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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm. ]; d9 h, q% q6 T- w
原始出处:http://www.3ast.com.cm
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8 m8 B6 Y# Y% O. D6 o8 u看不懂的直接绕过) ?7 @8 b; }( c9 U; ~
加密前为:hwy123456) c* ~6 [4 D; O' d2 k7 G! M
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E6 m. s9 v2 Y( y$ Q- w
+ w) Z1 k% c. M
============================================
, m3 j8 [' T- v! H" P+ W# _上面是当时自己校内的心情。现在已经解破出来了,分享给大家, Z8 D- V3 s p9 R9 U" W+ L
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法+ r+ w+ a5 o2 R* V
以下是RSA算法文件
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* m& U5 e8 E% y' ~1 J) c7 j {. j文件名RSA.ASP
/ o! I" [0 }; Y5 b( D- e===============================================
8 X+ j9 i! F. Q$ P<% . w: M+ s* s; O% E2 S5 j d
Class clsRSA
- g3 n8 ^- ]9 S$ k# r6 a2 WPublic PrivateKey 0 `+ j: g/ b% b; h# B+ Y
Public PublicKey ! v: q$ [: w. A+ {, k
Public Modulus
: z: X4 S+ k. t# N* {! dPublic Function Crypt(pLngMessage, pLngKey)
# v. w4 a! t5 O' G* lOn Error Resume Next
E. @( q. n$ n. `Dim lLngMod
0 P* s' H$ a2 Q3 ]# ]$ VDim lLngResult
: S/ @7 Y" J- mDim lLngIndex 4 u# n' v* _- z* D2 v; ^
If pLngKey Mod 2 = 0 Then
5 L1 J0 M" a" o& f+ p+ KlLngResult = 1 : z1 L; y' C- s7 b' A
For lLngIndex = 1 To pLngKey / 2
m8 O( `# P# h7 L$ JlLngMod = (pLngMessage ^ 2) Mod Modulus
7 J& J* t1 `* {8 b: F' Mod may error on key generation . Y; s s, W( l/ P9 f. ?
lLngResult = (lLngMod * lLngResult) Mod Modulus
1 w+ H$ L4 ^ @! Y: U2 P- t* v5 UIf Err Then Exit Function
$ o9 s* T7 J- l, J5 t, XNext ; X% B! h1 ~3 l( p# o: q5 h, W
Else
# _) \8 Q: a% W$ `lLngResult = pLngMessage , X# x! X8 F5 K' m
For lLngIndex = 1 To pLngKey / 2
- a$ h4 a9 k: W& q7 G* klLngMod = (pLngMessage ^ 2) Mod Modulus 1 P8 i& Q8 n- k* Z" T# d8 |5 s8 H
On Error Resume Next 8 c! D$ e- r( y
' Mod may error on key generation
) j5 j& } c: Z$ Q( ^' |lLngResult = (lLngMod * lLngResult) Mod Modulus
& S' K1 f: s' j5 F; x1 J! ~# o0 lIf Err Then Exit Function * f8 I8 V: \0 U
Next 1 x' z: v8 c* ~8 ?, D- o( r
End If
" I! q" l2 Y' J0 g3 XCrypt = lLngResult
# L I! t% Y0 B5 E9 D* |" B9 u1 I# CEnd Function! N+ m u! E& p' c2 b3 y( F( s
% O/ ]2 A3 B6 Z* s5 B" nPublic Function Encode(ByVal pStrMessage) ' E4 t/ F9 b% i2 B5 n. G
Dim lLngIndex - e& W, J& y" q8 i
Dim lLngMaxIndex % L; E8 Z& B n& z: g/ \' k$ I# }7 B. U
Dim lBytAscii : K* f/ ]" k& J, A* j' k1 |' W
Dim lLngEncrypted & n8 b6 b2 `3 C$ ]% k
lLngMaxIndex = Len(pStrMessage) * r/ u% l- a4 w& }. L8 e' @' f
If lLngMaxIndex = 0 Then Exit Function # v: ~, ~, E: \# b. ]- o
For lLngIndex = 1 To lLngMaxIndex
" H o6 `% g0 C2 w |& n YlBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
W0 V$ I' k5 W' A" }0 R wlLngEncrypted = Crypt(lBytAscii, PublicKey)
1 ~" T8 O7 x! T2 pEncode = Encode & NumberToHex(lLngEncrypted, 4) 5 v9 J; {- D4 j0 H
Next
3 ^% i$ L5 U. L- n$ a# R5 rEnd Function
5 w& v! ~: d( n+ v0 [- ]0 h6 QPublic Function Decode(ByVal pStrMessage) - y' \& p3 D/ }1 V( Y/ B' F w
Dim lBytAscii : O. H$ h J2 ^
Dim lLngIndex
; g. j9 ?2 m, Z: j! H; L* |8 b, ZDim lLngMaxIndex % W& i# g; [* z7 t% D) R2 B1 g
Dim lLngEncryptedData
5 ]+ R8 T) a* T# Z4 cDecode = "" , F* g+ `! w6 X6 y
lLngMaxIndex = Len(pStrMessage) # O+ r4 P( B1 r2 I! I
For lLngIndex = 1 To lLngMaxIndex Step 4 ( v5 Z! f% @* [: [
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) % V0 M) y/ n( A9 `. N. I$ B
lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
& g' H8 ?! U* ^) v% \ C7 f. pDecode = Decode & Chr(lBytAscii)
9 E p" \, m: m2 kNext ; _: H2 U% E( d+ e6 N0 N
End Function ( u0 D( H- \/ v
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) ; W! K: z9 d8 j% o
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
4 l( R% _$ a8 b4 j+ r U6 E GEnd Function
" t3 h8 w' \1 t9 EPrivate Function HexToNumber(ByRef pStrHex) & M& L6 J5 @, J7 P @+ T1 a6 {8 b
HexToNumber = CLng("&h" & pStrHex) 3 {# G- O" A9 _: C" e, J
End Function : @* o. `) u/ Q$ q1 H4 T1 R, Y) d
End Class
" B( d- x# s# sfunction Encryptstr(Message)
0 v) x' c, K2 A3 {6 s/ Z% [6 hDim LngKeyE 5 i. D! j* U1 }
Dim LngKeyD
4 G2 q3 D, G) `. R: Y" s* L! a" WDim LngKeyN 5 E$ B) K, [, R7 z. y4 P% a
Dim StrMessage
) u7 q3 b9 ?4 Y8 bDim ObjRSA
5 R$ H4 Y7 G' U( i# Y$ R. WLngKeyE = "32823"
1 t, y1 u5 Q) f6 M1 {5 ALngKeyD = "20643"
8 \ G* @3 E" a1 O/ J) dLngKeyN = "29893" - H1 @# A/ d) \8 t
StrMessage = Message
% k; m" E& ^; M; d6 A% ?Set ObjRSA = New clsRSA & `6 n2 q# S- D& o" Y: Y, m# ?
ObjRSA.PublicKey = LngKeyE ) Y: f* C/ e( A+ A2 F! h
ObjRSA.Modulus = LngKeyN # F. _; g* }2 D7 Y% D j
Encryptstr = ObjRSA.Encode(StrMessage)
1 c4 B% T5 D2 o2 v9 |9 rSet ObjRSA = Nothing
0 E8 d! q$ s {' Q0 g. send function
. w7 _& a1 q: c$ YFunction Decryptstr(Message) 1 s1 n- }; o- I# @, k! b: F- }; }
Dim LngKeyE - I( n' ?% h# U6 N+ S
Dim LngKeyD # E* M3 e- z G. P) U8 j5 P. e+ y: i
Dim LngKeyN 0 z$ |( x4 m% N/ m% Z3 ~( K9 V
Dim StrMessage
5 N6 t& X; Z: e" H2 V( R2 xDim ObjRSA , k5 m8 P/ _1 }* }- N6 P" _
LngKeyE = "32823" 3 w4 R; F& q; [5 D9 A" a/ g
LngKeyD = "20643"
" r, |! G6 Q9 h3 Z: p5 |7 jLngKeyN = "29893"
6 O3 G5 `7 d, N, g3 X7 [9 {StrMessage = Message ; I8 q4 E( d k7 `5 M
Set ObjRSA = New clsRSA 3 e7 t$ h6 Z8 R+ H9 m( h
ObjRSA.PrivateKey =LngKeyD & V3 o; s. u, D4 I
ObjRSA.Modulus=LngKeyN
: d6 n" q L$ N) j& w" A/ mdecryptstr=ObjRSA.Decode(StrMessage) 2 [3 ` x y$ R+ @# f4 l8 s# k
Set ObjRSA = Nothing 6 V9 X9 x. v' P0 n% n
end function + x; `3 W U$ j: o6 |4 f, V; [
%>
* T+ F/ E( ^( D===============================================9 g+ Y) e2 p+ e3 H
4 P% ]' H( i8 S+ I0 [) ~2 Q) E2 \还有一个用于测试这段代码的test.asp7 N1 i0 A7 |5 [4 |) {5 O
有兴趣的自己搭建个IIS测试下+ A* A& W, ]2 d' f/ m" d2 r6 |2 x
<!--#INCLUDE FILE="RSA.asp"--> " \2 D1 _5 a# z% {5 Z
<%4 [/ t* K9 P0 X d$ S( @
function Encryptstr(Message) + T8 K9 S y& O- W1 M1 |" B
Dim LngKeyE
1 y2 u1 D" S$ E4 f0 Q A- \Dim LngKeyD ; P1 b4 h5 W+ S7 r" ?" x
Dim LngKeyN
. ^2 l; F+ y1 ]$ q! K$ lDim StrMessage 7 f0 X, O5 J! U% m! T' y% A2 s
Dim ObjRSA , u3 A* p8 r/ C- v; O, `
LngKeyE = "32823"
# k$ N3 o/ _; ^8 vLngKeyD = "20643"
4 [! t6 a# A9 A9 P0 u( a- ~LngKeyN = "29893"
+ `7 P7 _% j' W( Z1 @5 DStrMessage = Message
* [! k9 k5 a# a- R$ p/ Q) rSet ObjRSA = New clsRSA ) W5 r, d% X4 g' a m- D
ObjRSA.PublicKey = LngKeyE ; J/ O* F3 i" _+ W5 J
ObjRSA.Modulus = LngKeyN ' Z4 X R+ v3 S0 ?* w4 b4 d8 W
Encryptstr = ObjRSA.Encode(StrMessage) 4 Y' N/ P2 ?; z
Set ObjRSA = Nothing
+ U3 k" { |" |, O- f% cend function - ]% j8 o, x- ]" k
function decryptstr(Message) ( G3 H* e2 c* U( V2 L
Dim LngKeyE # _/ C* m Q R1 _, J9 ~0 ]
Dim LngKeyD % `8 t, i9 J4 f; i) h, C
Dim LngKeyN
! y' F0 n* W) o! ?& mDim StrMessage
3 v- D& ?7 a) k4 q2 \0 h n7 qDim ObjRSA ) q/ f) U% K: c
LngKeyE = "32823"
# {/ s. R ~& n8 i) H+ JLngKeyD = "20643" $ {8 N9 F8 t* S/ e
LngKeyN = "29893" / D, w7 {5 |$ u) u
StrMessage = Message 5 r" @ C# S& h1 B* y
Set ObjRSA = New clsRSA ; K1 T" `5 E5 k5 l4 P
ObjRSA.PrivateKey =LngKeyD : b+ T+ _# i1 a2 w1 V
ObjRSA.Modulus=LngKeyN 5 L. o8 \" s( `
decryptstr=ObjRSA.Decode(StrMessage)
1 ]* d' k- C: j/ A- L0 E" q! wSet ObjRSA = Nothing
) M2 h2 t5 m" S: z) Q# h+ Y3 u2 i5 D4 Gend function
W3 g7 {& [: Pdim last,first
- t& k! I7 y8 x0 hfirst="!@#$%^&*()"
. \0 O* S2 j% b9 E2 A# N eResponse.Write "加密前为:"&first 0 v% Z- J% R6 z) ~
last=Encryptstr(first) ) T* `/ u( a- S% c9 b( Q
Response.Write "加密后为"&last : F5 s( U: I. D' ~, p U$ d# w
Response.Write "解密后为" &decryptstr(last)
4 y* G+ n! F; N%> ==============================================9 B2 d% M1 V6 x
剩下的就是字符的对照表了
" `0 y* p$ e0 v' \ n2 q3 B===================字符集================
8 ~0 E' l M4 r. E- D1_____6EBB6 C. w$ _, f1 ? I) ]8 j
2_____5C1F/ P4 @8 X' h7 R
3_____4D75" c3 a5 E& k3 x4 c1 R5 e
4_____26CC
- ]. k( G& G) U" T! d- @5_____4F88% R; G( P: P/ _& L, V
6_____3F4E
3 u" i9 i4 \+ b% o: y7_____0A9D# K4 }; L& Q' X8 i& w% o/ U
8_____1A1C5 Y3 i# `% D8 y: k! s
9_____6D20: E4 w) X0 R' X# ?- Q4 q
0_____1089
& I4 i3 F$ L5 J- y% Da_____0F3E6 C, H) s2 V0 c- D0 O! ?, U/ B
b_____31591 E8 ]6 g& q. E8 M
c_____35177 h6 R q3 C6 r$ O' r, S
d_____419C
. H' ^$ [7 @1 e4 \' Je_____615C$ G/ @! G2 @$ k9 R$ g3 @$ ]
f_____556F
& C% u9 n8 s8 E# i0 M' i, n: [g_____2B7F
, n6 e+ N+ @9 F; fh_____0F9C, i- b, R! ^! j$ K5 Q
i_____00FA
: c4 p, _3 X+ R! @# ?3 Jj_____5A502 I; X B: \% @" U. p* k
k_____28508 z6 V: R! U \% L( {, r, X
l_____3E7B( ?0 a- f, R$ ?# G6 C- A
m_____71C5; n0 D: j1 ]3 s6 |4 X
n_____1FC8
7 j5 g" c# m* K* So_____74C10 g1 e0 K, e/ K( { [! F/ u
p_____5FB86 Q0 o1 n& [2 v( {9 d3 }
q_____60857 a& @" Y2 x; U$ F* n2 L: ~6 n
r_____3AC4) j4 S; w6 w% U8 f6 w6 q
s_____2F50! J" c) y! U! E \
t_____36F8
3 w( [4 w* S0 x5 V- K5 yu_____70103 M( x! I2 S, F" R8 p' |
v_____0B42
$ I) s3 e$ f' [+ } gw_____1C7A
$ e$ i- \( ]- x( S( B- o P$ h0 P% M9 rx_____16F8
! |. n' c+ J% y) o ey_____2EE7
# ]" C; K! H2 U' `z_____5CF3
3 N/ N! T8 W M+ ]!_____62335 m8 V: F$ j% k- I0 `
@_____3A45
+ k7 J" E0 S; I( ]$ z r#_____2291/ f9 @8 N3 o; a/ ? G( I9 y
$_____5D5C
" Y, h; N) E* K' Z( S* y8 A% S%_____09B9
: p. f' T+ w4 b: k+ |$ l ?& }^_____43EA
. e% c3 ^% k0 n5 A&_____62B9$ E5 p1 W; s; L0 @6 T5 F0 {2 H9 Y
*_____63017 L* T/ u6 U/ o m D* }' `
(_____4659& {$ P4 G5 ? b M. z
)_____5C82 |
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