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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm. V' p: ?/ Z1 p* g5 ]/ u8 u
原始出处:http://www.3ast.com.cm0 I$ ^$ x. ^1 J) i
- ]9 B @8 [6 ?# E- F: @看不懂的直接绕过" _$ X! ]2 M/ E1 J: l
加密前为:hwy123456
, c- A0 {. r3 H8 [- @# m$ N加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
4 T& y" R: {8 x" l0 n, q1 l6 e) i7 p3 _# H# u4 _8 t
============================================: r/ }4 n! z% G' ?% S/ K6 {( ]1 F6 \
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
; s! I9 B" { Z* N& {' B7 S也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法8 {' U* f/ G0 b# a& z
以下是RSA算法文件
- N6 h- H* G( \9 p( M* F6 L% d' X$ F( _# Y) y1 v
文件名RSA.ASP
) w$ A X: \ h) O" K4 d4 x4 n===============================================2 ~& s4 d' r& x8 |
<%
2 _+ L. d, h8 I: J6 |; w5 fClass clsRSA
. A* ?) J4 u+ V H) E' vPublic PrivateKey ( h: l) u2 i6 R, g, _
Public PublicKey % V/ z0 \/ E, ]3 o- M1 h
Public Modulus " s3 N; |! k% d2 U: L9 k
Public Function Crypt(pLngMessage, pLngKey)
+ I, ~6 ?8 D% P( C: R* F3 t( fOn Error Resume Next 0 s- n J1 D' u- b' Q' r9 ^
Dim lLngMod
) f( ~4 N& u/ H+ BDim lLngResult & ?" j2 K L3 n6 p" |) I* E/ o
Dim lLngIndex " {; t @& H3 X$ A/ N
If pLngKey Mod 2 = 0 Then . a; p2 t% ~1 I. N
lLngResult = 1 8 U, Z4 ~& X0 F5 y( V; n3 R. C
For lLngIndex = 1 To pLngKey / 2
& ?' w* ^/ p2 l$ W) alLngMod = (pLngMessage ^ 2) Mod Modulus - b+ C s: m& h) }3 {5 f% I. z
' Mod may error on key generation " a% _7 m2 x/ m- s
lLngResult = (lLngMod * lLngResult) Mod Modulus + ]: q+ k0 u$ `9 g; V
If Err Then Exit Function
" O2 m) A5 x$ U4 p+ k0 c" fNext 8 `2 B/ D& l) j# d5 P* U6 m
Else
7 e f# C. c) D; J8 j3 TlLngResult = pLngMessage
! f/ r, @' c& N8 s6 O o# cFor lLngIndex = 1 To pLngKey / 2
1 S! k/ P7 a; S+ RlLngMod = (pLngMessage ^ 2) Mod Modulus
T/ [$ Z0 K, C! ]0 ~0 EOn Error Resume Next
( ^6 e* y1 Y$ O' s8 {1 W5 I) J' Mod may error on key generation E7 ~" S, ?% ?: q9 t$ S' M2 i
lLngResult = (lLngMod * lLngResult) Mod Modulus 6 r$ {+ k7 y( M
If Err Then Exit Function
m* N* T$ Q7 j' c+ j5 `) x5 nNext ' _& k8 R( H( F& q
End If
5 G+ Q+ p0 W) ^! n8 l: VCrypt = lLngResult
! R6 Q* z. S# n9 V3 g8 @% M# HEnd Function
5 P2 b; Z: G4 |, z2 J% j9 Q X2 b2 \ W# ?$ Z% }6 Z$ j
Public Function Encode(ByVal pStrMessage)
9 ]; G8 d ^+ y. U7 z" ]; wDim lLngIndex $ Y- H9 K- Q8 F" E: ^ Y8 {
Dim lLngMaxIndex
4 |: z E, }" `- ]" W& S. yDim lBytAscii
' p1 ^8 V4 U4 Y5 GDim lLngEncrypted
; J& |. q; I+ D3 I, elLngMaxIndex = Len(pStrMessage) 6 Z/ G2 ], I0 I, o: S R, T
If lLngMaxIndex = 0 Then Exit Function : D) T$ ~) k# a; O
For lLngIndex = 1 To lLngMaxIndex ( x4 P- l/ K2 M8 `& [( |
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
! g* \- d1 }; t! s2 K9 h: klLngEncrypted = Crypt(lBytAscii, PublicKey) ) W4 d6 K" O. ]: {# o% j8 |4 @
Encode = Encode & NumberToHex(lLngEncrypted, 4) 1 y1 ]9 R5 b4 d8 D7 W, W. d' ]7 g
Next
- o5 {1 w2 A" P `- REnd Function
& N; r+ u4 u [8 H0 o3 gPublic Function Decode(ByVal pStrMessage)
E' V+ m% C* @Dim lBytAscii
% ~5 c- @4 X0 \7 M$ v4 xDim lLngIndex
0 Z0 P9 Q% U) K! e. Q8 d0 C8 xDim lLngMaxIndex
2 L" P* R, g) x- f/ b6 LDim lLngEncryptedData
% k% @) {2 x. TDecode = "" ' K& `1 B4 M: t4 D
lLngMaxIndex = Len(pStrMessage) + D- M7 Z) s& W7 d' h
For lLngIndex = 1 To lLngMaxIndex Step 4 ; E% m* f8 i: o0 o6 L; V2 B+ \/ B" {
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) ' G; t. r9 V; ^6 |* z
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) & p1 `: p3 B3 ^; h
Decode = Decode & Chr(lBytAscii) ! m ]- K) y. G0 w. }
Next 7 G1 O% t' k) G4 b
End Function * k. D+ C9 ~0 u' f( a4 q
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
; P, g6 ]$ }( b4 Z3 w& fNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
8 A1 v) ?+ z+ M8 l4 `" |End Function
& o% C/ f9 C0 XPrivate Function HexToNumber(ByRef pStrHex) 5 L9 R" I% N* B7 r
HexToNumber = CLng("&h" & pStrHex)
( b+ t$ B/ L! S C6 x WEnd Function
. u9 L. f4 t- I1 wEnd Class
8 m4 r |2 J% u! xfunction Encryptstr(Message) ( c9 b0 H4 C9 r. A
Dim LngKeyE
" w& @1 h, K# Y* I& y# h+ \Dim LngKeyD
2 b8 o! M& E- v+ P, pDim LngKeyN
: R) o5 K7 ~2 X! k3 ^0 X9 C, GDim StrMessage % T# A" a( {7 @0 K
Dim ObjRSA
- t8 e6 l* Q! T* mLngKeyE = "32823" / {( @% x( i7 Q9 V0 a! p6 m- U
LngKeyD = "20643"
0 |) Y* W+ v1 {5 ]8 ~& KLngKeyN = "29893" + q8 ^2 y1 M% ], N2 C
StrMessage = Message % G4 r$ Q2 r9 Y, I
Set ObjRSA = New clsRSA
' ^; i7 f- P& \/ N/ UObjRSA.PublicKey = LngKeyE ! H6 X& Y- x8 p* @% b8 u, ^3 }
ObjRSA.Modulus = LngKeyN
7 p+ P) @, N. `# U! F; ]% IEncryptstr = ObjRSA.Encode(StrMessage)
2 k; O$ g* e6 v; U" z0 ?Set ObjRSA = Nothing ; a. e, N. t+ {% l$ \/ U* P6 m
end function
: o' W" ?% u, E; m- v- @' q5 DFunction Decryptstr(Message)
, N5 I4 A8 G! s) I- n IDim LngKeyE
: X- p4 ^8 G3 S" ~- F4 lDim LngKeyD 7 p A* k$ J; D+ `. U% F
Dim LngKeyN
2 q( z% Z0 g' }1 qDim StrMessage 3 O/ {2 j6 `& ^! o' j! L- M
Dim ObjRSA , Y5 g' c" q3 F6 J; } W
LngKeyE = "32823" . C0 U+ x9 T- k1 C: i
LngKeyD = "20643"
$ _- w" V+ s& u' \! ]LngKeyN = "29893" ) F8 b# T" L8 p' W& Y0 U7 }
StrMessage = Message * L/ R1 A- p8 g; | I# w6 S! o
Set ObjRSA = New clsRSA . {. S" F) q c9 Z! l9 W1 y7 a
ObjRSA.PrivateKey =LngKeyD & b- Y" A5 p9 u( S$ P' g
ObjRSA.Modulus=LngKeyN
, O7 q% @) R5 Z7 F0 E4 pdecryptstr=ObjRSA.Decode(StrMessage) . M0 Y3 q D9 E1 B
Set ObjRSA = Nothing 9 B: u7 z" q9 E$ h; a- V
end function 6 @" _# Q: M8 {7 z" A1 d% ]
%>3 S4 w* ~3 c7 c; M
===============================================
5 y) p8 Q2 u: M- d2 j) z h
/ {) Y G2 c& ?1 G6 Q1 b( }还有一个用于测试这段代码的test.asp% Y/ S; c: t, W9 s
有兴趣的自己搭建个IIS测试下
2 c3 m k' c7 `7 p' B<!--#INCLUDE FILE="RSA.asp"-->
+ M" h% e/ i2 {' s<%
6 O0 p$ g0 v5 x8 E. e; K6 U6 ]function Encryptstr(Message)
% K1 M: r* |" ~# TDim LngKeyE + z% f& b* H# O& B4 h
Dim LngKeyD
/ T( ^: o4 u7 D3 Y9 h2 H1 [Dim LngKeyN 2 }; R8 o4 }$ [' m
Dim StrMessage 2 Z& _+ L& V* H8 [9 x$ i, g/ u' w
Dim ObjRSA
( U5 H6 v: [7 t) F* }LngKeyE = "32823"
9 [2 D& X% @) S, _LngKeyD = "20643"
5 H6 W+ O b! xLngKeyN = "29893" 2 v& y9 R: I; P- E' Q
StrMessage = Message
8 |8 j& x) _. p6 ZSet ObjRSA = New clsRSA
5 M8 S* `# C8 F5 K, [& Y( e- yObjRSA.PublicKey = LngKeyE
( v \3 K& l3 j" sObjRSA.Modulus = LngKeyN
" G2 ?' k+ L% ^) Y% tEncryptstr = ObjRSA.Encode(StrMessage) : @: @. W( v6 A" ? p% c/ \
Set ObjRSA = Nothing
6 K% s9 l- ^) t9 z* T+ V( W9 n# Uend function
6 Z/ D6 }6 T: K$ S8 _8 u0 u' Ffunction decryptstr(Message) " Y- y, z9 u2 J0 u0 a3 G& Q
Dim LngKeyE
; N' I+ ?% ^- R5 r8 ]Dim LngKeyD
7 k8 E2 e7 `& z3 F T3 gDim LngKeyN
, i+ E" Z6 I6 iDim StrMessage
; V; z' g L5 K" {" G- H7 LDim ObjRSA
. t' N: n! {/ L! G q; x" ZLngKeyE = "32823" + l$ b8 W0 k* k
LngKeyD = "20643" % y W Y9 }" q. C6 G
LngKeyN = "29893"
# l& ?2 L# k' I' FStrMessage = Message
$ S4 Z3 {& d/ j- N" m& Z! K5 bSet ObjRSA = New clsRSA ' w, p6 ^# Y* G/ E: m7 Z
ObjRSA.PrivateKey =LngKeyD 4 z6 A$ F, u; \ \7 a
ObjRSA.Modulus=LngKeyN
: \. I6 `5 ]! \% \# {9 z8 f& zdecryptstr=ObjRSA.Decode(StrMessage) $ r3 W; ~6 Y3 S2 f. `
Set ObjRSA = Nothing
, q( @) }8 M1 b7 \* |end function ' m$ g. ]) i5 N8 u# B. J& ]
dim last,first 8 m7 }5 h M+ t% b2 q
first="!@#$%^&*()"
2 g$ ^9 _7 b. |Response.Write "加密前为:"&first
5 Q: p& S4 o- L1 U6 N, ]( Klast=Encryptstr(first)
8 h6 m! h' ~2 v; [8 CResponse.Write "加密后为"&last ! z$ o; ]2 \3 o; E: k+ [
Response.Write "解密后为" &decryptstr(last)
6 K% {6 i) Z l ^* ^%> ==============================================: d4 p1 C. v! e' Y6 Q/ u2 g# ?
剩下的就是字符的对照表了, b' T* }+ ?- a) f9 q5 ~$ j
===================字符集================) u6 @4 K+ ~2 q7 I! Z
1_____6EBB$ E; M- H7 y3 o. @9 p( u0 s3 {4 b
2_____5C1F# h3 K# z! Q1 [7 v
3_____4D75
7 P( W4 u& O: e4_____26CC
6 Z9 V( q/ W8 a. y$ `, f: B. s/ K: _5_____4F88
; T: H: k# o1 X" P+ P3 |3 q/ s1 T6_____3F4E
3 z; r) e4 u* f( h0 C1 [7_____0A9D
E& e! `/ {! N. \" C5 p8_____1A1C
. m1 H7 @- w: t' ^4 \! N6 z( ?9_____6D20" H, Z8 W; R: p2 k
0_____1089
+ ^3 @& P9 y. N- m, {' ja_____0F3E) I1 z- q6 \+ L/ {% I3 w
b_____3159
/ g& j2 E& g$ P) d- m9 N1 a8 t$ }c_____3517$ P6 t" u/ a/ a! T- \5 e) j$ ]2 ~# L
d_____419C: `7 Q6 @4 C* x" F |) f$ L
e_____615C
& R1 z1 e1 W6 l& cf_____556F
3 A* s- B, q4 bg_____2B7F
. R+ h- z3 j: Y. M5 D6 gh_____0F9C
" \+ J, D: G+ [i_____00FA3 F/ Q7 W/ y% o0 Z$ n* h9 H
j_____5A501 K; }$ t% m% m7 [
k_____2850
5 r+ o# x4 V2 I8 d+ Bl_____3E7B
& P# S! e: }: s: s; B0 Vm_____71C5
8 W9 z2 | a0 O, Ln_____1FC85 U h/ F; ?9 b2 h& W) G" c, D
o_____74C1( F4 L5 |$ C* `$ K
p_____5FB8
5 a0 F+ B! |! I. o) T" {% Q/ Y$ N8 x8 Eq_____60857 y5 p- C+ Q/ _/ K- b
r_____3AC4# J6 m) o9 t \: ~
s_____2F50
4 ^( j; d4 i, G5 Q9 R+ tt_____36F83 I+ b3 k6 e8 }7 L
u_____7010
) }' `' U) |, l6 B r D" [/ ]v_____0B42
2 @/ r3 b* I3 Y& L3 E- tw_____1C7A
% n. ~9 L! D6 a: dx_____16F8 E3 O$ V6 `4 y' H0 ^" [
y_____2EE7
2 I8 F, R6 i! Z. _/ az_____5CF3
, u2 D; y% U! w!_____6233$ X- r9 K7 m8 B8 J$ i4 V
@_____3A45
/ b9 G/ t! _! Q/ Y- \% n1 }#_____22915 N' [- l) w7 A v2 V
$_____5D5C' W* }3 P1 O' J% j3 J0 Y
%_____09B98 a c x" J; R0 D4 j8 l( B1 ^- V r
^_____43EA
/ \5 L( E/ X* u' e&_____62B9* R' p1 o9 ^% v! ? ~, m
*_____6301( _3 U( m# w/ G9 Z; ~8 ~( }* Q
(_____4659
# W, [3 U1 V8 R3 i) y1 W& G)_____5C82 |
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