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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
" b* t, W! `6 t0 b& ^( D$ q原始出处:http://www.3ast.com.cm3 T2 p1 \3 e3 g
* g- @& q3 P4 u1 k( ^( F" n看不懂的直接绕过
4 k, \2 R% [8 H4 Y; R' ?( F加密前为:hwy1234567 {/ b/ F, h6 R W5 y( E
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
( M& N3 s$ P6 V- F. b0 ?
% F6 B. ~5 f. `( n) e1 A1 e6 P* I============================================
/ k7 U" \* {% ]* @上面是当时自己校内的心情。现在已经解破出来了,分享给大家
5 e. M, a. L. c也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法) ^; w4 e4 u t/ [& {
以下是RSA算法文件4 ?: V+ o6 t: q. Y$ `# S
# u$ E% [3 S& N, M7 R& ]/ A2 d文件名RSA.ASP' S' ^+ D- k" t8 M; B. X
===============================================- I$ g( e2 Y3 S0 x+ O1 i
<%
" t; C% e+ S6 e+ RClass clsRSA 0 O! D; j" J* [! ~ S+ I( d1 F
Public PrivateKey
5 b* U" r7 w9 Z H) @Public PublicKey
; k- c' t2 _) `Public Modulus
+ A. Y$ P! [9 i" C: R; c* i! ZPublic Function Crypt(pLngMessage, pLngKey)
, G, ]0 e- R- ?1 ^" vOn Error Resume Next
3 e! W" N0 I* Y" h' i4 k7 }; BDim lLngMod
. N& i ^! G# JDim lLngResult ! a% H. ]8 M# G9 g2 S" d
Dim lLngIndex " }& n( V) j3 R
If pLngKey Mod 2 = 0 Then ; M/ ]6 Y# L! h9 n6 W
lLngResult = 1
3 n, w' E% D8 a: ~+ wFor lLngIndex = 1 To pLngKey / 2
" N9 G5 ^3 G, _' R* }lLngMod = (pLngMessage ^ 2) Mod Modulus
# t8 j( K& s: c( T' Mod may error on key generation * M. ~. m5 o. V7 E
lLngResult = (lLngMod * lLngResult) Mod Modulus
5 b" p. Z3 c& ]5 F+ uIf Err Then Exit Function
! U) C- d( B% ]7 W! }Next . I T7 Z/ a5 p: Y7 v7 S; u& U
Else
3 O: C" |% H* w: G& B+ i# G" d% tlLngResult = pLngMessage
* m3 J2 W6 P3 q- S: y6 xFor lLngIndex = 1 To pLngKey / 2 # v# E. [5 o! P% H2 ~( H
lLngMod = (pLngMessage ^ 2) Mod Modulus
. ], W7 T! L i) `; }: U4 c' z& iOn Error Resume Next 5 k# j4 { i6 W2 H3 a# ~, I$ D
' Mod may error on key generation
( I E* W) b+ d# glLngResult = (lLngMod * lLngResult) Mod Modulus ) W9 C) Q8 {$ h9 Z1 x
If Err Then Exit Function $ N! n8 f. N! E# y
Next 8 a6 Y! j+ _7 G, ?' U; _* ~
End If ! l k/ d4 F! D Z/ I5 `
Crypt = lLngResult
& M' d6 _ X1 n8 rEnd Function
: p# w! L- s% c' t$ F6 ]* R
( |9 O( P) t# A" E* j' V# iPublic Function Encode(ByVal pStrMessage) ) X6 H; N$ e4 H) P( q
Dim lLngIndex
2 C. N `) i' eDim lLngMaxIndex
8 V# x4 D0 O* P5 q* i* ^Dim lBytAscii
3 ~) V- t: M3 \8 ZDim lLngEncrypted
! Y2 T) z( b, ?4 p6 G2 U3 DlLngMaxIndex = Len(pStrMessage) ' t2 X8 f- K" \9 k
If lLngMaxIndex = 0 Then Exit Function
0 ~- W5 V* `1 r/ @For lLngIndex = 1 To lLngMaxIndex
& x* r) T- _* @lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
8 g9 j7 \3 H4 SlLngEncrypted = Crypt(lBytAscii, PublicKey) 8 X6 L- n$ P* m
Encode = Encode & NumberToHex(lLngEncrypted, 4) , H4 A! v( J* Z6 y
Next
! F& o: z R; L7 _! S; J8 ~End Function
3 D1 }, i, z8 ?' q1 xPublic Function Decode(ByVal pStrMessage)
, X6 K3 Y/ V. B; _9 {- uDim lBytAscii
/ [- }% p. ^9 h# LDim lLngIndex % g4 F3 S- {. g$ _6 N: N' J9 |
Dim lLngMaxIndex
! O$ m* k5 g. t! r- [Dim lLngEncryptedData
% Y$ c+ t, F7 h6 h# E0 u: {Decode = "" & _( R0 I& O0 F4 w, X
lLngMaxIndex = Len(pStrMessage) 9 k; F3 N! {9 P, A m& Q, i
For lLngIndex = 1 To lLngMaxIndex Step 4 4 r1 c. ]; e# K: \# P
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
0 `2 A$ T8 F s2 A$ l. _& L: llBytAscii = Crypt(lLngEncryptedData, PrivateKey)
% i- d8 g/ X0 m! t" ?% |Decode = Decode & Chr(lBytAscii) 3 p/ `. y& ~- B8 H/ i
Next
5 k0 S& t2 n. K8 X' e2 WEnd Function
0 q! x4 x- R, ^+ \9 Y5 YPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
+ s# e, Z3 s/ B6 D; ^. g r* }NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) * M7 } P+ @) q/ _
End Function V" i( Y8 f' E) ?: ?
Private Function HexToNumber(ByRef pStrHex)
: x% W F$ r* G \$ z& x0 SHexToNumber = CLng("&h" & pStrHex)
8 v3 P! l0 u7 LEnd Function $ v* S; w; L+ Y$ X$ @9 }
End Class 9 a; i% U+ @* H0 P( a! r
function Encryptstr(Message) , n5 K+ R3 ~$ j3 T7 o5 ?, p4 y
Dim LngKeyE ; y) ^2 n5 H) S0 Z* U0 a
Dim LngKeyD ' I9 S# U( ?: U+ ]6 W8 Q* t, e
Dim LngKeyN 3 t5 r- `' [4 a9 A6 ~# s" C4 o
Dim StrMessage
" Y" X9 d h* h+ ~2 \0 a% UDim ObjRSA ; K. Q$ f# G& s3 I
LngKeyE = "32823" 7 c) W: `& b# F; |* h! a5 k* i
LngKeyD = "20643" : j$ a, L& N9 K7 s5 Z
LngKeyN = "29893"
/ Y* C/ o2 P5 [& p5 `StrMessage = Message ' j4 `' A7 _- \; Z# t# m, ^
Set ObjRSA = New clsRSA 3 y2 ~7 s9 I! H E, j) E. \! r
ObjRSA.PublicKey = LngKeyE # W0 O3 q4 I' t2 d, \- [3 y
ObjRSA.Modulus = LngKeyN
6 y& j" h! V/ }& |) J/ SEncryptstr = ObjRSA.Encode(StrMessage)
# p2 B4 X! h) C1 xSet ObjRSA = Nothing 7 V( H0 H7 y, d. y. d4 P1 V
end function" q* a. d9 v) S; T5 `
Function Decryptstr(Message) % W9 h& Z6 G Q6 X7 F& n- ^
Dim LngKeyE # k1 W, ~) Q# E. L5 |
Dim LngKeyD 1 F- }+ g+ t" E# {6 j0 ?' c
Dim LngKeyN 0 e9 @8 \0 R0 _: ^
Dim StrMessage
3 M+ V w1 R* P, }$ z( rDim ObjRSA
, |% T3 u8 _8 ^) t3 ~) ^LngKeyE = "32823" 3 ]7 q! i2 L* X# `
LngKeyD = "20643" 2 L+ f/ K' c/ @
LngKeyN = "29893" : U+ G0 o( s9 N+ Q* V- I7 `2 `
StrMessage = Message # v* `; t% D" T& {
Set ObjRSA = New clsRSA
2 c U. W, X" V5 I# B. b2 M/ m8 OObjRSA.PrivateKey =LngKeyD & j% b7 m: o. f$ ~1 N
ObjRSA.Modulus=LngKeyN
1 a) A) R3 O) E5 ndecryptstr=ObjRSA.Decode(StrMessage) ; u5 x( e0 ]: \* A: s) ~+ z! X
Set ObjRSA = Nothing
. k' T& M9 C6 ]1 ]( Pend function 2 w- l% z& c. N8 z8 D; Z
%>" o, D4 U; @ X/ j( A4 E4 {3 \- L
===============================================
5 l, S* B- R# q$ [
k' Y8 K. J: G8 i& z' a7 G还有一个用于测试这段代码的test.asp% M8 u1 F+ y& u4 @$ J+ x
有兴趣的自己搭建个IIS测试下
# c) v5 N, X- w# H# P<!--#INCLUDE FILE="RSA.asp"--> ( A+ _/ u: o |6 f
<%
" b3 j5 Y- J" `$ g- p' {0 tfunction Encryptstr(Message) - K/ D% g, C- J
Dim LngKeyE - }; a5 U- h! J6 N+ z1 t
Dim LngKeyD
% H5 e9 I$ e, d' l2 tDim LngKeyN
* w, X) G, ~& q# q! u/ aDim StrMessage 5 E) \6 x) v* P, Z
Dim ObjRSA
* {' x' h* C9 w8 {& N! F8 xLngKeyE = "32823" $ |* [" h3 j4 `
LngKeyD = "20643"
`) \ _9 k! @; w# A- KLngKeyN = "29893"
0 Y3 I; q2 `) F+ P4 J( G0 aStrMessage = Message
) Y/ Y, @5 P' u) ^8 xSet ObjRSA = New clsRSA
3 K& K, r. {* {0 y7 W8 J H6 UObjRSA.PublicKey = LngKeyE
6 }/ ^ k9 ^. iObjRSA.Modulus = LngKeyN
8 {+ U/ d+ Y; r! `- \2 NEncryptstr = ObjRSA.Encode(StrMessage) 2 L: Z4 g% a& s" r0 b; }4 N [
Set ObjRSA = Nothing
& ?! v, b3 z& N- lend function . c' F/ X T0 P3 ~3 f
function decryptstr(Message) * e# u2 u- X. C/ H
Dim LngKeyE % M- q- {: G1 ~1 n. x
Dim LngKeyD # \/ ], P U; O. z7 C% j) R, w- o+ z
Dim LngKeyN 7 O! V2 T0 v( R
Dim StrMessage * _- H0 U$ b A: u1 s; v
Dim ObjRSA 9 v2 j. d* b4 I) Z6 m
LngKeyE = "32823" 3 k# L1 E6 q7 l7 F* i1 d% {
LngKeyD = "20643" 6 t* ]0 m4 d' \- q
LngKeyN = "29893" # t5 U0 e' I# s; n; s. X
StrMessage = Message ' {1 D! d# k% E" T
Set ObjRSA = New clsRSA ! t' ~. y0 l4 N5 t
ObjRSA.PrivateKey =LngKeyD ( S0 [# j. g8 O6 q6 V
ObjRSA.Modulus=LngKeyN
3 t7 T" \% X- o2 w, o+ w9 C/ K; } wdecryptstr=ObjRSA.Decode(StrMessage) , C l, a( y" B; L: H
Set ObjRSA = Nothing : K7 m6 Y! Z5 q1 Y* H" R
end function
* a& X! q& U& @3 T0 o% [9 ?( {dim last,first
+ f) K' x# u0 O4 c$ ^first="!@#$%^&*()" % b; q( ~/ d8 r
Response.Write "加密前为:"&first " ?- i# n. e+ [/ l
last=Encryptstr(first) ! Y. g" ~! o4 A( H
Response.Write "加密后为"&last / @0 L! O8 W" I4 m+ ^( r
Response.Write "解密后为" &decryptstr(last)
7 @6 ?4 J& h4 Y7 i9 ?/ ~%> ==============================================' L7 ?0 p& m; D6 h
剩下的就是字符的对照表了5 v9 @" A% J7 F+ v# k
===================字符集================
( j7 b8 ~1 l. N$ ^" H+ E" k1_____6EBB
8 k( Z0 ]) _5 {) m% s2_____5C1F
/ L' `( Z1 d8 k8 g: q u. ?3_____4D75 }6 r5 {9 u: x L
4_____26CC. ^+ F- F8 z$ Q
5_____4F88
8 C' ~" G6 d4 o7 o1 h6_____3F4E/ L, f1 l) C! |+ ^" G8 ?: g9 C$ I8 d8 c
7_____0A9D
3 \% F( j& g8 r& d1 @! L8_____1A1C
; b) T( [3 `0 G& @$ o' N7 k9_____6D20
! U4 g5 G1 k4 S, x0_____1089
- H8 N3 @6 L4 sa_____0F3E
2 x V& R1 F! P8 T6 vb_____3159
( P6 X$ M1 c: v, O4 u: Uc_____3517
- F4 L- c. |; L8 P0 F f( K2 Ld_____419C
6 G) {( s C( c" h; Pe_____615C
/ w( Z# R5 ?6 w7 _0 }$ S, k: a/ V2 j; R5 Mf_____556F
+ s! F% }1 {! kg_____2B7F# y2 u) B2 W9 h4 j. o; }# F
h_____0F9C
9 N2 z! K/ G5 \/ m# g! Ri_____00FA7 \/ L- ]0 S& w" q. s5 d
j_____5A50
" W6 {" d9 s' c* d4 sk_____2850
+ z! Z4 f* d& S7 Y( O) Ml_____3E7B
+ `# f) v( }' Q2 Q) mm_____71C5
% |& }* n3 h9 J C% _n_____1FC8; j8 V0 U3 y1 G' i' c
o_____74C1
2 A M4 P0 \7 a5 ^9 x n6 g" sp_____5FB8
- ^' x0 l: c0 k& P" Z" @q_____6085& T' [, i: O5 Z3 k0 ~! Y
r_____3AC4
( n/ _- Y' ]* us_____2F50# G& e! u" _1 z1 }2 C4 @9 E
t_____36F85 \$ f1 K! \' b9 g# R6 Q& y9 O0 L
u_____7010
5 k! u, o7 a! j5 |2 |9 N; Z8 D7 Jv_____0B42
( H5 c1 a3 b* h1 f' L: P4 j* Gw_____1C7A
5 p+ u% M, F$ L1 G9 B! ^x_____16F81 f8 E8 p Z8 ^4 O2 ~5 E' ?
y_____2EE7
: A: K0 ~% l) q; M. t1 l# f$ |z_____5CF3
- B7 g$ s* f$ @2 A- [; a!_____6233$ s4 Y2 H: w# f+ `, k
@_____3A45
5 Z2 \% I) ?7 t7 u" o#_____2291/ Q2 ]: ~) a( l& T3 v
$_____5D5C' Z5 ?& n( ^+ H
%_____09B9
! V$ P1 c# w( \% O/ i% ?6 G/ [^_____43EA
$ h. F+ h) U/ S&_____62B9
1 I0 k" n. I; \! C5 S( d5 p0 N*_____63013 r! ^5 h" y7 _# ?5 K
(_____4659% o: S" K5 ?" q0 Q1 a) s: }) W2 A' J' e
)_____5C82 |
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