|
    
- 帖子
- 3852
- 积分
- 13044
- 威望
- 16780
- 金钱
- 36761
- 在线时间
- 1139 小时
         
|
原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
1 _( y. v6 [2 l3 d G5 b9 i原始出处:http://www.3ast.com.cm
( X* s+ z9 K, Z7 ^5 i7 a6 _
% h" g) \6 J8 q7 D# w看不懂的直接绕过& E% ?; x3 \ }: x/ Z
加密前为:hwy123456
+ W5 y) s/ h6 L" O# k5 J7 ^8 v5 H; w5 D加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
: z6 b" Y+ J0 t& J- H! U4 ]! }7 k# Q# V% ?7 n# I. ^& Y
============================================
5 ~" V3 Q, M3 S$ q% S: @+ @' o上面是当时自己校内的心情。现在已经解破出来了,分享给大家& e2 [' s% U; {- J4 A: }; Y8 ^' r
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法* y" D0 }- e$ S1 E
以下是RSA算法文件" y n% r8 V* K3 _1 z6 V3 Q! h
2 X1 N) j; ?$ n- {文件名RSA.ASP7 h. A, O( _, @" X1 E
===============================================9 j/ w# ]! ]2 Y+ W- R: x3 {- x# I
<%
' [6 X5 t ?( [9 K5 m4 ^- I' SClass clsRSA
' q( g( m" | N3 Y, APublic PrivateKey
, _# G1 K7 |! n* A1 j# ?Public PublicKey # s3 d% X/ S7 t6 r# K8 @1 K8 E
Public Modulus ; ?9 |! s0 }/ |0 X9 e: w, a4 K
Public Function Crypt(pLngMessage, pLngKey)
" E0 g% K% r8 v1 y* [, v2 ROn Error Resume Next
$ G6 y+ u, q1 F( k4 E' j/ JDim lLngMod ( k% q1 S: v& P8 ^
Dim lLngResult 9 I' d' O# p. r/ U' o6 e, Z9 [. {
Dim lLngIndex 4 p- P' t4 a8 {5 R f& w4 S( D- M
If pLngKey Mod 2 = 0 Then
2 m3 C7 l; C W I+ H3 [lLngResult = 1
" i1 c3 C% m& v/ FFor lLngIndex = 1 To pLngKey / 2
; ~; V ?4 s. U1 T9 PlLngMod = (pLngMessage ^ 2) Mod Modulus
& X1 z: y( m) X+ ], U8 h# w' Mod may error on key generation ( ^$ o9 J: C C) s2 E, |# j
lLngResult = (lLngMod * lLngResult) Mod Modulus
& ~ Q- H, x/ m8 H7 S( _! tIf Err Then Exit Function
) k9 L5 F- @' f4 vNext ! x/ y Z3 H j
Else / Q2 B; Z! k0 U
lLngResult = pLngMessage
4 C+ y' m/ v3 J$ _8 XFor lLngIndex = 1 To pLngKey / 2 8 S8 e5 U) [, W, V* a- V: T# Z# g
lLngMod = (pLngMessage ^ 2) Mod Modulus
1 N3 N# z+ I3 I3 ^$ s0 XOn Error Resume Next
! D& {7 |8 T, B% N8 f, q5 l* d$ L' Mod may error on key generation 3 e" s5 B/ |& N1 i8 h
lLngResult = (lLngMod * lLngResult) Mod Modulus % W5 d& ]* V! O8 e7 _
If Err Then Exit Function 0 K6 b" z- G. @3 v
Next 0 ]/ v' ]8 w5 {/ F3 k
End If + \& M1 Q) Q4 h0 D, a x
Crypt = lLngResult ) c- Q+ e' x1 U* k2 Y% s
End Function
. `% s9 E1 W& S! y6 `3 G' W1 G8 u4 o% O: `5 d' u
Public Function Encode(ByVal pStrMessage) & n( X0 n5 p# }# R$ ~4 |2 x# z
Dim lLngIndex
( b. a) P# u& w" b$ |8 `% j8 [Dim lLngMaxIndex
2 ~8 y( V6 m0 J7 H/ H' w2 s- @4 n0 ^Dim lBytAscii
" V& X! ~) s+ F. C2 lDim lLngEncrypted
6 ]0 T+ a h3 q6 u& h$ Y0 DlLngMaxIndex = Len(pStrMessage) 4 k( G" I1 b1 O d
If lLngMaxIndex = 0 Then Exit Function
$ H6 Q7 W1 N1 G) q! R6 FFor lLngIndex = 1 To lLngMaxIndex
! D! ^' E9 V( S9 _ v2 OlBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
4 i: s! }% b& L8 ]$ h$ p' T: ulLngEncrypted = Crypt(lBytAscii, PublicKey)
* F# O" s9 J: n! l! bEncode = Encode & NumberToHex(lLngEncrypted, 4) # Q8 d2 C- n6 d" u8 L
Next 3 e: K, D4 N6 T7 H3 f
End Function , p9 A5 O* n" g
Public Function Decode(ByVal pStrMessage) % }9 Z* T9 h3 U, ] t9 p
Dim lBytAscii # q" V Q# l4 o' j+ T, k4 {
Dim lLngIndex
6 A! w/ K/ Y# i) ~Dim lLngMaxIndex # N7 w5 D2 N; f+ C2 {
Dim lLngEncryptedData * b" ~) t6 N3 ?# h$ ~) X F/ n
Decode = ""
' h! I6 e, V* V0 NlLngMaxIndex = Len(pStrMessage) $ }4 l* R5 f, w" r
For lLngIndex = 1 To lLngMaxIndex Step 4
! Q$ v h, j+ G1 S8 TlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
* ` `, n' a* Q* P }; A! plBytAscii = Crypt(lLngEncryptedData, PrivateKey)
0 O+ l/ U1 j. \8 h I4 |Decode = Decode & Chr(lBytAscii)
; H. a! H) _6 N6 nNext % K, h: Z6 ^: \, H
End Function $ y: A% u/ A2 `/ y3 H+ l. f
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
# x4 k9 L& `( U1 yNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
6 j2 _7 G9 P5 O5 E( J7 vEnd Function
* M4 J3 ~9 b" _) YPrivate Function HexToNumber(ByRef pStrHex)
/ d: u Y0 A- H! @% QHexToNumber = CLng("&h" & pStrHex) 0 @0 ~# y& ]; P9 D# T5 I
End Function
7 q- N z& Z& ?, r1 q9 x4 MEnd Class : |: e' w4 p! V1 k. A/ x
function Encryptstr(Message)
! @4 p; g. R- F% a- GDim LngKeyE % [/ n2 e; \+ `- o5 j
Dim LngKeyD - c+ ^4 Y/ s) P3 C1 {
Dim LngKeyN 1 B4 h$ L8 v. Z- U4 x
Dim StrMessage + e; q! E8 t+ h0 k* d& \ h* v
Dim ObjRSA 0 R8 c9 d, q; o7 a6 K
LngKeyE = "32823"
; ^) g, n B3 d1 N5 GLngKeyD = "20643"
, M B4 W5 _( [; I; F/ qLngKeyN = "29893" - | L, f8 F" t! e" u+ J' L
StrMessage = Message
& E4 d' t9 g2 y& [, FSet ObjRSA = New clsRSA
b& V1 F) i4 t- @) N! iObjRSA.PublicKey = LngKeyE * Z m$ q7 t2 A. f3 W1 T& w1 r1 o
ObjRSA.Modulus = LngKeyN
% X0 v/ m) [8 HEncryptstr = ObjRSA.Encode(StrMessage)
" C7 P" G) {2 p+ J6 ]5 mSet ObjRSA = Nothing
- C6 D* z2 ~6 N4 {/ U* {: D- q& Lend function l+ l! t8 D6 h# C6 s
Function Decryptstr(Message)
P; `8 @$ Q9 x! zDim LngKeyE 8 H! \, J, O3 e* |( E" }- V
Dim LngKeyD
- M D; N* ^7 V; n- ADim LngKeyN
0 {; B! W/ K" V/ m7 _- ]. }9 }/ BDim StrMessage
0 [# z* Z) Q/ cDim ObjRSA ; s* M3 f2 w# Y% i9 y5 L& g
LngKeyE = "32823"
% `% [5 Q8 |2 N+ BLngKeyD = "20643"
: b9 d( B) j$ B: dLngKeyN = "29893"
& D" b( P9 n( LStrMessage = Message `/ s4 [$ h! ?2 Q& e
Set ObjRSA = New clsRSA " j& f5 a8 ]- A0 ^8 N4 f+ `
ObjRSA.PrivateKey =LngKeyD
& ?2 s3 \6 H% b6 H% ~$ |ObjRSA.Modulus=LngKeyN 9 Q# M! q4 j! }: D
decryptstr=ObjRSA.Decode(StrMessage)
* E ]3 e y9 k7 o. J$ ]Set ObjRSA = Nothing * ~9 v) j/ V- v, X
end function
( D. l+ y% q( P2 o0 T5 D% z0 p%>+ b9 t% x2 V; t1 p) h( r4 g
===============================================
# _# y7 v% n2 [ K0 K! Q1 m% u k
还有一个用于测试这段代码的test.asp
" h( M) {8 X' y有兴趣的自己搭建个IIS测试下$ ?( i! s: m) X+ c; \$ b
<!--#INCLUDE FILE="RSA.asp"--> 3 L- e1 W* ]3 }( |" J) d
<%# ~9 C6 k: ^; c7 Q8 M; j
function Encryptstr(Message)
( h; G' G, g* X" f, p s6 eDim LngKeyE ! b# F( f6 g1 p h) C* ?" q1 L
Dim LngKeyD
4 G5 i4 ~. _4 k2 ]8 L& ]5 QDim LngKeyN
4 A5 T/ M/ g" e8 F6 h/ l wDim StrMessage
t B, s! d) @& D& I7 o( l1 @Dim ObjRSA + p, f8 [( G' A# n% C! b
LngKeyE = "32823" : ?1 i7 u; D+ Y: \) i
LngKeyD = "20643"
1 L, V+ h- k/ o7 QLngKeyN = "29893" : z# [ r! k9 L1 z& q( V
StrMessage = Message 3 U) K5 t4 |! A) X# @, v1 j
Set ObjRSA = New clsRSA
|8 Q9 S3 b! ^7 FObjRSA.PublicKey = LngKeyE
7 A! B! V5 F$ \4 V8 ^( F1 D# HObjRSA.Modulus = LngKeyN 5 K) I* V3 o; w6 E6 R
Encryptstr = ObjRSA.Encode(StrMessage)
; O% A( _6 @, `6 ~Set ObjRSA = Nothing
: n. C3 F0 u& t5 Yend function " ] v* ^) m3 I+ |; L# Y
function decryptstr(Message) / a( [. J: l- h) T" B
Dim LngKeyE " q- @4 p1 e+ H( V8 G
Dim LngKeyD ; f l, w, \8 U: A5 ]$ ~: b. s
Dim LngKeyN
7 N1 G0 q/ @6 x1 _1 sDim StrMessage $ N |0 Q( T {# l! k) a* A. |* {
Dim ObjRSA 6 R0 a# P4 c" q
LngKeyE = "32823" 7 @' k. x- @: f& x
LngKeyD = "20643"
% r! U( [- ]% W3 u, oLngKeyN = "29893"
" V- C% X L# @3 kStrMessage = Message ! l5 C4 X, s2 ?+ D3 A
Set ObjRSA = New clsRSA % V! x" H+ P e0 c) w
ObjRSA.PrivateKey =LngKeyD , J) }, }; v0 Z- l* r1 [
ObjRSA.Modulus=LngKeyN
, i; c: a6 @0 c, x8 W" M% m# \decryptstr=ObjRSA.Decode(StrMessage) $ b. u& g9 @- c* {/ |* U4 m5 v) o
Set ObjRSA = Nothing
( O/ n9 e* h; Lend function
! w, i* Z2 B# I: v7 m9 udim last,first
, k# q* |& {5 G& U ^6 J/ ~first="!@#$%^&*()"
# v7 w" g$ {$ A0 H- aResponse.Write "加密前为:"&first
# }% k& u' K, l4 R. {last=Encryptstr(first)
' ^ T9 J" Y: r, sResponse.Write "加密后为"&last
8 z( s( O) K+ {7 EResponse.Write "解密后为" &decryptstr(last) * u p4 C: g2 j" s
%> ==============================================
: P2 s7 o7 N* I剩下的就是字符的对照表了
0 Y' _% _* b: Y6 n===================字符集================* W8 I- X5 |9 A6 |/ w3 T" V
1_____6EBB
8 p' m/ d. J2 U+ d2_____5C1F
+ H% {' o- W* h2 ?* v) x, a- V3_____4D758 |& N: Z9 C( w+ _1 t( B
4_____26CC
# [; i, z8 \& s; N5_____4F884 y+ U/ k+ P7 [ H5 \+ B Z
6_____3F4E
5 p/ ^) m0 O# W6 L& H0 v! l y8 v7_____0A9D
! x$ a! W/ x; @6 q1 F& _7 t8_____1A1C5 |; e) g+ n; J
9_____6D20/ [/ }% n& B& b% `0 D# P* b8 o# N0 d
0_____1089" r$ s1 ?; [+ j8 U( E: o" r( C; G
a_____0F3E
; Z/ b- n" V$ C; ^+ i i5 ]b_____3159
6 a( C/ m& b; r2 _* l$ lc_____35175 h( n6 I6 ?: g. ^0 ]7 l
d_____419C3 v" b! Q. R- k2 }
e_____615C
0 f. G9 n2 F+ _f_____556F! F8 ~5 J* V8 A( |+ d# L- n9 R
g_____2B7F
' d% {" D3 {5 S' }; ~" O d- |h_____0F9C! z! s7 E4 M0 n1 p9 s' o1 g, d
i_____00FA
i, }6 @* e+ L V* ~j_____5A50
' {! Y g' c6 a% Y4 J2 }8 g: X# fk_____2850
! F' }2 n" J+ c- X1 S+ u) y( bl_____3E7B
2 K% K# z1 ^2 K/ {; P% xm_____71C5% e1 Q# l1 m- R
n_____1FC8! s% R {4 f( D
o_____74C1+ T. G9 b# F( \ ~% M5 T
p_____5FB8
$ Q2 `$ Z9 |8 D" l4 q( P3 @5 Gq_____6085
* h0 n9 b) u2 T8 e' ?0 Lr_____3AC4
2 f: }* k/ B9 d6 @- N' w7 j( P7 {4 Qs_____2F50! g! F( _, _7 z9 Y8 O4 y7 x) O
t_____36F8
# s: g* I3 C4 e3 J5 su_____70107 C) ` U3 ^2 y a, i' E5 ~8 k
v_____0B42
, I2 t) f; ?: ]* Lw_____1C7A# D( q" _# @& J; l$ ?$ J, T* p% I
x_____16F81 t( k8 T0 Y7 u' k
y_____2EE7# p/ N3 Z* k7 u
z_____5CF3, M p' ^ v; C7 R! u
!_____6233 F5 A% ^# S" N( E* [
@_____3A45* @3 N$ b7 a7 _$ ~0 V( i
#_____2291
- ~- j8 @; A" H$ y" b# w2 c$_____5D5C
: s. S0 A" A7 W2 a%_____09B9: O" @. x4 x. f/ x! M1 E) t3 @
^_____43EA* k0 [0 r+ P9 z
&_____62B9% {/ L! l8 @0 C1 q2 H7 B
*_____63015 x. z! ?1 }( A1 ^( T
(_____4659
# |3 ^) \* k8 E ]2 e/ e! B) r)_____5C82 |
|