- 帖子
- 3852
- 积分
- 13044
- 威望
- 16780
- 金钱
- 36761
- 在线时间
- 1139 小时
|
原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
/ W# ]5 A. W% B4 ]* X5 O原始出处:http://www.3ast.com.cm6 N" W6 j" p0 H- ]1 [, T
, n7 w- ], k: _3 V0 U
看不懂的直接绕过
, _6 g5 L2 b1 k. N# d4 x4 W$ Q加密前为:hwy123456
! K, G+ f5 p: P) R; e/ z- c加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E- c1 O; z Z" S- L+ X" r) X
4 T: s" B* k6 y0 y! }4 \% L
============================================
) j/ `2 e3 M% ^上面是当时自己校内的心情。现在已经解破出来了,分享给大家3 j- J! O# H2 E* C E
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法3 `( k5 ]* y1 \2 ^# Y
以下是RSA算法文件
! v' X3 p4 J" i( s: ]9 z3 R" b/ d
/ V6 r3 T1 C' C# M4 _4 h! x" u4 U文件名RSA.ASP- n9 N9 }8 K4 |# f) I. Q: ?# y
===============================================
1 M. ~1 t3 K A6 C<%
7 h7 ]+ ^7 Y4 M& Q1 GClass clsRSA
# X. s) x- ~. G7 X* ~Public PrivateKey + S& a- N* Q6 Q9 T
Public PublicKey
& W, X6 V+ o6 i0 u S3 B8 bPublic Modulus 3 Z9 H& }& w7 k# N8 v5 n
Public Function Crypt(pLngMessage, pLngKey)
1 Q; ]: e+ M- K" d, b7 N! TOn Error Resume Next
/ x& o( A9 k, u0 bDim lLngMod
7 n- M, b+ L, A) ]- WDim lLngResult
/ u+ F4 {: t( S& @, H& d: T- ^Dim lLngIndex
; s6 S6 }6 m& H$ J- F" EIf pLngKey Mod 2 = 0 Then
" Q8 X O2 S6 a9 B7 S" p; n% NlLngResult = 1 & |+ l+ q9 P% b7 {- G3 O
For lLngIndex = 1 To pLngKey / 2
+ I4 `1 v5 Z" {2 ZlLngMod = (pLngMessage ^ 2) Mod Modulus
7 t( F+ b' z# m2 R' Mod may error on key generation % G l2 ]! C3 Y3 a3 p
lLngResult = (lLngMod * lLngResult) Mod Modulus / j1 Y7 \2 o1 ]" w5 f3 t
If Err Then Exit Function v. C: t6 a$ q. K7 C% |. }) D
Next
7 K) j: _+ i9 P" b* |Else $ F8 u2 D& m9 K, n8 U. t
lLngResult = pLngMessage
8 K! \& a5 D! u% w; h% GFor lLngIndex = 1 To pLngKey / 2 4 K7 g$ O: q& N4 i: V# x( S
lLngMod = (pLngMessage ^ 2) Mod Modulus
; G) l, R! U9 J, r! N5 T2 I$ ROn Error Resume Next
5 S+ k+ ?+ A' [7 a1 m' Mod may error on key generation ; m& e7 S6 W+ ?* B. s5 J) a+ S% m
lLngResult = (lLngMod * lLngResult) Mod Modulus
5 H/ F" {) L! G, C/ O5 y4 k( aIf Err Then Exit Function % k/ X% E" U+ g( v: l
Next
9 @9 _2 u- @. h. U# g# `9 F5 @End If
9 L e3 C6 Z$ r" n: K* W" [3 KCrypt = lLngResult
1 O3 L& s2 l# k5 P) B% d/ pEnd Function1 H8 K3 r4 H, r7 r% k' R! H3 A7 c2 z( m
& L3 X. a. M1 y3 T1 {, t+ e
Public Function Encode(ByVal pStrMessage)
9 D' ` a; {/ y( c9 L3 FDim lLngIndex ( u# z, L# l8 @: L2 R( \' l4 v
Dim lLngMaxIndex
+ C, e( w& `0 ?! s4 ?" _5 oDim lBytAscii
1 o' u8 O' I. @) S% z! ZDim lLngEncrypted
$ c5 M. ?& h1 @' t2 _* @# U- s3 @lLngMaxIndex = Len(pStrMessage) 4 Q# V! E$ V3 v" h9 ~* J: X9 @
If lLngMaxIndex = 0 Then Exit Function 6 q% P+ I8 G6 g9 T' V' `0 F1 W+ O
For lLngIndex = 1 To lLngMaxIndex 5 \( t1 ~2 Y! c2 G4 N, t
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) 9 _, t1 S9 S' _& V9 B9 D
lLngEncrypted = Crypt(lBytAscii, PublicKey)
! ^! G1 ?9 D; z1 ?$ @7 JEncode = Encode & NumberToHex(lLngEncrypted, 4)
; j9 ^) H1 {+ O; O9 L2 ]Next & [$ q8 @/ l! P
End Function 6 ~1 g) i- l4 `: c: V0 d
Public Function Decode(ByVal pStrMessage) " I2 o9 C7 i5 S8 ~- `' E
Dim lBytAscii
* y* f( b. @0 y- oDim lLngIndex
9 t6 m: z) y" Q+ U* V% H* oDim lLngMaxIndex
7 F6 q# N x0 o: u& X1 l- PDim lLngEncryptedData & n( E5 W# w( H# Z5 y3 m5 k1 p' I! S
Decode = "" - w8 M' g: K- Y% p1 t
lLngMaxIndex = Len(pStrMessage) ' _% v' a1 F4 e3 m5 ?
For lLngIndex = 1 To lLngMaxIndex Step 4
C# J. i/ N) J7 \: WlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
4 {) h& s, a0 `% C7 U2 D* olBytAscii = Crypt(lLngEncryptedData, PrivateKey) * D( C; @& f- i/ N1 r6 S% h8 F1 y
Decode = Decode & Chr(lBytAscii)
" |) h1 I' Z% U: q, {& z6 LNext
& Y8 P+ e- T" PEnd Function
% z6 K5 V: I/ l! r2 SPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
! R' |6 V5 a$ v3 t2 pNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) 7 A4 x5 l) O8 ~) E4 P+ U% t5 I
End Function
$ T' s! U+ [; l/ A* M# N( NPrivate Function HexToNumber(ByRef pStrHex) ( X, ]1 H2 V9 ^+ I0 l4 T9 m% z o
HexToNumber = CLng("&h" & pStrHex)
* K+ k' [8 b+ O: [) \End Function
}" O( c* j; P C, E0 E1 ~End Class " J) Q( f5 `' H
function Encryptstr(Message)
' \* H/ k2 ?/ ?) B: pDim LngKeyE
( ]5 `, f6 s. k$ P9 F LDim LngKeyD
- k0 E3 q$ J6 v- m7 PDim LngKeyN
5 M; }8 x2 ?/ D8 D$ k& v ^Dim StrMessage
' Q7 O* T) l7 E. n2 V, bDim ObjRSA
9 T% F; R, R3 {6 E1 K: i. }' b4 uLngKeyE = "32823"
- x) q( d' Y& f# D$ fLngKeyD = "20643" ' \$ Z0 t1 U& n5 }) n U, w, B1 D
LngKeyN = "29893" + j& h$ x( }0 k
StrMessage = Message
: w& D) g3 x) Y$ M1 R, sSet ObjRSA = New clsRSA
d5 `& g$ [6 _( }5 aObjRSA.PublicKey = LngKeyE - k- R! F) v/ R# ?, U& K5 M
ObjRSA.Modulus = LngKeyN
+ {5 O, }2 ~6 j3 f4 T2 |$ |( ~Encryptstr = ObjRSA.Encode(StrMessage)
3 _( y _# N' i7 d( K* y6 P+ Q( qSet ObjRSA = Nothing 2 I- W5 I. p1 x% z* b
end function
# a9 F( l9 d5 p5 u! w; BFunction Decryptstr(Message)
$ D1 S8 V9 m% QDim LngKeyE ) C( W' p3 f0 T5 G1 U
Dim LngKeyD
- ^( _& }' m- h: h2 L% N1 S% zDim LngKeyN
U) `# M/ z# |/ kDim StrMessage * N6 n0 I, D9 ?' G ~8 x
Dim ObjRSA ! [% y( x1 s( [, [/ P
LngKeyE = "32823" 2 w! U1 A9 C6 H
LngKeyD = "20643"
2 C5 ~" R" M0 O( ELngKeyN = "29893" ! h2 e2 p% }; d% z
StrMessage = Message % d0 r- B3 U4 {% Z" _8 K
Set ObjRSA = New clsRSA
# \3 G0 e( y+ }# zObjRSA.PrivateKey =LngKeyD
7 ?1 t* I+ w9 s5 l/ }ObjRSA.Modulus=LngKeyN 3 w8 q' S1 v* {8 q, E% d) A- m
decryptstr=ObjRSA.Decode(StrMessage)
8 E) f/ m- v' ]7 kSet ObjRSA = Nothing # f7 `4 Y4 k* \3 U
end function / H& D) A0 p: Q' \3 E
%>4 r! O& } E/ m0 N) A% P% P M0 F' a
===============================================+ g0 v B- X, j' o b+ Q
0 W& K8 ]! R7 e7 D2 p- R, M0 B还有一个用于测试这段代码的test.asp
R( P2 \0 e8 j- e s8 p( ^有兴趣的自己搭建个IIS测试下" l5 h E1 c* p
<!--#INCLUDE FILE="RSA.asp"-->
! [1 i; }& f6 C* a; Z8 ^<%
+ E& n- Y5 b+ m! P! v" R# p2 yfunction Encryptstr(Message) 4 ^5 n, O4 s( q/ W( z& ^8 r
Dim LngKeyE + m- S$ @# v! Z2 C( S
Dim LngKeyD
( C* ^, p9 P6 D i$ u8 V" n* E% LDim LngKeyN
' l; d, n% [3 b/ W) u0 x* QDim StrMessage
' y2 C7 E O* n3 kDim ObjRSA }+ W# W- f$ \8 A: | u' N
LngKeyE = "32823"
' w4 g) Q* ?6 m3 _, lLngKeyD = "20643"
1 D3 K# B2 a0 c0 h) I/ |% ALngKeyN = "29893" 1 P; t3 H+ @: o7 t5 Y
StrMessage = Message @$ |& @7 P" w: V. m8 D) t. i, p" j
Set ObjRSA = New clsRSA
- |; O J* r7 Q! v; QObjRSA.PublicKey = LngKeyE
7 x9 J) ^- q7 Z! D& \' xObjRSA.Modulus = LngKeyN
. T* Q" L9 p- d! n5 T0 AEncryptstr = ObjRSA.Encode(StrMessage) - c0 i9 v0 T* s: u7 H: i
Set ObjRSA = Nothing E! m f+ B3 O2 a. o0 ?8 |: i
end function
7 V4 A+ u' u- k4 t" h {9 ifunction decryptstr(Message)
1 Y' h; j! k, u- qDim LngKeyE 2 Z) W- E! I6 o) p1 r! k
Dim LngKeyD
. J( o) ] { sDim LngKeyN
4 N3 h3 Q7 \* Z6 r! b* tDim StrMessage # }! k( p! _7 `# W% X# o- E
Dim ObjRSA
( B, _. ^' I7 I. i7 M/ PLngKeyE = "32823" , Q( M# ?4 {) H: y+ A! e
LngKeyD = "20643"
3 g7 G: j9 m: X: p9 @+ OLngKeyN = "29893" 6 \ H9 i# n+ h; Q2 l
StrMessage = Message / f9 O" b7 w0 w( C: C
Set ObjRSA = New clsRSA
) A5 z7 O: [6 p4 A6 z& P8 m7 RObjRSA.PrivateKey =LngKeyD
4 y6 _2 C* {2 O0 }1 W4 V) P5 _ObjRSA.Modulus=LngKeyN
0 c4 e6 h k$ K P1 y% O5 Jdecryptstr=ObjRSA.Decode(StrMessage) ! }2 h1 c ?- X& S" T7 E* g( j8 U
Set ObjRSA = Nothing
# L) ^6 H1 @) t: ~9 fend function 1 q" n6 H h; S: ?2 C/ k9 f
dim last,first
4 {% w: m! c1 _& Z1 B" C+ T/ @first="!@#$%^&*()"
! y9 Z9 {1 Q# M/ UResponse.Write "加密前为:"&first / _5 f& D( w2 I o
last=Encryptstr(first)
6 _" _1 N: z: J/ VResponse.Write "加密后为"&last
I7 ~/ A2 _2 {$ K+ I9 TResponse.Write "解密后为" &decryptstr(last)
# P, z/ L: u/ Y% S- u: @" n; }%> ==============================================
+ x! X0 i- H4 |/ v剩下的就是字符的对照表了) E: c+ Q7 {7 r, f
===================字符集================) `* u1 t5 D5 }$ D$ u; ^# [
1_____6EBB
6 L2 Z# Z Q5 p6 K9 k2_____5C1F
6 y' w" |, {5 b7 X1 d8 z- d8 S6 j3_____4D75
1 H1 i8 B6 `, a4 v6 Q8 F7 w4_____26CC
$ f" V* _4 a, r3 a4 ^2 O$ Z5_____4F88
6 l7 |9 K. H' c) \# C! T4 ~6_____3F4E' z. R8 n' A! y
7_____0A9D7 p& G; s8 V @! ]
8_____1A1C% L# j% {2 D+ G1 w$ b1 H1 Q
9_____6D201 K5 M" w$ H5 i
0_____1089
; D* _7 T) e2 }) Va_____0F3E
. x" A' C& |3 k" W' t q( w/ |b_____3159
: U! y- b& J a( B' w% e! } t; R8 L0 ^c_____3517: z' u( _1 O% F4 h& ^! i
d_____419C& r" B" A* \( j* D0 G
e_____615C
$ B. t# u3 \* a; R8 L4 E& |& h. ]f_____556F- M) S6 A2 _8 S$ ^9 ?9 Z3 o, f
g_____2B7F
) N" n" r9 `9 [7 y3 b+ Eh_____0F9C
) Y0 r7 o$ I$ @3 ?: n2 B S5 C* a0 yi_____00FA
) F2 F- l/ z6 G* {. k+ S/ j+ ]# zj_____5A500 p o, e5 V# d- g3 J2 @2 s% Z3 [, P
k_____2850
7 O c, w( }. m# O. h) _( nl_____3E7B
6 {/ k( a& h. G) [1 g, }m_____71C5
% e/ X3 e3 U6 Z D T- y( cn_____1FC8) g: ^3 \4 B7 {8 g9 ?! y
o_____74C1
8 ~$ j( `7 t8 rp_____5FB8
7 x" W* U9 m, V- sq_____6085) @: x, B1 I4 D! z4 T( ]
r_____3AC4
6 a/ n+ e# ]+ `. ]s_____2F50
$ H% V/ ?" Z2 Z) ^: E/ D9 xt_____36F8
# d' _- j$ \+ f5 ou_____7010
/ s9 `/ }* y; B7 [v_____0B42/ c7 H: b; s! v7 l
w_____1C7A
5 {+ t1 H& |" kx_____16F8' ]* O i/ W5 p' Q9 K+ C8 E% n
y_____2EE7
- E Z; k* A* N, |z_____5CF3
% e1 {5 B# c! |( M!_____6233
$ w m) n1 ^1 L! ^2 f@_____3A45
2 a. ` \1 Q l& z9 E! ?+ M#_____2291
; |+ y1 l) x" a$_____5D5C
$ d6 `: _* v/ p7 q! `%_____09B9+ I3 B) ^- A. |9 M
^_____43EA
( L& @% ^) J$ j. B: F0 Z&_____62B95 e- x. m6 ^7 K; N3 d |5 H
*_____6301
# U( l4 K6 K1 J8 T: F: O; t$ M v(_____4659
! k3 L$ s1 m3 y. S2 z)_____5C82 |
|