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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm0 H2 T" A Y" _# ~
原始出处:http://www.3ast.com.cm- P: K2 j5 o2 A# ~; H2 R
) n: l) m8 J% e5 s看不懂的直接绕过
4 L% g5 x0 T; E6 s/ _加密前为:hwy123456" x1 e5 U6 C8 Q: [; [7 K
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
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1 M2 H! e' H& O1 A8 j============================================- U" F9 W+ N6 E f7 @
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
" r& l4 o9 k: b; H0 v6 @也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
* L# H! d* r% |0 A+ \0 j以下是RSA算法文件7 o8 ~# i3 g" \( r. O
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文件名RSA.ASP
: r8 [5 \, N) O: \" p8 J# L===============================================
" f- l' w4 _( q2 t+ h0 d k* R' q<%
; x O: I" Z1 v, l E9 mClass clsRSA
7 A% Y# c" \6 n: g0 dPublic PrivateKey : K$ N2 ]5 T/ j+ f* C# u
Public PublicKey 7 N0 z- x9 J( b r6 I
Public Modulus
0 r t7 l) G/ e' J2 k9 qPublic Function Crypt(pLngMessage, pLngKey)
' A1 V6 B; n( ~# W0 {On Error Resume Next y+ ]2 p X! w4 {" G8 Z0 [
Dim lLngMod * Z3 N4 f2 [% Y, F
Dim lLngResult
2 T2 @) N& I, u$ o( P8 y K: EDim lLngIndex 3 b! Y/ {; m; `. Z6 O$ s: B
If pLngKey Mod 2 = 0 Then ! d5 `! F# Q; W2 D# P& v9 I+ g5 x
lLngResult = 1
1 g; [) j% F8 R, ~* F0 L9 z/ K! qFor lLngIndex = 1 To pLngKey / 2 8 Z' h9 s6 ^& w; D0 b
lLngMod = (pLngMessage ^ 2) Mod Modulus
: L5 W# p! h6 {# i. C, {+ n, K$ `' Mod may error on key generation
: @; o% d# w l6 L, G& AlLngResult = (lLngMod * lLngResult) Mod Modulus ; m, B" b F% ^* S" N
If Err Then Exit Function
3 } ]) b7 p% [4 l' y" g) NNext
1 w9 L+ J! m$ D. n2 m/ k7 aElse
$ V5 t% U3 z% E1 i( x0 n9 \. e. |lLngResult = pLngMessage * s9 g& @2 \% h8 x
For lLngIndex = 1 To pLngKey / 2 # W- ?$ C9 z, u; Y$ ]
lLngMod = (pLngMessage ^ 2) Mod Modulus
0 `2 G! M$ A# z d! \On Error Resume Next 8 V M; A: `8 c: t. _
' Mod may error on key generation + t! n2 s0 y8 B- o8 Z4 g
lLngResult = (lLngMod * lLngResult) Mod Modulus
' p: d* i! P1 d1 IIf Err Then Exit Function
# C$ P! b* |; X7 `% H; JNext
. {2 O* _; u2 O2 M0 Q( [End If # L$ U3 o# U& W. y. I/ S
Crypt = lLngResult
( o9 ~- W$ n" bEnd Function$ S0 r0 y9 t; R. Q4 m- E) W$ h
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Public Function Encode(ByVal pStrMessage)
9 b0 h: ?5 {" t* SDim lLngIndex ) k$ T. @4 k3 p+ _& S
Dim lLngMaxIndex - K) C+ b8 p# s- n3 s& ~
Dim lBytAscii
3 z1 t4 w* S8 @- B7 KDim lLngEncrypted
5 j1 l8 H8 K E1 olLngMaxIndex = Len(pStrMessage) % ?, [! M& r2 F( k. o- z! [- _
If lLngMaxIndex = 0 Then Exit Function ' C! c4 m+ ~7 {" J: S6 f, r
For lLngIndex = 1 To lLngMaxIndex
( V6 I& ^; R1 |1 wlBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) + F1 K2 J, [% d2 m; e
lLngEncrypted = Crypt(lBytAscii, PublicKey) ' c: h$ p4 W4 l0 U
Encode = Encode & NumberToHex(lLngEncrypted, 4) ( @9 T% T% N+ a2 Z6 R
Next 4 p) T- z* [$ @- r0 u- g3 l0 p
End Function
" i: o6 I* o# pPublic Function Decode(ByVal pStrMessage)
5 P {) n/ }6 Q# y6 X( v8 T* VDim lBytAscii
8 \( W, z% V. ]5 d3 c. t6 RDim lLngIndex
' \: ?/ f1 \+ o7 |( Y( Y5 j( H8 NDim lLngMaxIndex
" E4 \( p9 g% N- uDim lLngEncryptedData
" Z8 o, I4 C9 h% r3 w. aDecode = ""
9 o9 [8 T* u# O$ e& g( z. V/ Z3 ulLngMaxIndex = Len(pStrMessage)
$ {& W7 [+ m# O4 @$ q5 t) XFor lLngIndex = 1 To lLngMaxIndex Step 4
+ z5 h4 q& W4 K) X3 G0 u0 TlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
7 L4 O% s9 R6 `; hlBytAscii = Crypt(lLngEncryptedData, PrivateKey) : h% Q; `- a( m+ x: H
Decode = Decode & Chr(lBytAscii)
% |& M$ L7 m6 yNext
' F5 }3 N, ] R FEnd Function % m! C* Z- P$ \. y4 M
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 1 H: U4 c* D9 ?6 q' \
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) 7 Q- R9 T x* M
End Function
3 x: d/ ^9 O0 B5 V. U9 y# }- w7 YPrivate Function HexToNumber(ByRef pStrHex) 0 v7 T; G: O t" o
HexToNumber = CLng("&h" & pStrHex) : S# N, c) F& c5 t4 j3 X/ |
End Function 8 V9 Y8 _7 f% y2 N' z- N' x$ l
End Class * E2 k, y" R: q
function Encryptstr(Message)
6 r8 M3 x% l2 j* JDim LngKeyE - z3 P/ Y' t7 J: `2 J& A5 g
Dim LngKeyD
2 _( C6 w$ l9 h/ nDim LngKeyN 6 ^, t/ x+ i8 O
Dim StrMessage
- m0 i. c! x: Y9 S0 r, d; eDim ObjRSA
9 c' w, G. }7 O% [1 {) u4 eLngKeyE = "32823"
9 y8 y5 b7 J& C, d+ RLngKeyD = "20643" . R5 m9 Z. O4 `2 d
LngKeyN = "29893"
8 R" G. u, s! \6 i" tStrMessage = Message
$ n; E! `" W4 Q8 J& S" vSet ObjRSA = New clsRSA
" F5 }: ^( n! `% k1 OObjRSA.PublicKey = LngKeyE
0 Y- K |( v3 h1 rObjRSA.Modulus = LngKeyN
" y6 h* X$ r) b1 ~" }Encryptstr = ObjRSA.Encode(StrMessage) $ w& B# R( ?* Q7 a' D2 v
Set ObjRSA = Nothing 1 \# p/ I4 S' \
end function
' l: t6 B, y: Y- K G/ R8 SFunction Decryptstr(Message) 1 x+ L) y) _" O8 B
Dim LngKeyE 5 Y/ _, r/ S5 S
Dim LngKeyD
5 I4 q5 g5 i' b0 D3 f! eDim LngKeyN
# o, ?! g5 P" T/ H) yDim StrMessage
) }8 L, o6 L$ J9 ?Dim ObjRSA - d7 }0 Y1 n3 P" [( F' g, e3 {1 `
LngKeyE = "32823" - H9 Y) V, ]1 S
LngKeyD = "20643"
5 V& i, M8 t% i# `: r- nLngKeyN = "29893"
7 ~! M$ H+ g# D" A! X7 s9 _- \StrMessage = Message 0 Y, Z: R+ r6 Y- b3 I1 H2 y! Z+ M& o
Set ObjRSA = New clsRSA
9 z+ z- u" @1 i' kObjRSA.PrivateKey =LngKeyD
& |' ~3 T; r9 d" OObjRSA.Modulus=LngKeyN
' ^# F: Y' @6 v6 cdecryptstr=ObjRSA.Decode(StrMessage) 4 V2 ]; Y6 x6 U6 z! W- @7 l: i
Set ObjRSA = Nothing ; D0 f9 R; ?! ?/ W" J8 W
end function 0 e- u# Q" E5 m) v4 b- Y
%>8 E4 E. @. o8 S2 S; k" m
===============================================" t7 {6 C* ~8 z7 K
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还有一个用于测试这段代码的test.asp: N9 Z0 G" v7 X: n3 M
有兴趣的自己搭建个IIS测试下
! E$ d& n. _- `7 L) R" l8 S; |$ n! B<!--#INCLUDE FILE="RSA.asp"-->
! Q- U ?% r/ V1 e3 M' u<%
' n5 m6 D c" r" ^: {function Encryptstr(Message) . h( g C9 j( s7 i* ~. M3 T% e& C
Dim LngKeyE
& O- a& u+ ^' T0 |1 ADim LngKeyD # F/ }, r% L' o! t4 |( i
Dim LngKeyN
/ {3 [* }9 ]8 J. FDim StrMessage
+ V! Y1 @6 C9 C# t6 ADim ObjRSA + L; N$ H% p$ ~, k! Z1 u* z# m/ }
LngKeyE = "32823" 7 N1 J9 C, S5 H f( a
LngKeyD = "20643" ( J9 W# d/ G' J. n7 t% @
LngKeyN = "29893"
' X3 S- s7 w( `3 V) O. yStrMessage = Message 3 L8 d% t% J H2 ~# ?
Set ObjRSA = New clsRSA 0 v# b7 D# x1 w) J3 ]
ObjRSA.PublicKey = LngKeyE ! w$ w* B- X2 ?+ Z1 a3 @0 K, W) D) [" y
ObjRSA.Modulus = LngKeyN
/ G! d6 [1 k# }/ a0 JEncryptstr = ObjRSA.Encode(StrMessage) * l8 N/ d( F1 g# C+ R# @9 g! S
Set ObjRSA = Nothing F9 G+ J" B0 }# `" t2 R
end function $ `( t$ p B0 j- \
function decryptstr(Message) [( r+ u+ f" M. L
Dim LngKeyE
7 P3 V" p- m+ v" \) g: b% B+ ~Dim LngKeyD
t R1 O$ A- P1 x3 b) J0 X( FDim LngKeyN 7 ~, m2 A7 v6 T$ g |) {
Dim StrMessage
8 b; T& d' R$ c9 y) f$ K: S- ~5 @Dim ObjRSA
% [+ y3 L. Y' T8 i7 WLngKeyE = "32823"
* x$ I: }( U4 O, h* Q- |+ BLngKeyD = "20643"
5 _- F/ Y- `( _$ W- u# O% U7 rLngKeyN = "29893"
- ? N, y% o& r; ~: a A: y2 e' MStrMessage = Message
7 w4 Q) i0 I0 |3 ISet ObjRSA = New clsRSA 1 Y0 X/ X! g3 W4 ~# N1 o
ObjRSA.PrivateKey =LngKeyD
# s" K7 e: y5 vObjRSA.Modulus=LngKeyN
8 S/ r4 D. U* Q ~decryptstr=ObjRSA.Decode(StrMessage)
* Y8 p* M) O) M7 ^Set ObjRSA = Nothing 2 Y1 J: }5 U1 g* r4 x
end function " {4 h5 c8 b2 V+ J; m; p' Y! Y
dim last,first 0 G0 k/ j G4 W" [- W0 C! _+ s
first="!@#$%^&*()"
5 X7 t9 R2 a% U6 EResponse.Write "加密前为:"&first % x4 j9 I0 v4 D( y0 a
last=Encryptstr(first)
8 o3 Y0 a; H9 c) bResponse.Write "加密后为"&last
; L, \3 r# `, Z5 \* YResponse.Write "解密后为" &decryptstr(last)
3 L$ Y# x, V/ Q/ @+ }%> ==============================================3 }6 ~" G+ C/ g
剩下的就是字符的对照表了5 w, S' C+ {# {; `) S( | j. r
===================字符集================; E/ K6 f+ s9 T5 X
1_____6EBB0 @( P3 h9 R- Q5 \/ |0 o# Y1 x, e
2_____5C1F
& v8 `7 T5 F# W4 ]3_____4D75
, u- m+ G1 ~& b, A/ q4_____26CC
1 T: u+ k( w4 h$ H) e5 p4 c( H& R9 f5_____4F88% p' f, r' `" N; I9 c& y
6_____3F4E
4 v5 o% z/ Y( L# z- \- Q7_____0A9D. k1 U- }6 S' ~6 P
8_____1A1C E$ I" }: `; Y0 N, h9 H! R
9_____6D20
2 I$ P4 O% t g7 v0_____1089- M m# s7 W+ Y+ x* w9 Z; \
a_____0F3E
$ e1 w6 j7 K: j% h, X# Q, ob_____3159
5 q: Y# \- c+ U5 T$ o" b+ V" Oc_____3517$ L' q& L2 D% |3 s- P
d_____419C5 e; b$ \+ a2 _; V
e_____615C8 T4 {; z' w) q: C6 w/ ~ d1 ]0 E
f_____556F
' i1 B6 Q2 ^# Q% ~9 ~" ^5 ^/ S- O: Sg_____2B7F4 U: q. p# Y- _3 c& x" r
h_____0F9C
. x$ M, U; \# s' w. ^i_____00FA
3 ]/ k, f8 m, r7 D" Q: Jj_____5A50
. O, t0 v( R( |5 c& G% ik_____2850; P2 M+ [, a0 h$ B+ Y+ t" Q
l_____3E7B& `& h& y+ \- ?3 a% v
m_____71C5
5 p8 B- ~: u& ] y# v% ]n_____1FC87 Q8 J x# a2 C! @4 t. N
o_____74C1' w8 b8 A- \0 A7 X* C% h
p_____5FB81 D$ t e" h3 y, M, Z$ K
q_____6085
% n" E; `2 R V7 K2 Sr_____3AC4# q z4 H+ r9 |+ |8 b- J
s_____2F50
( `7 J" I- s' xt_____36F8
6 \9 b* I4 f0 G7 Zu_____7010
, W- t* @. [% b- |. _v_____0B424 ?2 q7 ~1 @+ L* l3 R# `+ F
w_____1C7A
- b) m* U' ~4 Dx_____16F8
& I9 L. P6 U+ ry_____2EE7
1 x) G% T: m- Q7 vz_____5CF3
2 ?/ U$ L+ N9 c" D/ a1 r!_____6233! T3 H& \" U% e7 q. e# y
@_____3A45. P8 M6 T L' `$ ~2 y) a. V. G( B
#_____2291
% D+ l ^! M5 G$_____5D5C
6 ?4 k3 K- p" t0 r%_____09B96 p: N2 O$ ]0 t$ l
^_____43EA
' u7 M! m9 o n5 H* x&_____62B9; l7 q& {; Y, O! m5 x: Z
*_____6301
* f# \" `$ j7 i+ }(_____4659
( D2 E7 f; M7 V3 V8 l$ T)_____5C82 |
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