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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm# l9 l* u7 }# \
原始出处:http://www.3ast.com.cm# W+ X ~- u; N5 C `# @; p
! F, t1 K. A. G
看不懂的直接绕过. \7 V& V. z! J; o8 Z
加密前为:hwy123456. a& S8 q( L b
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E' `: s3 F" X+ _9 u" ~ P0 i% Q8 F
' U% J7 H# z+ s; i; L+ k3 i============================================: E; N8 v e! L7 C. i
上面是当时自己校内的心情。现在已经解破出来了,分享给大家0 R$ }' i. K8 T( l1 w9 q
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
6 B! F* J, R# k2 Z以下是RSA算法文件
5 v1 a }% {9 }1 [- l+ R1 C* _% H8 u1 p
文件名RSA.ASP
4 A, N- U$ h+ `+ O) c===============================================
" s, C" n5 q# G- T& U7 v& G- \" u, L<%
! J; b* q& P; Y' Q4 K& `6 p# CClass clsRSA
( R4 W5 w8 K. a9 E% ?1 p2 ]' DPublic PrivateKey $ b# w1 V1 k s# L+ `5 z* e
Public PublicKey - w( G3 O: M( Y" r, ?
Public Modulus
% o7 K5 v+ K( y! U. QPublic Function Crypt(pLngMessage, pLngKey)
9 o, U" C9 }* S4 o7 O( i3 lOn Error Resume Next - m0 I: ^, N9 O* \
Dim lLngMod
. [5 N; X% r" MDim lLngResult 1 ]8 U! K7 S8 Y% W
Dim lLngIndex 5 o* J/ w# k: U5 L
If pLngKey Mod 2 = 0 Then V# s) v8 @- ?' \, m1 @
lLngResult = 1
" b8 `$ o; n( SFor lLngIndex = 1 To pLngKey / 2 ! x) U3 H" m1 R! p9 Y) v; ` R
lLngMod = (pLngMessage ^ 2) Mod Modulus
0 }2 e. J+ G5 a2 M+ E9 K! |" S' Mod may error on key generation % F! `! {5 \+ n1 w; s
lLngResult = (lLngMod * lLngResult) Mod Modulus P' f. a6 u; Y, t1 T+ Q( f
If Err Then Exit Function 1 ~; d% h& d0 ]
Next " {7 d& N, b8 L+ w" y4 T
Else * I! h' b6 Q+ h) W \; C
lLngResult = pLngMessage
2 n( O x$ u, u8 d0 @0 LFor lLngIndex = 1 To pLngKey / 2
/ ?8 q. m9 E0 C: d1 @lLngMod = (pLngMessage ^ 2) Mod Modulus
) R# M+ u* F7 ]- e% a0 xOn Error Resume Next + `9 M% L0 b# F/ h; t) m- }! j
' Mod may error on key generation
4 e7 W+ b3 N( V: G3 E: KlLngResult = (lLngMod * lLngResult) Mod Modulus
1 `) a$ p6 _& Y1 V2 s7 p3 n' ?If Err Then Exit Function
+ P( ^0 I% S" Z a+ |- O- R: DNext & b6 g0 e6 J, t
End If ; y0 @- j h( N$ S" `: M0 q
Crypt = lLngResult
6 |; D* y( l( r" YEnd Function( V' W- f; V6 H8 n( r$ p
9 d4 ^5 |( v/ g$ H3 C0 R
Public Function Encode(ByVal pStrMessage)
2 c, G7 d2 Z" PDim lLngIndex " ]8 f/ T; l8 K6 p. C4 O) n
Dim lLngMaxIndex
& |( v' P; n* D& q& nDim lBytAscii
) r6 k$ Y& L% u& nDim lLngEncrypted # t' |% s$ [. `% ?
lLngMaxIndex = Len(pStrMessage) 5 n6 ~5 m" t6 h$ C3 U, H
If lLngMaxIndex = 0 Then Exit Function
9 {3 R8 U# M( w8 V; |For lLngIndex = 1 To lLngMaxIndex
, n4 K9 C t/ ~$ C1 I9 E+ clBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) # g" ~# ?- u1 p4 p$ Y" v1 U
lLngEncrypted = Crypt(lBytAscii, PublicKey) : Z% u' ?% v0 m/ H
Encode = Encode & NumberToHex(lLngEncrypted, 4) 0 Z0 s# ?) A) g' p* M% l. {4 \ x6 j
Next 1 b% Q# v$ B9 Z" H) z0 e0 n) @
End Function * ]3 X0 b* Q3 Q7 m
Public Function Decode(ByVal pStrMessage)
) O0 G. ^3 u1 A5 LDim lBytAscii 3 E5 F7 Q4 W/ x- e- v; v
Dim lLngIndex # @: M7 o5 m- Y) q+ G& M' f
Dim lLngMaxIndex ' g' g0 H" D2 Y5 O. Z' ?
Dim lLngEncryptedData
( O( i/ L* P/ z5 |" N, J; L8 JDecode = ""
* V% P/ a( S4 MlLngMaxIndex = Len(pStrMessage) 6 y( {! y; J" u# C
For lLngIndex = 1 To lLngMaxIndex Step 4 0 p; u# a7 R0 N7 k! y6 V+ W6 O: r
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) * Y" h6 h5 r$ V. z
lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
. u, w* t: ^4 a: V% }7 y& VDecode = Decode & Chr(lBytAscii) / }2 S5 v2 a& b& ]' X/ D) A
Next " E/ q! ?( v; [. R' I
End Function , w$ h. o# }+ [1 L6 l% {: }0 a- w
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) , n# s: [. ?: N5 j
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
7 v' s& h2 B; e5 T3 W" c: ^End Function
/ m% d: A. R% S" oPrivate Function HexToNumber(ByRef pStrHex) + T* S3 |. I# S9 q2 Y) _: K
HexToNumber = CLng("&h" & pStrHex)
* A5 O9 v6 U" FEnd Function ( Y% ]( {0 b6 R# P2 v+ h' m- h- l h
End Class
0 Z- u( F" r2 s; a( xfunction Encryptstr(Message)
3 K. U. S3 e" B3 V# Y# P A2 t# [Dim LngKeyE
- h: ?3 d5 O2 } V c; ~Dim LngKeyD
4 J- g1 t- f8 r8 A) r+ XDim LngKeyN
% j& w( i& [& g7 H; o9 ADim StrMessage
4 _0 I" z* Y! K6 k" T5 zDim ObjRSA
3 U; J, r# Z/ ]$ b4 G9 YLngKeyE = "32823"
' J1 w6 o0 {* {1 B6 X0 }5 pLngKeyD = "20643"
- G9 t6 D9 c3 F7 T7 U4 xLngKeyN = "29893"
1 H; `" l# U; x. H# T$ mStrMessage = Message 6 M! P" k4 y7 Z* a. Z# D; T
Set ObjRSA = New clsRSA + L8 D. y, v% M/ \) {0 F
ObjRSA.PublicKey = LngKeyE
. o) e+ ?, M9 n- M3 F) DObjRSA.Modulus = LngKeyN 4 @2 v' S$ ]! I3 X; s
Encryptstr = ObjRSA.Encode(StrMessage)
' K- E. C7 }& b) ~% N; uSet ObjRSA = Nothing 0 @8 h9 ?2 W- [" v( \: x
end function
* O# \) v _; u9 H3 K, Z* SFunction Decryptstr(Message) 7 b) ~+ a$ a& G# t2 D/ a" d4 L
Dim LngKeyE 3 l) t' ~7 K* p3 Y
Dim LngKeyD 8 J0 e% I% r, e$ D4 e; ^* ~
Dim LngKeyN $ O, P6 i8 ^) M% y
Dim StrMessage " B# h( z6 V4 @+ B2 i
Dim ObjRSA 4 o! c* N5 Z- k) n* f6 V, G# w
LngKeyE = "32823"
$ T" O- K) [; o7 m, i, o& a% mLngKeyD = "20643" ! V, S' r& E1 i1 t$ i
LngKeyN = "29893"
* T9 d& } r4 gStrMessage = Message s, m; }& Z1 \" g2 f2 |
Set ObjRSA = New clsRSA
) ]1 d! M! o' G# v. d7 M: o& FObjRSA.PrivateKey =LngKeyD
" d) Y$ f5 M w! U6 w9 A2 Y7 fObjRSA.Modulus=LngKeyN
/ ~5 a" W% x' j7 Ldecryptstr=ObjRSA.Decode(StrMessage) % |- y: @. O+ r0 p7 M
Set ObjRSA = Nothing
$ [2 o0 c! u. U6 B- s: kend function . {% x0 \2 b1 y6 J" {$ e
%>
3 x% F% e1 [5 V- {===============================================, y+ m# V* p+ `1 `. s# m
0 I( W' b$ P* L% H0 b% H还有一个用于测试这段代码的test.asp
# `/ ?/ k7 Q! z有兴趣的自己搭建个IIS测试下
4 M/ K( M$ K+ l8 |<!--#INCLUDE FILE="RSA.asp"--> / v- [0 U# P, @! T2 g
<%
- \! M/ @1 l, P7 S, }function Encryptstr(Message)
0 M/ `8 G5 O* I. d& k) T6 f4 y! \! EDim LngKeyE ( j9 D4 v+ P2 }3 a3 R5 ]
Dim LngKeyD
" h. n! x7 q7 sDim LngKeyN D7 a$ y0 }! @9 {0 b2 p a4 L
Dim StrMessage , S5 _& M7 A$ |1 Z7 S+ E9 m
Dim ObjRSA
8 w; F6 M; L6 T" PLngKeyE = "32823" : Z5 K( L1 {9 F( o) `; k2 H
LngKeyD = "20643" . O: S- _" Y1 r3 h/ X3 m+ O( F0 T
LngKeyN = "29893" / \: u+ i/ u" k" m
StrMessage = Message ! `0 O0 S5 x; u1 H' s
Set ObjRSA = New clsRSA
0 \7 A2 X9 }+ f/ o7 y! GObjRSA.PublicKey = LngKeyE $ j% e* x ?" Z/ e, L8 y0 i# K
ObjRSA.Modulus = LngKeyN
: e# ^1 r3 w# o% gEncryptstr = ObjRSA.Encode(StrMessage) " q! V$ w. T$ i j+ o9 K
Set ObjRSA = Nothing
4 Y- h% F M* U8 V4 O8 oend function 5 ?6 h7 P7 n1 C( n8 b l) Y2 }
function decryptstr(Message) , }+ J* b: x' b* A8 R" a
Dim LngKeyE 6 S# J$ s5 ~& \
Dim LngKeyD 8 Y7 V$ O1 y0 C+ _+ `( s* I7 X
Dim LngKeyN 0 H) \2 m. G! a0 @- b G" C/ n( z
Dim StrMessage [1 C' z3 D5 J0 | y
Dim ObjRSA
9 `% A! x$ `& W6 h) u, xLngKeyE = "32823"
7 I, v1 |; |& j! H/ xLngKeyD = "20643"
! {5 h) p) @: }. g4 vLngKeyN = "29893" * Q+ i0 Z0 e4 I3 N+ o2 r1 \
StrMessage = Message
& {2 [% r. q. H/ VSet ObjRSA = New clsRSA 9 c& ^' q3 R: w3 t' G4 `$ O
ObjRSA.PrivateKey =LngKeyD * Y$ n- N+ g2 g8 \4 G: p; V& S$ d
ObjRSA.Modulus=LngKeyN # G! z0 W2 |" r+ ?8 K
decryptstr=ObjRSA.Decode(StrMessage)
, N% s6 J$ X$ D" N) d. OSet ObjRSA = Nothing
* s, x9 Z' ~- [, tend function / \' Y$ n$ [! f
dim last,first 9 ?- G: F* x6 _- I
first="!@#$%^&*()" 4 r0 D* C7 `( j0 I9 n7 `# n
Response.Write "加密前为:"&first ( `/ t4 f/ a; G0 Q* _+ c
last=Encryptstr(first) $ \$ o' Z3 }6 S! E" u$ p/ l5 {
Response.Write "加密后为"&last 6 x- w5 Q* ?7 b4 F( M$ p' L
Response.Write "解密后为" &decryptstr(last) 1 R9 R% _( u+ n, Q5 b
%> ==============================================
; ^, u& z9 y J- [剩下的就是字符的对照表了 G5 f. X6 p' W3 _! j, \6 v
===================字符集================, f6 R# C1 u' [" `
1_____6EBB
2 }* C5 W& u, T- Z* ]6 ]2 E2_____5C1F' R- s, R- @1 @$ P+ k" N
3_____4D75
1 g0 o$ A3 K- m4 O2 G4_____26CC
1 Q ?% ^' {9 m. c6 s% v' b1 o5_____4F88
- P! h# E* u- r. a3 D6_____3F4E i \+ J( j0 b& e$ Y8 g
7_____0A9D
5 F2 d! a6 \0 T8_____1A1C
& Y) X+ `9 ]* Y2 S9_____6D20
2 `5 r/ {. S6 I2 u0_____1089
+ t9 x8 H1 _) A5 y0 H: H8 K& ?a_____0F3E
: ]: D0 g% I% A4 u/ _b_____3159
4 v' i2 \% T1 R5 c3 [' ?$ cc_____3517! d/ ?1 K; M- d4 ]8 _; D0 r
d_____419C. `4 s3 n, o8 _# g! @# ^7 {6 _
e_____615C
# R4 w$ F7 Z# Uf_____556F. o7 Z; |, C# ?
g_____2B7F8 _3 w+ C; O0 m- i9 Y$ p C
h_____0F9C- g' y/ f4 _8 t! P1 p
i_____00FA
* O# T0 {" F- N: A3 }j_____5A50
4 u1 k0 H" N; J3 \* e4 uk_____2850
' p7 v+ r; o7 Jl_____3E7B N9 k! R" g& u: r
m_____71C5% m" t- R1 c5 q" m1 d+ y
n_____1FC84 k4 Q1 V# H& }8 @
o_____74C1 G( V" W; H9 Y U6 Q
p_____5FB8, @" i! E6 G0 p" B, b0 y7 ~
q_____60854 |! \4 M+ \' p1 F( b5 e
r_____3AC4- m$ B# k: A# G8 i/ g
s_____2F50+ K) G* o. ? ]5 M0 \' |
t_____36F8
" O. u/ ]) X8 M& i' M6 Au_____7010
2 i) B1 n. R$ x8 iv_____0B429 g8 v8 i6 j/ k3 t
w_____1C7A
% m7 p% j% b/ o& h# u0 Cx_____16F8
% \ s4 c! U9 N( Z4 Ay_____2EE7' F! d; R& J6 n9 t
z_____5CF3
" L" j$ ?! _: Z9 b!_____6233
. V+ c% w# S' W p( e* h@_____3A45
7 E1 _+ ?2 Y' E8 k2 v* G#_____2291' E8 b: X7 R! P: n' B4 j
$_____5D5C4 l9 ^: b* J% W# p
%_____09B91 U# A; Z/ n8 Q3 K/ s* C
^_____43EA! H5 C. S. b+ ^& N
&_____62B9
r" [% K3 E% @+ w2 D*_____6301
; B6 d: X* k2 b$ l* j' O+ ~(_____4659
$ H5 }9 X ~0 V3 K; z)_____5C82 |
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