/ @4 Z6 H7 O1 S# R
Dim StrMessage
# [( g( Z" K0 ~2 gDim ObjRSA 2 Q9 r- _1 ?1 p6 h
LngKeyE = "32823" * ]4 M$ s2 G, i! n; Q6 e
LngKeyD = "20643"
+ A: c6 [% I) {2 u6 ]( yLngKeyN = "29893" . k6 b" K# w+ c+ y' S, u3 i) [
StrMessage = Message % { N4 [3 r" e0 J
Set ObjRSA = New clsRSA 5 w: K$ ]3 s/ S, A
ObjRSA.PrivateKey =LngKeyD ( U7 P8 O! C" [' J
ObjRSA.Modulus=LngKeyN
6 S) z/ i2 P0 Q9 Xdecryptstr=ObjRSA.Decode(StrMessage)
O9 y- C1 K- S$ G8 L4 bSet ObjRSA = Nothing ! X( q: f2 `, l C% r1 Q
end function ( z0 `- o& u) Q2 \+ A% h: t
%>
4 h" G, L4 a9 m: M) b% E W- g4 }. k===============================================
I( L! u0 X9 d1 e4 c; S. d+ S8 u" y$ ^' P1 l1 h0 _
还有一个用于测试这段代码的test.asp
% n: V7 A' I: Q- I6 x有兴趣的自己搭建个IIS测试下4 E1 x) {# V! v& q
<!--#INCLUDE FILE="RSA.asp"--> % k2 l; B8 ~) ~: L( [
<%4 i1 b& D" L- u* R+ G( T# l
function Encryptstr(Message) " D4 W2 C0 u6 l7 V
Dim LngKeyE 0 v: W6 S% t9 ^: j$ U
Dim LngKeyD
6 w7 D+ F' m! U5 |. NDim LngKeyN 7 M) e6 q' {0 f' O
Dim StrMessage # l1 h( r1 U) E) Z; _' ~# Y
Dim ObjRSA * [7 j- ?( B) \) x- e% z6 z# t
LngKeyE = "32823"
: R/ P9 j" X8 s$ T. f& y2 QLngKeyD = "20643"
# _: x+ X4 M& F! D! O+ K3 XLngKeyN = "29893" - F. c+ N' L% R; }/ z' s
StrMessage = Message
9 F C1 A- K8 o @7 y7 Z$ iSet ObjRSA = New clsRSA
& e1 N3 K0 Y: iObjRSA.PublicKey = LngKeyE
0 y2 o9 B) r0 O/ e5 pObjRSA.Modulus = LngKeyN 3 N7 A1 S+ Q- K
Encryptstr = ObjRSA.Encode(StrMessage) * Y3 ^& e/ O: a2 l! x
Set ObjRSA = Nothing 7 _: B" ^& }; G$ H
end function
& J/ V4 k2 ^+ Y {$ {7 L! A( Kfunction decryptstr(Message) ( J( r8 i/ J6 m
Dim LngKeyE # t6 B6 |$ h; s& |# X' R5 g! Y' V
Dim LngKeyD / M, x6 [/ _3 q4 ?- C0 {
Dim LngKeyN
7 u v4 A1 e; |. c& EDim StrMessage
c1 X1 ^- |1 f$ e' h! @Dim ObjRSA
: K0 W2 ?3 M% |$ h$ v5 G2 Q9 qLngKeyE = "32823"
' c4 M; v) D! v; {$ m% LLngKeyD = "20643" 2 D; B: l1 z1 w
LngKeyN = "29893" / }7 j8 r0 S# R( ~% R1 s
StrMessage = Message ( R3 x, D$ z5 l4 [6 ?) k
Set ObjRSA = New clsRSA
7 A) G! y; c7 h/ U2 X- JObjRSA.PrivateKey =LngKeyD
' [9 { `! D! _. x ^ObjRSA.Modulus=LngKeyN
5 v+ Q( A7 Z; G: I6 Cdecryptstr=ObjRSA.Decode(StrMessage)
5 ]+ q0 Y" S8 RSet ObjRSA = Nothing & K9 a4 ^& N. M7 o
end function 7 @1 r; z5 u0 D2 c) X
dim last,first
6 T5 q/ b# A- Q8 f+ Yfirst="!@#$%^&*()" 3 N, ? i4 T5 R6 [3 ^8 ^1 A% L
Response.Write "加密前为:"&first ! m* N+ t$ J8 ]
last=Encryptstr(first) 9 T# y- K3 N& M+ s/ ]: f
Response.Write "加密后为"&last n8 C' S0 e5 ? r7 Z7 y7 X+ A
Response.Write "解密后为" &decryptstr(last) 9 ?! N5 `2 O' \* C* }. g
%> ==============================================( ?" z2 {. x4 _$ S6 v: U
剩下的就是字符的对照表了
, j0 G5 P1 q1 ^1 j" Q" X& u===================字符集================* y) [3 E* H% d( ?6 K0 T9 S, f
1_____6EBB4 Z9 u' ]! ~: C6 K2 z) C; ^
2_____5C1F# d4 h- F6 q) p
3_____4D750 ~% a: M& X/ X# a# D9 Y
4_____26CC
1 P/ _. H' U, \5_____4F88
1 ~) X3 n: N7 H9 ?* X! \; W6_____3F4E# n7 U: C1 \! @4 S! z+ ~/ G* l
7_____0A9D* g# Y; p7 n; f o. ]9 V& Y9 n( Q$ n
8_____1A1C, s6 E3 _# x5 V" A4 ^/ a
9_____6D20
5 `: f& C+ ^; D; a! C& n0_____10898 L; g) h) F. I$ j# W. Q
a_____0F3E
2 k( i' [ P6 r: h' ?+ f5 n/ kb_____31593 B' C- _$ i) d
c_____35176 y, ]; j5 m+ r3 t
d_____419C
0 L. U" O# O7 V) `/ ~, Ae_____615C1 m. B+ z8 r8 A8 j6 D, K* W
f_____556F: q( d8 F( j! n3 s7 @
g_____2B7F( |: y0 T* G; A) O
h_____0F9C
5 E X1 u; D, ii_____00FA
/ T8 t! Q' R6 X# D p9 wj_____5A50
5 K# [+ E1 T0 }* A/ h# Ik_____28501 y( A% _/ J$ `
l_____3E7B
8 z* w' `) K1 E' Wm_____71C51 e) B# y) P( j
n_____1FC8
! |2 i* @% \" G( f8 ?o_____74C1
8 U( o: ?$ S9 `9 I0 {p_____5FB8
. X' ?6 h+ d: Y3 a# Cq_____6085
$ ]- d& D8 X, ~9 b1 Gr_____3AC4
) D8 Q5 [# Y- v us_____2F50# l* a0 |- k7 I
t_____36F8) q4 O( K; E; W
u_____7010
+ P3 L5 b! K& J5 O& S3 {' ov_____0B42
@4 i# f4 o6 c. P9 Jw_____1C7A$ T" T4 S$ t* N2 _& o4 U/ d
x_____16F8
0 F" L2 m3 r& M- G+ vy_____2EE7) J$ I3 Z. [; |% Z4 Y) A( @
z_____5CF3
& k! t& G) J: I0 S9 k( O!_____6233* v. q3 h; C! x8 d5 {
@_____3A45
% u m- s# `' K2 K8 B* y# [#_____22918 Q! M# u2 s! `! d7 U0 l8 w$ q
$_____5D5C0 I/ \% g$ T* g3 Z L2 r# s
%_____09B9$ ]0 b+ h3 f( n3 G! \* U; s* Y$ E
^_____43EA
: C+ h4 A9 U! [- n, c* R9 R$ r&_____62B9
0 y, J4 ^% t" b*_____6301
; O% m( i0 D5 J# ~, B(_____4659- N, C' _* Z1 M* M* A/ r4 z# D1 t
)_____5C82 |
|