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原创作者：柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
- p2 B& j3 U6 w3 ?原始出处：http://www.3ast.com.cm+ J; t L, o' X$ H p
% U# R. n$ D+ X# U2 ]/ j看不懂的直接绕过
/ y6 w1 e2 b; m加密前为:hwy123456
F! ?) o8 L+ W! f; S" B加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
; B' N6 \; F8 D6 x. ]; i
- {: i4 p1 O5 B# E9 {' P" F============================================
% U4 J( }! p2 m上面是当时自己校内的心情。现在已经解破出来了，分享给大家
+ ^, B6 G, O$ T. G0 [. F也就不隐瞒大家什么了，这个是国内某知名大学的后台加密算法( Q' f K0 ]0 u% a2 Q
以下是RSA算法文件1 z* t3 b8 v8 g/ V
$ b# _$ B! s! B+ g' x3 F1 Y' u文件名RSA.ASP
S% N' W! t9 m( u9 ` p- j===============================================
_, ^ h" a6 P0 N8 b( K<% 3 J' U; F4 Y8 k* b: p9 ^+ } \
Class clsRSA 0 H+ A8 T. b& }- g+ K0 ]* b
Public PrivateKey
# [. n# w' u K7 x" V. _( G! gPublic PublicKey Z! \" z' Q+ t" N% f: q
Public Modulus 6 Y8 d. g( j2 E+ C6 p9 b; e
Public Function Crypt(pLngMessage, pLngKey) 3 x: c5 }2 X7 u$ E
On Error Resume Next
' U# |" P2 i/ R% W9 j D# ]! S1 s0 kDim lLngMod
5 T" i3 A5 T) a- c! s$ \Dim lLngResult
- n: \- X9 U) U6 u( q3 k, B, R4 d RDim lLngIndex " v" b, K2 b R% R# E
If pLngKey Mod 2 = 0 Then
- x( z# z6 N; i+ {+ b5 t" r2 ~lLngResult = 1
; J u" g/ i" @% N( E; h1 @For lLngIndex = 1 To pLngKey / 2 ! R9 m9 n' h8 D: R& G1 j! {5 t% E
lLngMod = (pLngMessage ^ 2) Mod Modulus
, ~" J/ F3 e8 w1 Q8 J6 P* K9 T' Mod may error on key generation 6 X. n6 W; q6 ^
lLngResult = (lLngMod * lLngResult) Mod Modulus
( h" v. l& x7 U' V# _; e' }9 W2 S; \If Err Then Exit Function
5 W: m% n5 b- A8 a mNext
- ?5 _, y& U% t: J! vElse 7 ]2 S% X+ U5 ]% [: y
lLngResult = pLngMessage 2 v5 R. N5 z. Q& t4 i
For lLngIndex = 1 To pLngKey / 2 0 @9 D0 A% V1 z# e. M, V9 S
lLngMod = (pLngMessage ^ 2) Mod Modulus 0 e2 a% Q0 ]; F# d" ?
On Error Resume Next
C8 H; g+ _3 n- R! R6 [# C ?' Mod may error on key generation
4 L* r1 t5 t ^0 zlLngResult = (lLngMod * lLngResult) Mod Modulus * T& n0 P) o% G) l9 H
If Err Then Exit Function
w1 s; |( h/ }7 TNext M, A5 D' ^9 [& l5 Z8 }
End If 4 [" ]4 \% V& B, e# X+ k- g
Crypt = lLngResult 6 o9 V3 p# r: H/ S+ S4 b2 n
End Function
4 V. h N; w9 k9 N
. p2 s, Y" l B- o' EPublic Function Encode(ByVal pStrMessage) & ~: y, Y2 R, v) @* P/ C6 o! i
Dim lLngIndex 2 ~& }- ?3 R* g; @4 p7 _
Dim lLngMaxIndex 4 B% y, O$ E) D+ d1 K/ [
Dim lBytAscii
, s- U, a2 ]* u* w" m& L! j0 w2 ^Dim lLngEncrypted
/ {) E$ Y7 L% h, M- O9 b! t D2 H5 flLngMaxIndex = Len(pStrMessage)
; v! ?1 Q1 R0 n7 f, \9 m% n1 oIf lLngMaxIndex = 0 Then Exit Function ' U3 ]4 d# k! f: w0 N. A3 c4 B/ l
For lLngIndex = 1 To lLngMaxIndex 0 {3 | k; T' J5 Q$ H
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
, C, K5 k: d3 TlLngEncrypted = Crypt(lBytAscii, PublicKey)
) A$ ~* z' o0 J* Q, \Encode = Encode & NumberToHex(lLngEncrypted, 4)
, j' P7 c/ ?' d5 P3 }# DNext
) s6 {* b7 L* `- Q/ QEnd Function 9 ?: J% C1 ?5 D
Public Function Decode(ByVal pStrMessage) & p; O' e! M& v$ H0 V. h0 C
Dim lBytAscii
( K# W1 f( D3 b- \) F) }+ vDim lLngIndex
$ z6 V9 S+ g! QDim lLngMaxIndex 5 y4 r# R. E* L7 c N
Dim lLngEncryptedData - z% O( |- j5 ^9 n
Decode = "" ! O$ V) l! m; l0 m; z) y, X
lLngMaxIndex = Len(pStrMessage) ; {# i$ @5 ]3 [) G
For lLngIndex = 1 To lLngMaxIndex Step 4
5 \. [* }% x; J ]8 |lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) + M; M) G% W9 O( T
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) ' w; ?+ L# m' z4 ?+ E2 N6 H- I/ f/ X1 m
Decode = Decode & Chr(lBytAscii) # _1 C3 |8 u4 C: ?* |- s7 c& c
Next 0 W+ y r9 b: H/ p: h
End Function
: r! \- A5 z5 _5 Z3 D& J9 [: qPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
6 Y* z0 d6 X4 O$ D5 lNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
0 H; b3 |, t V/ R$ eEnd Function % n# V# a( p) }- q" _. K
Private Function HexToNumber(ByRef pStrHex) % K4 X- V$ K7 _. @& R; e# m) l
HexToNumber = CLng("&h" & pStrHex) 1 k0 T- _7 D7 V5 C+ @! Z8 o6 x
End Function N2 k- B# u. F6 p: ^/ x3 ~/ d
End Class " O# e" j D$ K
function Encryptstr(Message)
. i( F& s8 X* H7 B: X9 ? Y8 k7 DDim LngKeyE
4 X) t; W$ b1 D) d2 x0 K2 VDim LngKeyD 1 S+ d" u' N5 x; f
Dim LngKeyN
9 d$ a$ j1 K( n! zDim StrMessage
d% j" f3 c. l7 N L* I5 s/ gDim ObjRSA
. o8 s/ g# H* d0 U2 p) o8 OLngKeyE = "32823" 1 T' i" K3 } _. f5 d! t+ u
LngKeyD = "20643" 6 e: @! P! x/ E/ l, f. [
LngKeyN = "29893" 9 |) [0 s& ~( {
StrMessage = Message
8 G3 P* J9 B, ]/ f1 v% d+ ^Set ObjRSA = New clsRSA 0 }; _+ a% g8 ?1 Z
ObjRSA.PublicKey = LngKeyE
& A1 ~+ F- l) I- e) Y( rObjRSA.Modulus = LngKeyN / V* m% P4 V: e) m2 x! d8 J, i% |
Encryptstr = ObjRSA.Encode(StrMessage) 1 f) ^4 t8 R& e5 C) ^; M
Set ObjRSA = Nothing
0 T8 t# T! {5 K% send function
" E1 V# t* F7 qFunction Decryptstr(Message) 5 g1 D$ E4 Y; }6 M. {3 G2 ]
Dim LngKeyE ' E& y- l R; s" T: U
Dim LngKeyD
# i$ H* D& g1 w2 RDim LngKeyN ; @% K3 f) K. e5 ~
Dim StrMessage 9 V* J2 z x: M: D4 X
Dim ObjRSA 9 f; T h; E0 x s. [
LngKeyE = "32823"
2 t+ W1 M/ K0 T a7 y4 m$ zLngKeyD = "20643"
* g$ K9 X) v3 s0 ALngKeyN = "29893"
" s: v7 L; W0 Y! sStrMessage = Message
4 l" M: s9 `) ZSet ObjRSA = New clsRSA 4 T( a( T# @; p/ ~' W
ObjRSA.PrivateKey =LngKeyD 6 k3 @( p" X. Q W( s5 I
ObjRSA.Modulus=LngKeyN
( G! [; W% B" K; W7 c; z a! L' \' Cdecryptstr=ObjRSA.Decode(StrMessage) / Z& s% s R7 z# C2 d% O
Set ObjRSA = Nothing 1 }: [6 e% t* @; m4 u. Q
end function
9 I; o; N$ L6 T: ~1 k( C%>2 q2 J6 b. l5 Y; K
===============================================
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, ~6 n& t* ^# O8 R5 P4 |还有一个用于测试这段代码的test.asp
+ A! G& s0 o% X3 u1 Q有兴趣的自己搭建个IIS测试下
3 J, b0 O i: b<!--#INCLUDE FILE="RSA.asp"-->
4 I$ J8 l, c: ?5 t; ~# b0 X7 S<%: v" e1 L) _1 @ E0 o' }' {' Q% E
function Encryptstr(Message) ' G* r \8 y4 B: @) E% W- {
Dim LngKeyE
3 T6 s! X6 R7 H6 O2 ?% A* gDim LngKeyD
5 p: Z3 g1 X' ]+ ADim LngKeyN ( @, b- ~9 N8 ^3 P9 I7 l) p
Dim StrMessage
! Z$ z* d' ?0 m9 H* d) X+ M1 WDim ObjRSA ; _; w9 |3 d6 \& w/ o
LngKeyE = "32823"
. B s# z% U6 H/ Q4 l" zLngKeyD = "20643"
) K% o8 v; @0 p' T# i( [9 t. D% ALngKeyN = "29893"
2 B/ J7 U' F/ j# mStrMessage = Message
) V3 S! [8 ^' l; kSet ObjRSA = New clsRSA v5 w0 G& P& [5 x7 q6 }
ObjRSA.PublicKey = LngKeyE ! V! v0 m! E1 O( M
ObjRSA.Modulus = LngKeyN
/ o$ v, D1 S c8 b1 I4 a, o, H& OEncryptstr = ObjRSA.Encode(StrMessage)
: d% p' Z1 a! }8 L0 s1 KSet ObjRSA = Nothing
. Q6 A4 Y$ q' K' H3 ~6 Y \: lend function & q8 H( I; z% d+ _
function decryptstr(Message)
2 h0 x1 I. ]6 cDim LngKeyE
) [6 [7 W* W2 V" k! j3 x L9 Z7 xDim LngKeyD * R _* e7 c! m% O! c1 P! g @
Dim LngKeyN
1 T0 \* t- K3 q5 x5 U/ b+ MDim StrMessage
" Z% V0 j) J! F/ q4 @6 kDim ObjRSA
7 v) `2 t! X0 @* {7 ^# a3 l* s1 TLngKeyE = "32823" 6 I* `$ x1 K4 g4 N; w3 J/ A
LngKeyD = "20643" 1 q9 q/ U+ Q+ m, a* E
LngKeyN = "29893" " G6 g+ t6 F4 \! t
StrMessage = Message 3 G5 }* i" M+ N
Set ObjRSA = New clsRSA 0 I7 u9 v4 P( I3 M% g
ObjRSA.PrivateKey =LngKeyD + _! D( O l! m Y/ C1 ^2 g) c# Q. \
ObjRSA.Modulus=LngKeyN
/ N2 x" O1 ]# w8 mdecryptstr=ObjRSA.Decode(StrMessage)
. l6 O0 |- i8 LSet ObjRSA = Nothing
/ e8 \" s( G9 \end function " A } a/ _5 f
dim last,first # A8 D$ L V- H6 j( h, o: l
first="!@#$%^&*()" ' P6 {6 @2 H; I
Response.Write "加密前为:"&first
! s l6 W, f `last=Encryptstr(first) & @. u4 F6 X7 o( J( m; u# ~1 q
Response.Write "加密后为"&last # m( J& j; a0 Y! X; B) L
Response.Write "解密后为" &decryptstr(last) 8 s7 m% Y" }5 {7 B8 Q! D1 \! s$ }
%> ==============================================0 C) m( X1 B/ h! H9 j* L
剩下的就是字符的对照表了
9 z1 O& D3 j! m===================字符集================
- U6 F e, J! ~# o# ]1_____6EBB2 U7 B- p8 J# L7 r! Q6 R/ p
2_____5C1F
. u& N7 m _; z8 ?* h9 ]& ?3_____4D75
0 ?- {3 P3 W; X: m/ l4_____26CC* |5 M( S; V! K) x+ S
5_____4F888 V, E( V9 M5 r/ h; U2 L. ~
6_____3F4E
( [4 Z5 r" Q6 ^) k' B0 T+ L8 b7_____0A9D
4 e5 u Q t: _$ x8_____1A1C. p, Q# H* }$ U/ n
9_____6D20
- l$ H; G7 y: m: M8 U& p0_____1089) A; K2 _, g1 v0 l( @
a_____0F3E
) z* D; ^6 c( g3 r- d7 M: Z/ h, v* ?b_____31594 E O9 k+ L; g7 c3 K/ \0 Y' W
c_____3517$ E: [& _( C N5 Q* L
d_____419C
& I7 q8 N. T, s. X, V: Y" H! u7 Le_____615C% s% n% ]9 p/ |2 \6 _! \
f_____556F
. J# c7 c- ^7 b' P0 D. }1 wg_____2B7F
" f' @1 t, I2 |: I0 Y5 Mh_____0F9C& [( n' |( r0 q" Q7 X6 b0 s
i_____00FA% m5 S4 A6 b4 g, k& C5 w* C* Y
j_____5A50
" i# d4 @' h' a5 c6 a( J% Ik_____2850
]; f, \# e. `l_____3E7B/ O/ y$ Z0 y5 k' J: \' V
m_____71C5. S; b# Y- ~: q+ D: }
n_____1FC8& U( ?6 W1 U5 O- \
o_____74C1
, N+ m: f! H* d& S9 R% vp_____5FB89 e& O7 M: U# c. O
q_____6085
3 T& g, `" K8 a4 V* br_____3AC4
1 t. P7 M1 ?0 f: xs_____2F50
7 E9 p" e% F$ A, E& ~: b! i# L- x: Ft_____36F82 |; r8 a+ m o2 q4 A3 X
u_____7010
; R2 X# x) {/ A9 Ev_____0B42: Z& d: i8 K, U5 o/ n- x
w_____1C7A
# b3 S9 g1 Z) c6 ?6 M2 wx_____16F8$ A3 M) S! ~' V
y_____2EE7 F0 E8 N' g3 n' f
z_____5CF3
: i* p/ ?6 o! k6 A* V5 V!_____6233
, o6 s! n( a5 V. I@_____3A45
* W; N; D f% D#_____2291 \& B* ] T) a9 x
$_____5D5C
1 L: O" l. b2 V$ A* \7 i2 X3 C%_____09B9 v/ Z5 {# p( l! h6 f. q+ W
^_____43EA% V+ j- f$ z3 T- F5 j
&_____62B9
# V2 g! B% y( a*_____63018 t& x8 r; [& _7 a+ U8 X: \; ?9 x
(_____4659( T. Z/ w) _4 e* o* V1 O% W8 r6 |; R; r1 d
)_____5C82 |
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发表于 2009-4-19 21:52
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发表于 2011-12-4 17:17
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