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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm( n3 Q. \5 N, r( v6 J& u4 r
原始出处:http://www.3ast.com.cm! o4 b0 l# u. k# V* V; A
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看不懂的直接绕过
0 n/ U; ^' r* L n加密前为:hwy123456
t3 R; {6 y) B3 N4 ?9 w0 x, M加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E/ Q% I" w m q" d" u, R' a
+ R0 V2 ]( v: L9 g& W- E$ k$ _3 i; ]
============================================. v* A$ R8 Q4 W) T, x2 C- C
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
l6 r% p3 q( P* Q1 P2 |也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法* j# p- `' l+ D& ?. A- G# H
以下是RSA算法文件6 ^( C+ C) M8 S
& K+ p& Q8 G q
文件名RSA.ASP
' e4 ?* t# S' I2 y===============================================( H( H; Y) x$ K% v! t& ^/ h
<%
. Y, Y5 B' i* e f+ w5 L# u5 cClass clsRSA
; n8 z8 ?2 z, `3 x6 BPublic PrivateKey
1 O% @& A7 s$ B8 XPublic PublicKey 2 n5 U4 ?$ A+ E' q
Public Modulus . h/ k! u% R1 Y7 W
Public Function Crypt(pLngMessage, pLngKey)
0 K# ^+ Z w$ e$ COn Error Resume Next
* h3 p9 H5 u7 c( D. D, \Dim lLngMod
) K E/ H" ?' V- m: sDim lLngResult
! b% [, H% r+ X3 H+ L& KDim lLngIndex
/ ~: K, M* j2 w* @. D$ y4 H \If pLngKey Mod 2 = 0 Then
' E5 j6 m1 P: S Q6 W) s7 \lLngResult = 1 5 c0 \ w! Z+ @% F2 ]
For lLngIndex = 1 To pLngKey / 2 3 C4 k4 M* h5 [. c
lLngMod = (pLngMessage ^ 2) Mod Modulus
; G% Y9 F d; C/ d; j- X9 f/ i' Mod may error on key generation
/ v+ i% n0 u4 T# w' HlLngResult = (lLngMod * lLngResult) Mod Modulus ( E( s, i1 L' R( L' h8 U6 F. f
If Err Then Exit Function ' x; p0 |3 I0 t7 Q
Next
) ~* O4 [# ]7 E4 r- v+ L7 t9 iElse
% Z6 F7 d8 h; Z9 W) h- @' p0 clLngResult = pLngMessage * e2 l: Z! _6 h, x# g( l& [& a% {
For lLngIndex = 1 To pLngKey / 2 4 Y+ A. S* a, s) r: P
lLngMod = (pLngMessage ^ 2) Mod Modulus
- ~- u' w/ Y7 @) C/ _On Error Resume Next * O) y' @* ^$ U0 d0 X6 W" p- f
' Mod may error on key generation
7 H0 I8 V) J2 ^9 NlLngResult = (lLngMod * lLngResult) Mod Modulus
4 A: ~. C4 j9 r* t4 {: lIf Err Then Exit Function
' }$ |1 D; h/ K2 j5 KNext " {, _7 }3 P6 S& q( i; N
End If 5 _. V! o; m( l; j: z8 [& g6 W, v
Crypt = lLngResult
# X! f7 S# P6 V. r# k! tEnd Function
2 o* m/ U; D# C* o
7 Q* R2 u9 w0 u/ I- S. @Public Function Encode(ByVal pStrMessage) 1 V0 V; E, O7 v }2 x
Dim lLngIndex
* G: c8 ]% K P0 F/ z: N9 GDim lLngMaxIndex
, A( j# E; S/ r; o c- UDim lBytAscii ' F2 X/ [" ~3 C# w- m% X& c
Dim lLngEncrypted 6 z* k1 [! n+ B! a# M; t0 N6 ~
lLngMaxIndex = Len(pStrMessage) # |" T8 P, r- ]# n) c
If lLngMaxIndex = 0 Then Exit Function 2 S6 d- [" h- L# t" ~$ G
For lLngIndex = 1 To lLngMaxIndex - w' ^7 K5 V3 e3 J5 G
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
3 [1 r& N. D% C$ nlLngEncrypted = Crypt(lBytAscii, PublicKey)
2 G/ e# B5 I6 b3 sEncode = Encode & NumberToHex(lLngEncrypted, 4)
+ i3 c6 h7 W" Q) aNext
5 c) ~: \2 V9 V! Y ?; `End Function : w9 l" U: p" u
Public Function Decode(ByVal pStrMessage)
& N+ B" A5 Q, H8 M1 {Dim lBytAscii
( R" x- P6 i; k% iDim lLngIndex 0 [* Y! L' `4 z' U8 P; W: c
Dim lLngMaxIndex
8 l+ l/ B# c! D# G) LDim lLngEncryptedData * p$ j2 s2 ]1 q' w: [
Decode = ""
* \' |% V8 U) ]7 c( X1 f tlLngMaxIndex = Len(pStrMessage)
+ _: ~& i' `0 h) }$ IFor lLngIndex = 1 To lLngMaxIndex Step 4 , p7 }. i6 M/ X" h' d9 H
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
! e) X% A" j8 DlBytAscii = Crypt(lLngEncryptedData, PrivateKey)
4 g& t+ k* m, O5 M" c8 T0 S5 V W9 YDecode = Decode & Chr(lBytAscii)
% X8 Q+ \9 E0 Y, KNext
: F. n6 E0 a ZEnd Function 2 W* r2 G: j7 f8 x# W
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
5 M% C, Y0 Q! c, W' gNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) - N4 e- [& A0 \! k
End Function
/ Q3 `3 L$ p7 I) CPrivate Function HexToNumber(ByRef pStrHex) f$ S) k- @9 H
HexToNumber = CLng("&h" & pStrHex)
- O) k% Y" u$ z$ cEnd Function
, u" B- d, T7 }) n1 x/ KEnd Class ! D* A$ d. _9 f4 G: Q
function Encryptstr(Message)
5 Q7 M' v# [% H% [Dim LngKeyE ) l: [* V3 w- }, ?: r- D
Dim LngKeyD 9 m1 T2 A) V6 H: `- V9 O' b) Y
Dim LngKeyN
8 D7 q) _( }6 Y# v% d* U+ e( |7 B: T- bDim StrMessage 1 F5 X9 y, }( o3 b6 d
Dim ObjRSA
( C \3 Q# C4 a x. h2 U. o% [LngKeyE = "32823" 8 \- s# q2 ?) @1 x0 V! p
LngKeyD = "20643"
, A# J6 E8 e5 Q- Q4 @' RLngKeyN = "29893"
; X) w- i- i6 X# i; zStrMessage = Message
8 }6 y; b7 x" ?9 `Set ObjRSA = New clsRSA
5 y, h R0 z6 a' j" PObjRSA.PublicKey = LngKeyE 4 m+ U0 O( W$ T; h
ObjRSA.Modulus = LngKeyN
$ b8 y( k+ I7 ^! L5 b3 x7 TEncryptstr = ObjRSA.Encode(StrMessage) ; N( H4 c( v, c3 l7 J9 K* L/ W
Set ObjRSA = Nothing 0 p, B7 ~* X% q. J, t" P) J. E
end function
0 O8 x4 t" T3 |4 uFunction Decryptstr(Message) 6 Z$ K% T& W, Z9 E! ]! Y0 I4 O( v
Dim LngKeyE + K" g9 y, z; q+ {
Dim LngKeyD
& D! Z( p& [) nDim LngKeyN / ~. T1 j8 H5 _; B. j9 f
Dim StrMessage ' C( ~6 _2 g: d' y# s( Q
Dim ObjRSA
7 Z! s: f' {/ U8 f* w% c! T. fLngKeyE = "32823" 3 ]' }+ R O- G1 @- W3 ]$ W
LngKeyD = "20643" $ a1 Q6 @) @* T: U& f
LngKeyN = "29893"
5 P7 p: h& @* k2 }& yStrMessage = Message + ~7 b" p9 {+ X% W. |5 C. y" d
Set ObjRSA = New clsRSA 8 i9 f% R' _- ^7 l
ObjRSA.PrivateKey =LngKeyD
* w$ Z+ ?' i( f4 g! o5 Z- U, X8 pObjRSA.Modulus=LngKeyN
& T" c8 O9 y/ b) b/ g7 R! u/ o* jdecryptstr=ObjRSA.Decode(StrMessage)
4 l7 H5 O: w. |; V) Y& DSet ObjRSA = Nothing
( T( C- [$ l( J- [& m5 ~end function
3 j% I/ |! w4 Q8 `, F%>. r, p) ~8 [) C
===============================================. }7 B$ @7 H8 m3 s3 Y1 z
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还有一个用于测试这段代码的test.asp( J' Q/ Q5 b: G5 [
有兴趣的自己搭建个IIS测试下
% f8 z8 W# ~) I7 \<!--#INCLUDE FILE="RSA.asp"--> ( P& [9 N1 ?2 _. m
<%' I# N @# h3 P. P* S! \; d
function Encryptstr(Message) * u# z* u. D# s) _
Dim LngKeyE ; ~8 h3 m9 _9 O2 G5 e- D* g5 ~
Dim LngKeyD / f8 b8 r% u7 @ {
Dim LngKeyN ) Q( g+ ^: r5 G* a. z$ k+ E
Dim StrMessage
( ^: a! l0 v, a t eDim ObjRSA * ]/ t2 R. W$ o) l
LngKeyE = "32823"
, {5 o. V# P6 ~* yLngKeyD = "20643"
* b( w' b- @: q! WLngKeyN = "29893" 8 Q* y: Z. y6 P# u5 _& m+ J
StrMessage = Message
H; V& h* W/ mSet ObjRSA = New clsRSA 4 l: D. `' x/ M5 p- N2 w7 x; t' b
ObjRSA.PublicKey = LngKeyE
/ N( ?* ]8 M5 B: kObjRSA.Modulus = LngKeyN & ~; h7 I w3 W* q" M0 \
Encryptstr = ObjRSA.Encode(StrMessage)
1 D; P3 g/ B0 }# g1 ISet ObjRSA = Nothing # r# C2 b ~2 l" I# m, c. r
end function
, n. r+ R5 X- `+ T% x. X$ J* zfunction decryptstr(Message)
/ Z9 W0 O$ L; s! t5 s* ^Dim LngKeyE 1 \4 K, u; g: f. B: j: S1 q9 T
Dim LngKeyD / J7 \1 p y; X r2 u7 X
Dim LngKeyN $ m! i* O. b2 h/ V( T
Dim StrMessage
5 |) O" h' J9 m8 RDim ObjRSA
8 c, S1 ?0 P5 `5 M& T8 S, U4 ?LngKeyE = "32823"
2 R9 C' s1 n' a6 sLngKeyD = "20643"
: @: x7 z3 r4 m/ KLngKeyN = "29893"
! R: ^+ Z' Z. u# _% H2 B/ wStrMessage = Message : l+ T2 R0 p8 \: w$ q# b# g
Set ObjRSA = New clsRSA
7 d+ G" _: n1 v _% ?2 MObjRSA.PrivateKey =LngKeyD
! Z2 i; Z, A" n @& z: _ObjRSA.Modulus=LngKeyN
- k: M T+ r8 I( ]) @. m0 rdecryptstr=ObjRSA.Decode(StrMessage) . u$ h4 ~( z% b. x1 p: D2 ]. O1 T
Set ObjRSA = Nothing
3 I4 j5 G2 Y; H( w8 N0 x+ Rend function - \7 Z7 Q# q' ^* p3 _3 J! @
dim last,first
+ u3 j1 {6 P% f7 O7 Afirst="!@#$%^&*()" " W( b; L, q) [+ p
Response.Write "加密前为:"&first
+ e) p& u0 I% G% S. w; E# Elast=Encryptstr(first) ! _: U# O1 E! b
Response.Write "加密后为"&last 5 e2 O2 J; |- u0 ?: j8 }' Z+ O/ h
Response.Write "解密后为" &decryptstr(last)
+ t" q% V) y0 }, q%> ==============================================, f: i; t0 U |8 z" l! F7 k
剩下的就是字符的对照表了# N8 k4 T+ B6 Q# ], D
===================字符集================
4 @8 P- \% B) E. A1_____6EBB
* L5 h( `- t& h% F/ L* U2_____5C1F
* P6 J# L/ ~3 }) |3_____4D756 R* c( B% }; }7 i, O
4_____26CC
; e) M: W' t- j" A4 @5_____4F88
3 x v4 D+ a& j: H3 o- Q6_____3F4E
) E+ N' ^" G" y9 x; Y7_____0A9D
% D6 @- }& L$ G; c- E8_____1A1C# s+ ^; q8 M* y9 O7 m
9_____6D20 ]; L6 b7 W2 |( k
0_____1089
6 `6 S. D9 b# V% c% x0 b! Xa_____0F3E
# e7 }2 q, R5 a" N7 Rb_____3159
I! }3 O* Y) k1 `: Xc_____3517$ A: Q% i m: l
d_____419C
1 o: z& D2 R* T! C" h' e! Xe_____615C& N0 r @2 M0 P2 I
f_____556F
/ f4 ]) Z. D0 B9 K# f" |g_____2B7F, p% J3 H" `8 v+ p3 I1 w
h_____0F9C
4 n# g: N8 G* c- t% L: R7 t0 @' m8 T4 Bi_____00FA
- W) r3 ]+ v% i- K9 dj_____5A50
, d! B4 K& t- t2 T% e' ]k_____2850% Z9 \. ]$ v; M8 C' ~3 M/ g1 ?# _
l_____3E7B3 }/ ^% h0 @+ @
m_____71C5* b C" U& g! B* M/ q
n_____1FC8: c3 K2 J0 L* H% l# M; Z
o_____74C1
, R- ^; V: Y' s5 Z" s, O5 i3 bp_____5FB8
9 e4 m; t/ E8 E3 k) C! Vq_____6085
7 y0 [; l; ~" M5 M4 nr_____3AC4
2 G1 D; |: c) w6 ^' w% D' ts_____2F50: k. G) V+ v# U% w' R
t_____36F82 ?' t. M+ c: C1 D; {" I+ X
u_____7010
4 n$ t; n* g ^- c+ S6 ev_____0B42
' K# C9 Z5 W; R) c; [. h( A$ s. q! Ow_____1C7A
0 ~3 C! D0 L; H2 Ix_____16F8
2 Q6 u8 A% K5 Z" W( Hy_____2EE7
* @9 u2 t6 m9 C2 t: k# R' nz_____5CF33 A$ ~4 x' C7 ^
!_____62339 M/ j- g/ |4 s8 w: o
@_____3A45& I. E0 q8 |1 D! M. r
#_____22917 C7 k6 b' }) l. o
$_____5D5C
4 O# T0 N' A1 ^, w8 v e%_____09B9
! O8 d1 s" i/ m% A2 m' i- l^_____43EA$ k% M3 E+ x: x& R* { V9 t
&_____62B9- J% H1 ?2 A b2 G, z# _
*_____6301
6 F7 }6 m: ~- d U1 y(_____4659
: O5 l# u$ N2 U3 j)_____5C82 |
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