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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
2 Q: M7 L! E- h4 p# x原始出处:http://www.3ast.com.cm
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看不懂的直接绕过, p& j+ q' j: Z5 E
加密前为:hwy123456
( z) t P4 X! k% [+ K3 q w+ @" H加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
. V6 {* k% k" I
& C* c9 Z. {2 ~6 e% }4 _+ C============================================$ M1 s! s+ M. I3 {% v2 K1 Y
上面是当时自己校内的心情。现在已经解破出来了,分享给大家' c( w9 @8 |- z+ _4 ~
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
% { S$ d9 N" j! s以下是RSA算法文件5 E& s" D( p( _4 U q% }
: f2 `& C4 q9 {. J& X
文件名RSA.ASP! P) e; r, O$ i$ E9 w2 L7 ~
===============================================
1 f- ?& j1 r2 q) F6 j% k<% % A: m, ^6 o) \/ W0 _/ n
Class clsRSA
2 B3 o* Z+ o% y: N6 Z. R# ?% ZPublic PrivateKey ( [0 Z4 z+ k7 D& _" u; u4 M$ n
Public PublicKey ( q- J! M, Y* R2 k7 }0 t
Public Modulus 0 |0 c: a! l/ a5 N; Y$ B i- J' f9 i' u
Public Function Crypt(pLngMessage, pLngKey)
( s7 l9 Y) j8 T9 [On Error Resume Next 9 [ y I! Z* k, N1 O6 ^
Dim lLngMod 0 {1 r+ e7 {* U5 m* W
Dim lLngResult
# f, f* h! G( \$ o4 qDim lLngIndex ) C6 H) Q: _& ^3 ~7 I) D* v4 v
If pLngKey Mod 2 = 0 Then , u& Q9 g" j, K) l; m. e
lLngResult = 1 - `+ z; S) b4 z& `
For lLngIndex = 1 To pLngKey / 2 8 A* N& w3 i3 i
lLngMod = (pLngMessage ^ 2) Mod Modulus 1 P) u+ O# B$ U" O+ }: S
' Mod may error on key generation
) D, `8 u, b+ llLngResult = (lLngMod * lLngResult) Mod Modulus 5 b$ V6 n# a4 D3 ?5 t A
If Err Then Exit Function
/ b( r' |5 j6 f; j$ sNext ! p0 b, C& b- Q0 r+ O: G1 z) z
Else 1 e+ z8 i* Z: A6 W
lLngResult = pLngMessage
O( i7 O! ]* _7 T$ S; i, f# UFor lLngIndex = 1 To pLngKey / 2 6 l6 e, H4 c4 l( s5 p& d' g" S
lLngMod = (pLngMessage ^ 2) Mod Modulus % c: T [) _- C' x) W1 ]9 I
On Error Resume Next
- D) |5 x- \5 E# ^' Mod may error on key generation
0 f% O N0 M I! GlLngResult = (lLngMod * lLngResult) Mod Modulus % v5 F1 A" v+ P) t+ Q
If Err Then Exit Function + h$ L! L8 Y: ~/ S
Next + X0 {. w" a3 r$ Z
End If
; A u; U) v$ l' [+ cCrypt = lLngResult J6 L9 @7 p3 ]/ y4 K8 ^
End Function( F* W2 Z5 q K' w4 d
$ e7 ?7 f; p7 ^8 H
Public Function Encode(ByVal pStrMessage)
. [6 `: f9 K( ^Dim lLngIndex ! s) }* n! ?/ n3 v
Dim lLngMaxIndex
6 g! i% p# J8 J0 p8 sDim lBytAscii 2 A. v& C2 A% B9 v+ H+ R/ `2 _; _
Dim lLngEncrypted
6 @& E D: A: VlLngMaxIndex = Len(pStrMessage)
- V+ u% A+ v, f$ `7 S: Q; X: cIf lLngMaxIndex = 0 Then Exit Function E/ M5 v' D2 F* X
For lLngIndex = 1 To lLngMaxIndex " v2 s9 ~/ T' d3 K( L
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
7 J7 k* i& W v7 o8 {4 Q: G% W0 HlLngEncrypted = Crypt(lBytAscii, PublicKey) 6 `$ A" A! f- t8 q- W5 L' p
Encode = Encode & NumberToHex(lLngEncrypted, 4) 3 [- ]) l/ P2 f, ^
Next
0 O6 \: O' `/ ]( h" ^# J% fEnd Function
7 a$ {! W* `6 M* Y4 j oPublic Function Decode(ByVal pStrMessage) 4 N; w; t3 b1 @3 F# j
Dim lBytAscii 9 e" ]4 P0 K( Y! x( @! M0 E
Dim lLngIndex ' W* d. {3 R, [3 |
Dim lLngMaxIndex 5 r# ]7 j. B p: Q
Dim lLngEncryptedData 8 c/ ~8 D& l; G! S: P" r
Decode = "" , w8 j5 ^$ `/ r1 ~$ O) H
lLngMaxIndex = Len(pStrMessage) ; r6 v2 I: ^/ Y& b
For lLngIndex = 1 To lLngMaxIndex Step 4 5 x$ q& n: M6 i4 n& R
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) . l2 M0 F( u6 s: y5 w
lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
* T& i( o; ^0 C: ?Decode = Decode & Chr(lBytAscii)
" p9 F# J, ~* ?1 [2 MNext
; F# W* O: o, x) z' o- v- ?End Function
. K* q% b% f- C- u: DPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 4 Q* p: S# h3 J- e
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) & f2 `# L, Z# i
End Function
2 N/ k- `/ D) X$ m. ~7 ePrivate Function HexToNumber(ByRef pStrHex)
! W2 g8 _/ g/ g+ H) j$ FHexToNumber = CLng("&h" & pStrHex) " Z# S0 m7 B- Z Y: ^1 s$ J1 i
End Function
$ t* u3 \. p9 T- o" N/ TEnd Class # ?6 e* I% D& U& U0 R
function Encryptstr(Message)
. H( h% Y' N/ \9 E5 |5 HDim LngKeyE % Y" F6 I+ B0 n
Dim LngKeyD
: |9 o$ e g: ?% M& S& j1 [Dim LngKeyN 1 x' f1 J) d! i8 p9 c1 G
Dim StrMessage
8 A7 L1 H4 f! X) h- b1 u3 CDim ObjRSA # P; L& H+ \& G1 L% T1 d$ U
LngKeyE = "32823" ! ]0 k' s+ W1 J( L: ]0 b' V% d
LngKeyD = "20643"
' E1 G1 {: F" m' Z, a* rLngKeyN = "29893"
4 x& B6 @2 @- v, [" fStrMessage = Message
; w9 Z6 n8 t' J7 g. G2 bSet ObjRSA = New clsRSA / [% R5 q! _1 ]0 _
ObjRSA.PublicKey = LngKeyE 3 i" v) N) v* N) s7 [7 L
ObjRSA.Modulus = LngKeyN
0 y" h+ I3 {) D/ @( g( A$ JEncryptstr = ObjRSA.Encode(StrMessage)
' H+ K( m* I: h1 d9 H1 q7 ~Set ObjRSA = Nothing # V. I3 T1 ^5 }9 z! i4 n
end function
. A$ K3 C& l6 M3 L9 w# @, \9 d$ ^; qFunction Decryptstr(Message) % Z7 @, t) M# I- v5 R, @$ K1 s
Dim LngKeyE 5 u# G" y5 u! }1 c! L; Q! ?0 \
Dim LngKeyD
; y( @& A: b8 }5 O5 wDim LngKeyN 6 u& s" b4 L; G) f- C: N9 _
Dim StrMessage
6 j( K7 I; N Z. [8 l2 A8 yDim ObjRSA * R3 {/ n3 o- q' ~
LngKeyE = "32823"
2 Y5 H W" K- d6 L" \' L: tLngKeyD = "20643"
$ z u. c& B2 W# l# H' p( r# _ XLngKeyN = "29893" 4 f; Y$ C" o/ F) G" ?
StrMessage = Message . T% E O4 _9 A& X2 z0 t$ @
Set ObjRSA = New clsRSA
/ N/ L: Z1 Y/ o2 R5 [4 hObjRSA.PrivateKey =LngKeyD $ e1 [0 n" _4 g9 S
ObjRSA.Modulus=LngKeyN ) v+ P) a# p* J' }' ~/ E
decryptstr=ObjRSA.Decode(StrMessage) % O$ ~" ~3 z4 c/ m; g
Set ObjRSA = Nothing
- [1 R" P0 q# nend function
- x& |8 c* z4 W" j$ s( w& E( |8 w%> O9 P' o z* W# n& G+ \
===============================================+ r( V, _6 \3 v
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还有一个用于测试这段代码的test.asp. l# q0 K, i4 s; v9 D) n( Q5 [
有兴趣的自己搭建个IIS测试下/ U' F. K L; P. _; b8 l" d
<!--#INCLUDE FILE="RSA.asp"-->
' E) u9 h2 g, c* Q8 T7 c& \<%
4 ?5 t( ]9 r ~2 ^! x1 Ufunction Encryptstr(Message) 2 W4 h ^ ~# f# C8 O( [/ C4 S
Dim LngKeyE
4 x& Z; K9 W+ ?) D% TDim LngKeyD
# l! M) J" @! v( E% [9 ]Dim LngKeyN
3 |, S/ y& q* W/ I5 X' T H0 lDim StrMessage / E2 H i( i8 h9 X- u ]
Dim ObjRSA
6 k$ T4 w/ ]& E; aLngKeyE = "32823"
% O. H; t: Z# p8 Q" lLngKeyD = "20643" ( D# @2 k M0 `3 D+ Z
LngKeyN = "29893"
9 i# Y. {/ S$ O9 b3 b0 U& X5 wStrMessage = Message 5 ^. F0 E$ v U* m0 z# X
Set ObjRSA = New clsRSA - a) V# T1 U- J3 D+ Q9 s- m. Q$ r
ObjRSA.PublicKey = LngKeyE
$ }# q9 o# u3 R" tObjRSA.Modulus = LngKeyN
6 Y8 O3 q. A+ p7 t! NEncryptstr = ObjRSA.Encode(StrMessage) " `" o; Q# R* u/ ?( C" J( }
Set ObjRSA = Nothing
- d8 e' h" } l& bend function
% u; {% N2 x& C( X( H& l9 G7 C. Y/ wfunction decryptstr(Message)
2 ^' O4 c" S" F) d9 }Dim LngKeyE ! ?) E1 k4 _4 o( T) z1 R
Dim LngKeyD 8 @: y4 z0 _4 `: V7 ]3 ^
Dim LngKeyN ; a! E! L' I2 s- E# o% H
Dim StrMessage 3 V$ M, w5 e+ _9 ?# {
Dim ObjRSA - p, V5 w& ]. n7 \5 x
LngKeyE = "32823"
+ P9 z4 c9 u, }* WLngKeyD = "20643"
1 c# o) e; @" gLngKeyN = "29893" p A' a/ I9 E1 u
StrMessage = Message 4 s4 z3 F. @: I0 h' J& l* D! U
Set ObjRSA = New clsRSA # T& D, ^9 {% I* `" e) w8 T5 H
ObjRSA.PrivateKey =LngKeyD 2 V3 x3 b" ]( u2 b0 u
ObjRSA.Modulus=LngKeyN
3 ^# _3 i$ y# v" t9 D" ?$ `/ Kdecryptstr=ObjRSA.Decode(StrMessage)
6 _6 t4 p" b3 p) _- x$ n: f7 b6 rSet ObjRSA = Nothing
; e8 \ N/ j; Wend function
7 F3 p$ _/ v3 Zdim last,first % A; n# D8 v1 Q x# Z
first="!@#$%^&*()"
4 n3 m3 G4 E7 NResponse.Write "加密前为:"&first 9 w, ^ R8 J& E- g8 l2 P) |4 w$ r
last=Encryptstr(first)
6 P1 p& J' T) {Response.Write "加密后为"&last ! b4 \( C" `6 [% B. ?/ N
Response.Write "解密后为" &decryptstr(last) 2 _' n% O1 ~4 e5 b" Q" ?# i1 C
%> ==============================================
U# m2 {+ f+ v1 U+ `剩下的就是字符的对照表了
; n4 ]7 W7 n& B1 ^2 ^8 `0 T===================字符集================
# i/ P6 S; S6 X8 C2 j) U: {% Z. b( t1_____6EBB0 y. }$ q3 R9 s9 l* b, a
2_____5C1F
/ @) Y2 ^/ X- T P% g3_____4D75
% n" v* }$ H7 E5 k4 c+ x! ]* z# ~+ Q4_____26CC
/ e* }/ @3 l& P2 T& [5_____4F88$ f& G4 [3 w( W9 v4 B
6_____3F4E
U7 J8 p4 w, r4 [, I7_____0A9D6 M/ z7 l8 n! m$ ~1 L6 ^
8_____1A1C2 C+ y8 N1 N4 O, y# ^- |( }
9_____6D206 y% M/ H) D5 O7 s
0_____1089% {( V! G- J) i8 ^
a_____0F3E
/ O7 g/ v8 T' [$ \b_____3159& n/ W4 x0 K: R. ]
c_____3517/ D! ^9 N+ g; V" T: ^( H
d_____419C
/ W. ~% V" P" ~e_____615C
7 I2 l2 c9 O' b9 ^( X6 rf_____556F
' r0 @$ F% G1 B& l* q2 G' p* ]" |g_____2B7F- }1 Z) V& t2 n7 `: z; v
h_____0F9C
( b, w$ j. W' ^5 Q+ Pi_____00FA5 Y' ^( q' `7 {( s2 {. R
j_____5A50
7 e: q: @' K/ R2 [$ w% X+ Vk_____2850
$ g O! ^; x4 R5 u( d- Q: T* F" pl_____3E7B7 d% y6 I: T8 ]/ h# X. ]
m_____71C5
2 L& m; m3 ~7 ?% Un_____1FC8 s7 Z* d/ P" i8 ]* r4 P7 f3 J$ q6 k
o_____74C1# }: D% ]- r. V4 \' _1 l
p_____5FB8
1 h- m6 U: q# ^( m dq_____6085* ?* }: D6 h9 M# C
r_____3AC4
3 O# c; [' H! f" i) \& ~s_____2F500 u0 ]3 b9 g( _+ k! g8 R: q" T
t_____36F8/ x$ A2 X4 k2 }0 f2 I- t3 n
u_____7010% i/ f3 L3 d' J' U
v_____0B42
& g7 `6 M5 a' {w_____1C7A+ `0 ~6 {6 W( B/ Z" O8 U, d6 \
x_____16F8
8 o/ z, a, M, \- k6 ~. xy_____2EE76 X0 l0 P, w0 d9 u" e" [
z_____5CF3
/ C7 o# X) V8 W N& f!_____6233
+ f( T" f1 ~. N8 s@_____3A45
6 H% j& q0 L+ j- z, c. Z3 V' l2 ]#_____22913 j) V* B# g T; e( X
$_____5D5C
# z7 w/ m/ ?, G- i7 f$ P- t%_____09B9
% p& k' K" b) p* ~" C^_____43EA1 _- c& u- n! L# I8 T3 ?1 Q
&_____62B98 I9 H3 A; i, p- p- i+ U; e
*_____6301
; q6 q a5 P! H2 A& W5 H(_____4659. J% s+ B v! s) L% F# N( J
)_____5C82 |
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