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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm+ c- ]8 D( z* d Z6 J! x" [) z0 F
原始出处:http://www.3ast.com.cm4 ]1 [# s1 Q8 L
U: T9 f- o2 K( h2 w* u
看不懂的直接绕过 v4 f5 K) S& p" F
加密前为:hwy123456
7 y( D {2 k4 S- A7 y2 _% C. ~加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E. v% F/ ~9 k* N4 P/ W: S
! Y/ k5 I# C( |3 V& M============================================
- x5 E3 W! t7 V上面是当时自己校内的心情。现在已经解破出来了,分享给大家
0 @7 M9 Q3 n# U4 Y也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
+ L! d3 f& q2 \$ Z以下是RSA算法文件# b: q' e4 `' a& v, J
' ~1 g9 Z( ]; E% Z文件名RSA.ASP9 l$ W7 g, |+ b( _3 D
===============================================* w/ P7 z# J+ y4 g& ]( T+ z
<%
7 R" \: t: z+ Z' I. [8 K* j( N2 kClass clsRSA
. R3 H5 L z% [- }3 i' fPublic PrivateKey
M/ n( P9 o( _9 f, ]Public PublicKey , [# |! h" I$ P4 ~! l, ^& L' d) v
Public Modulus
& U0 c. j$ O% G9 Y# L9 I! @. kPublic Function Crypt(pLngMessage, pLngKey)
2 S {, U8 z1 }- X' G7 c" Q0 M) e5 oOn Error Resume Next # B) l; Z" h8 R6 b, N: _
Dim lLngMod & D4 m! B0 O$ k; O( i4 K
Dim lLngResult ! ^& n% q: s) \+ c2 Z! _* F
Dim lLngIndex
! l' @9 a! h$ r' O9 i& v# BIf pLngKey Mod 2 = 0 Then $ G6 v _ J$ V8 m& u. L8 |
lLngResult = 1
. [ f0 O4 A; Q! b( eFor lLngIndex = 1 To pLngKey / 2 - i& M Q! w8 U& @8 _4 [" X
lLngMod = (pLngMessage ^ 2) Mod Modulus o4 m1 r, ~+ b
' Mod may error on key generation
8 S2 Q* n1 N; Y h1 ]# S: Q8 t/ AlLngResult = (lLngMod * lLngResult) Mod Modulus 3 q/ @' ~( p E- G1 ]
If Err Then Exit Function $ Y# E, q2 ?' _' c: y( P, C
Next
- l( h2 X: w8 M7 x8 ?) cElse % k/ B1 I; k7 [
lLngResult = pLngMessage
6 Z3 J( R) Z- W& X5 {. fFor lLngIndex = 1 To pLngKey / 2 * Q5 e, V; J* h; q
lLngMod = (pLngMessage ^ 2) Mod Modulus 8 c0 R5 |& i4 B8 d' R! P/ _
On Error Resume Next
2 p& K: m! {2 j. ~+ k+ S, A/ ~8 H% ]' Mod may error on key generation : u3 D# P4 {$ v" m/ Q0 }& C
lLngResult = (lLngMod * lLngResult) Mod Modulus 8 G$ N0 S+ y9 V+ t6 ?
If Err Then Exit Function 9 M3 K9 P2 D Q: H! W" H
Next 9 A( V. ~. h3 ^ p& w
End If
2 @$ A4 p/ `, {( ^Crypt = lLngResult
: |2 G v8 ]0 _End Function# U& j: m0 v% k" c' D& N1 ~
3 F& r7 \$ M; r( t* D
Public Function Encode(ByVal pStrMessage)
: e/ m: d. [; c, {: d# ~Dim lLngIndex ! j/ _ V3 L/ M5 h
Dim lLngMaxIndex * m* w5 Y3 \: b5 h9 H5 Q- e
Dim lBytAscii 4 i; U& N; U) ]) O
Dim lLngEncrypted 2 S, R: d3 N: T$ c; q
lLngMaxIndex = Len(pStrMessage)
6 T6 }6 ?' U: N* S$ `. W5 IIf lLngMaxIndex = 0 Then Exit Function
% A% T! w! J/ iFor lLngIndex = 1 To lLngMaxIndex # J u; F! p! z. c- c/ V
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) $ p! Z& [ I* A, Z* ?) a
lLngEncrypted = Crypt(lBytAscii, PublicKey)
a" ?$ A$ o- n! _Encode = Encode & NumberToHex(lLngEncrypted, 4)
" p3 \& D* ]/ I: ZNext 4 \8 c: G2 X1 s" b4 @ F+ a+ k
End Function
0 g; H1 q) }+ L: Y9 V4 ?0 VPublic Function Decode(ByVal pStrMessage)
: F x6 U& l8 m" ]Dim lBytAscii
8 n! {5 ~# E. F2 o) DDim lLngIndex
7 c" H& ~9 G, eDim lLngMaxIndex
: t# S% d! T! e& L/ W5 V- l6 hDim lLngEncryptedData 4 C J0 e6 Q% e3 N
Decode = ""
& P+ o a! `+ v% _& |( TlLngMaxIndex = Len(pStrMessage) 2 a0 a2 w4 g. _+ |4 Z( Q8 n/ a
For lLngIndex = 1 To lLngMaxIndex Step 4
" p* Y( T2 e" h+ JlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
1 j- p& R6 M2 P. Z3 f: plBytAscii = Crypt(lLngEncryptedData, PrivateKey) & J0 M- [; U& F$ i' R, D
Decode = Decode & Chr(lBytAscii) 1 V4 m" {, c+ A- h
Next
. j# Z8 o" B9 i. u Y& }! e- ?& { `End Function
+ ^# ?* ?0 q) x: P4 Q, }Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
& f7 E. a) ], d9 i2 T1 P8 |7 CNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
$ u8 S+ y( _+ l/ @End Function
# L. o8 X! V' f) x" d# RPrivate Function HexToNumber(ByRef pStrHex) / Y0 Z% l. ]- x/ ^+ K8 H9 ]) f
HexToNumber = CLng("&h" & pStrHex) , Q; U% `2 V+ m1 e- q
End Function ( R4 k0 L, ~1 D5 @
End Class
# O7 Q2 ?, {8 M! M) u; q& ]function Encryptstr(Message)
* I1 N7 K4 ~3 s1 Z! [Dim LngKeyE 6 _4 D) g8 c# m
Dim LngKeyD
% J0 l$ @. U" W; B% \6 r tDim LngKeyN : O- a A4 }" G* Y( p: f0 |; H4 I0 |
Dim StrMessage
2 q" M$ L5 _3 cDim ObjRSA
4 |8 f& a1 d' L7 S* b! CLngKeyE = "32823" # V3 _+ j! s$ Q; f
LngKeyD = "20643"
( z3 Y7 }& u' O3 K4 X9 K- x, T( @: MLngKeyN = "29893" ) x$ e6 e4 i; d& q, }" t7 k2 {
StrMessage = Message 6 S7 y8 k: K3 E/ b
Set ObjRSA = New clsRSA 1 G4 [( K1 C2 I; G* Z6 a
ObjRSA.PublicKey = LngKeyE
9 e6 D# ~ L4 O g$ q, XObjRSA.Modulus = LngKeyN
# E* I. J! p# ]* v) c* s2 a/ W* E% HEncryptstr = ObjRSA.Encode(StrMessage)
7 B1 N q$ v- J% E! bSet ObjRSA = Nothing
( h. M; p2 f( \0 e: v* Pend function* s; t; N n$ [2 D, L$ D
Function Decryptstr(Message) ; m4 P; v L O$ \! O5 m( o
Dim LngKeyE
: M4 j: C( g6 E4 L1 c# Y9 H- j4 kDim LngKeyD 8 Y# B) E. O/ E) \" R$ N+ L
Dim LngKeyN j( z6 G' k; Q& M! C( r8 `7 q7 H
Dim StrMessage
0 d8 s2 c9 n t2 i1 h: u& BDim ObjRSA
& a x7 w v5 m" D* l& `LngKeyE = "32823" ! [" V7 X# o6 Z2 V* x; R7 }
LngKeyD = "20643"
( p/ k, z- ~( L% V$ O% HLngKeyN = "29893"
) `4 n$ P& |% K8 C% dStrMessage = Message
: a( e! M/ m8 S/ p+ N: n/ }Set ObjRSA = New clsRSA Z4 _7 \- n; _3 q
ObjRSA.PrivateKey =LngKeyD
3 h- a7 }' c. rObjRSA.Modulus=LngKeyN
3 c( A/ i g, r( o2 ]decryptstr=ObjRSA.Decode(StrMessage) & ?7 k# K J9 H8 `% F, f3 T. V( g/ k
Set ObjRSA = Nothing
# x0 F1 J6 u* lend function
: i3 u" ^5 l# j8 o%>6 x; b! a* R1 y: H; ^ _
===============================================
8 @& u+ ]+ U4 T0 f% ]7 W! i: q# s6 J" K
还有一个用于测试这段代码的test.asp
' U# N/ B: O* N+ Y有兴趣的自己搭建个IIS测试下) b+ z) V: P8 F+ X1 u7 L5 t
<!--#INCLUDE FILE="RSA.asp"-->
5 _9 ^4 X V$ l0 s<%1 t: c/ f$ ^9 a! e
function Encryptstr(Message) ! v, l* ^" r: u0 Z$ W& B
Dim LngKeyE + F' b3 S) L, u. |% J" Y4 s
Dim LngKeyD 5 Y3 T4 O: H% d2 }
Dim LngKeyN
8 _ G1 M$ x; v7 w) E; M- v8 iDim StrMessage
- q" r% s7 N* lDim ObjRSA 2 @* C/ W8 G# z4 D. X9 r
LngKeyE = "32823"
t& z- G) g' R/ O" f1 ILngKeyD = "20643" - s6 Z% F. e$ x, X5 H
LngKeyN = "29893"
% Q/ p: |0 B8 q3 s- Q9 t0 xStrMessage = Message
" {4 g/ J* X6 X# F$ M: D0 n$ ISet ObjRSA = New clsRSA & f9 B% G/ a2 _- u9 r; C: Y
ObjRSA.PublicKey = LngKeyE " {# K& T( f% }) |* S- w
ObjRSA.Modulus = LngKeyN
7 O" B7 H3 g/ J" |$ J. Z9 C0 W- REncryptstr = ObjRSA.Encode(StrMessage) * B0 R8 S% f7 c6 d, G
Set ObjRSA = Nothing
8 B2 O' Z7 g+ ^9 X) J/ |8 p0 Kend function 5 W( t/ B+ m3 l% D
function decryptstr(Message)
' |& D6 o3 J. C0 aDim LngKeyE
$ N6 p1 \ h' O9 |& j& ZDim LngKeyD
3 v+ ]% i& V# bDim LngKeyN ( ?% [6 p& s; C0 F2 K+ y- { [
Dim StrMessage 9 @" u9 a& o, Z; l( s! y. s- a9 C: x
Dim ObjRSA ! f# L4 }, N" ~4 S. V, q! Y
LngKeyE = "32823"
7 s5 L8 {7 B1 v, E* _LngKeyD = "20643"
5 X' t9 }9 s6 MLngKeyN = "29893" ' d3 u/ t( c& u" M5 [
StrMessage = Message 3 X+ s% O7 @8 B
Set ObjRSA = New clsRSA & ~! F4 }2 Q# e( E
ObjRSA.PrivateKey =LngKeyD
9 @) n- f" o3 S- I5 C2 y+ f7 vObjRSA.Modulus=LngKeyN
2 f4 y( N# `4 G# s* edecryptstr=ObjRSA.Decode(StrMessage) 5 q+ s, U! C# m% o5 a Q7 t
Set ObjRSA = Nothing
. x! m8 L$ h! K+ N1 iend function
* y5 P; t2 ~: d H/ N' q/ [dim last,first
. q* C# M$ x4 g! @* R. gfirst="!@#$%^&*()" 6 m+ ~* b) H$ H+ {, F w
Response.Write "加密前为:"&first
7 P8 R/ h- _+ h: blast=Encryptstr(first)
1 a2 q0 T2 D( R7 _+ UResponse.Write "加密后为"&last # F: l6 J5 S* M I! F% M
Response.Write "解密后为" &decryptstr(last)
) \. b! L8 ?+ o+ o, F%> ==============================================
0 W) E0 k$ V! Q. G7 x/ ]/ i% F剩下的就是字符的对照表了
|; s$ Q1 h$ w* Q: M1 r3 q2 j9 j===================字符集================6 @* B% z5 o3 m e2 T% D
1_____6EBB! F6 x: K9 P9 S8 s$ ?
2_____5C1F
9 S3 ]# D' z3 j6 ~2 H3_____4D75
3 Z; W Q% f6 z, o v3 ]" `" ~4_____26CC P p4 U8 A" ~( \9 L+ ^2 k1 `
5_____4F88
$ x# ~% `4 w9 N. n$ A6_____3F4E3 M4 G! c; n0 G2 X
7_____0A9D/ n4 l: R* g4 b- K s4 j
8_____1A1C, r6 C* K/ l' g! X
9_____6D20
, s7 n/ G) g$ q; X- S0_____1089
1 ?/ ^+ E6 j8 K6 Ea_____0F3E8 G$ T0 N: y$ H, p G
b_____31595 T! F. \9 ^" Q }. g6 ?9 ]3 o# J. y. Q
c_____3517
' b; S# N( b8 _% H! Q K8 }d_____419C
+ u- `3 S% B, X6 e: He_____615C
1 @; o# G8 q" w p, g! nf_____556F
( f& z3 G/ H" T% X' l) Ag_____2B7F ]7 ~* m9 C1 C1 j8 D* w4 t
h_____0F9C) T! F! {4 e( V3 K
i_____00FA" p) J: b2 O: O
j_____5A50
1 Y( X) y: t9 Pk_____2850
1 r8 @1 Z7 D: `+ v4 Z3 }, Gl_____3E7B
4 K; P1 V2 U; w# K8 I) ]m_____71C5
3 U" w) P5 ]8 S! @/ u! kn_____1FC8! [0 e- O4 J$ Z
o_____74C1
* U" `" }( X, Dp_____5FB8
2 X; {9 }& f( F4 H1 C3 uq_____6085
! b/ H/ J% v D! N/ lr_____3AC4
0 l8 ]8 s) w4 G! U4 gs_____2F50
- ^! H7 b# P3 p+ m# |$ ] yt_____36F8
, I6 R6 P. `+ Nu_____7010
0 Y, e* ^ _( h+ Hv_____0B42# m q" h+ {4 V2 U- t
w_____1C7A W, E8 t& H9 E t$ t6 k
x_____16F8 g+ U* _* X* j
y_____2EE7
$ R! D3 k* C' {8 Z4 V1 P2 t7 O) ]. ?z_____5CF39 [% b, b4 m7 O
!_____62332 Z2 j0 ^/ A0 o
@_____3A455 S; K3 ?) B$ A) f4 p, r
#_____2291
+ |9 Y5 o" d, s0 `$_____5D5C
. d) M; i6 k: ^' o; a%_____09B9& j f" B* E5 o4 R) H
^_____43EA* d, t s$ V2 q1 `" D
&_____62B9
* B4 m/ w1 F4 t) J! f*_____63012 S- K/ D6 _ c f3 d2 y
(_____4659
/ p' w- Q3 m- a)_____5C82 |
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