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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
8 r& l. N+ m! h! o# ^8 Z原始出处:http://www.3ast.com.cm
% [) G$ Z t# |1 n9 S9 J. ?. G
' F, M6 u) O' }; j- Z6 v. O看不懂的直接绕过
+ U y* u: e. h/ g8 l4 I加密前为:hwy123456 Q) E2 L8 S( [8 s4 ]) X
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
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============================================
" y" v7 T6 \% _9 V {) j4 R0 N上面是当时自己校内的心情。现在已经解破出来了,分享给大家
p! W. J. B" J& @8 i0 {) G也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
* r Z8 Q: w4 z% |5 |# m5 b/ J1 D) j以下是RSA算法文件9 N: s/ K( N! r, _: E
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文件名RSA.ASP, `, l+ s7 }$ ]" i1 w3 E1 @
===============================================/ E. R# h: i7 v7 [' j6 X8 Q
<% # E9 R$ C2 `5 m
Class clsRSA 2 B/ O/ F5 S3 r0 a) f4 z. l! i
Public PrivateKey . A% b& w3 ^5 `; R$ _7 M5 c
Public PublicKey
8 m$ F1 T% W" y8 Y2 Z" vPublic Modulus
, Q/ i Y; `- z& h- v2 JPublic Function Crypt(pLngMessage, pLngKey)
; D8 ~! I* ?% w" S/ l4 xOn Error Resume Next $ ]. E. l6 {8 i* O) T
Dim lLngMod
. e2 x- U! p3 s: z- ^1 f/ i- CDim lLngResult
( w# h! g7 b8 QDim lLngIndex 3 X8 ^% H$ ^! s# `: Y! }3 T
If pLngKey Mod 2 = 0 Then ( u. X& x+ {5 z/ \$ D* }
lLngResult = 1
% ^8 T% o, i# R8 LFor lLngIndex = 1 To pLngKey / 2 * p* Z7 o" E* c! Z+ ]" h
lLngMod = (pLngMessage ^ 2) Mod Modulus 0 f9 a( W2 V: I* D6 D
' Mod may error on key generation $ _* U e) n7 c, g# E4 B
lLngResult = (lLngMod * lLngResult) Mod Modulus . o3 m5 {5 F F7 l/ y$ { r
If Err Then Exit Function " L+ i9 V+ `3 C4 e/ A
Next - H0 l, v. d$ X- i) p4 r2 j4 q& G
Else
0 \: K5 H7 I$ klLngResult = pLngMessage 0 w; P+ h! s! [! u2 k \* W
For lLngIndex = 1 To pLngKey / 2
, ]1 y- g/ t) j+ w# v6 i) j8 YlLngMod = (pLngMessage ^ 2) Mod Modulus 3 ~- S4 x. x2 s7 F; m( A
On Error Resume Next ( ?% |& q t8 h0 Z: \; p
' Mod may error on key generation ! C0 ?: f3 T3 i% r9 w
lLngResult = (lLngMod * lLngResult) Mod Modulus
3 q- n5 D5 P- yIf Err Then Exit Function
) \. u i$ ?( e, p5 h) rNext
0 I. B+ `6 o0 J aEnd If " R/ B: A) e5 Q
Crypt = lLngResult 5 i! }& ^) k! b) F" I6 w
End Function
+ e z& k* T) }8 O
x. I3 [$ V1 K6 x/ SPublic Function Encode(ByVal pStrMessage) % h* L) L4 W% ?3 \/ h! C5 q
Dim lLngIndex i( P' f0 g( T7 L
Dim lLngMaxIndex
" p0 w. m5 h! b' q6 k0 ^% O: aDim lBytAscii
! ~; b+ j( ]( W9 z1 D" `Dim lLngEncrypted - R) j, T0 I+ q+ Q& z
lLngMaxIndex = Len(pStrMessage)
' S& ~0 Z. a. G; fIf lLngMaxIndex = 0 Then Exit Function 1 n1 n3 |7 f% i6 \
For lLngIndex = 1 To lLngMaxIndex + ]* j& m, ^" M. {0 p* N. \
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) # r, ^% @2 J' d: c- W ]
lLngEncrypted = Crypt(lBytAscii, PublicKey)
" j6 g3 ]% ]7 h1 D, T) q" X: }Encode = Encode & NumberToHex(lLngEncrypted, 4)
( w: r2 M" b eNext
1 D. |/ I) R) O$ TEnd Function 6 I' T& y! P) o2 W# T
Public Function Decode(ByVal pStrMessage) , T+ h- w9 G$ U6 s& \" ~+ M
Dim lBytAscii
, |: ?& m! s4 @' V5 QDim lLngIndex
3 m3 u0 r! C# t% g) e i5 {( T9 ^Dim lLngMaxIndex
: M7 |4 H2 V( t1 v; K2 xDim lLngEncryptedData
' t0 m% {) f4 [8 ^Decode = ""
8 b9 Z* B$ p$ H; O2 n2 LlLngMaxIndex = Len(pStrMessage)
& U2 A) V6 u! k2 u9 }3 `$ eFor lLngIndex = 1 To lLngMaxIndex Step 4 $ {" @( O* O/ H7 }. B7 @
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
, _9 V% ~# a% o, z8 ?lBytAscii = Crypt(lLngEncryptedData, PrivateKey) 9 \# w4 r% v( ], S' J
Decode = Decode & Chr(lBytAscii)
0 d! T1 H6 @/ S8 ?9 zNext
- b7 i u2 K2 }$ ?End Function 6 N, D) w: |: C9 [+ M5 K) n+ a
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
' Y# V3 y3 [* c+ I5 K r: ^' S, |NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
. C+ z, ]: O9 f: U' eEnd Function 2 W$ t' P( ~& I- {" f3 r7 `
Private Function HexToNumber(ByRef pStrHex) ' D: h, n9 y0 f6 }; j
HexToNumber = CLng("&h" & pStrHex)
6 Z0 P+ o8 q) T$ BEnd Function ' [* H( ~/ `1 g+ K7 W5 j- c( c8 t
End Class . g- {3 @; Z7 ?3 A
function Encryptstr(Message)
7 E" |; e# Y1 r @1 L- ADim LngKeyE
" L4 s2 P) M: E2 dDim LngKeyD
" r2 P" o9 ~. IDim LngKeyN 4 k- L( n- i, U6 x1 k J
Dim StrMessage 6 D$ u* z/ ?2 o4 \
Dim ObjRSA
1 ?% Z m% |4 N9 I( i# V& [" r3 bLngKeyE = "32823"
?: v5 G/ t( {" {LngKeyD = "20643" " H) L7 L! T3 r2 ~; g' m
LngKeyN = "29893"
3 l* v/ e8 ~& p, N7 X1 IStrMessage = Message . A8 R: u( `1 T: N# c1 _+ o2 u
Set ObjRSA = New clsRSA
, Y* B/ W9 u) LObjRSA.PublicKey = LngKeyE
* Y! u# Q* L, S6 O! U2 J* U" P5 bObjRSA.Modulus = LngKeyN
. k. I! U p/ f8 z; TEncryptstr = ObjRSA.Encode(StrMessage)
! H+ T4 M8 w7 k6 C0 c8 @* Q$ }! P+ M: \Set ObjRSA = Nothing ) [2 w& l- g; j1 o; Y. H
end function8 ]$ F' t/ V( _8 `) T
Function Decryptstr(Message)
/ z. l( {- R9 T7 M# W% NDim LngKeyE
- X! L% E; |. Z8 ]" @4 x- \Dim LngKeyD 4 R1 d7 u* w$ r" n$ f8 ?( f
Dim LngKeyN 5 @" k* M7 p, [: k
Dim StrMessage , F1 w c, a- c- U
Dim ObjRSA ) Y& S: d1 k" M4 o
LngKeyE = "32823"
2 s7 @8 ?2 a" a5 E( [: r4 r4 N4 ELngKeyD = "20643"
6 K; H; d4 p& S. Y; a+ ^LngKeyN = "29893" 6 f8 C( _. @- D; X" |2 q) ]$ w. t
StrMessage = Message * i) K9 F7 s+ P/ W
Set ObjRSA = New clsRSA & ?$ w* M b7 _0 K/ \7 c2 X
ObjRSA.PrivateKey =LngKeyD # X4 R8 [! m7 g6 z l! T
ObjRSA.Modulus=LngKeyN
- |/ ?' G. {- \( j' z. Y( k5 @' qdecryptstr=ObjRSA.Decode(StrMessage) 3 {+ n& @0 [4 v. w" U
Set ObjRSA = Nothing
& P# J* d! m9 ` Vend function ; w) J! ~% M- b! a9 c& J
%>
! }* u3 P+ a; {$ p$ E3 o. y. S===============================================
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还有一个用于测试这段代码的test.asp
2 r4 C, o) @' R" m有兴趣的自己搭建个IIS测试下
6 e" M, [( q) }* b" _3 \2 e" C<!--#INCLUDE FILE="RSA.asp"--> 5 t6 s8 Q& c4 Q) s
<%% s8 b/ y, m& A
function Encryptstr(Message)
+ @/ `4 j; E1 a7 `$ W$ z9 cDim LngKeyE
4 Y, A- d- R; y! y: M( zDim LngKeyD 6 |. n: V. m1 V0 P$ r
Dim LngKeyN
! b" ]& \5 O2 xDim StrMessage
! O. v5 A; ^' w- Q5 \2 oDim ObjRSA K n% h3 R' T! {5 n3 {* B3 N- c2 f f
LngKeyE = "32823" T6 {8 M! t! B
LngKeyD = "20643" 2 z! I0 B+ H' q% B
LngKeyN = "29893" $ ~6 S) f6 Q" Z, K
StrMessage = Message
3 s; T5 j- ^ M/ }Set ObjRSA = New clsRSA
) e, G# _7 g; `( D3 iObjRSA.PublicKey = LngKeyE 6 c9 U7 l% }2 S$ S" e/ t; X7 h
ObjRSA.Modulus = LngKeyN
7 S* X: v7 ]. `7 N% m. O. nEncryptstr = ObjRSA.Encode(StrMessage) " B8 }. r( Z+ \: u
Set ObjRSA = Nothing
. F3 c" _0 G. i, v5 t" n, X0 N8 Yend function ; ~! o* }! A2 q5 z, m
function decryptstr(Message)
* l& Q: A! W e4 qDim LngKeyE : D* X8 e1 L: L3 q- c8 b
Dim LngKeyD
0 [ w2 D5 ~# t4 Y# {* ]Dim LngKeyN Z; ~- Z3 L0 @% `( k
Dim StrMessage
' ^6 R& y7 F5 K2 r3 t+ K, P" pDim ObjRSA , ]; J5 y- e, F |% N5 z& t
LngKeyE = "32823" / @7 F7 ^% F! Z; z% n, I6 ]
LngKeyD = "20643"
& ?. G. ]2 M/ P* p2 wLngKeyN = "29893" 9 c% b& c0 ~# [6 b3 Q; I+ H
StrMessage = Message
1 v2 O* E# M: g! Y! @# PSet ObjRSA = New clsRSA
. m, a2 M. {1 w KObjRSA.PrivateKey =LngKeyD 9 C5 C9 e; V. p, c6 j
ObjRSA.Modulus=LngKeyN ' A! A6 ^8 Z* d& V/ v! ?
decryptstr=ObjRSA.Decode(StrMessage) 1 n1 V" }# W6 @6 m% C G
Set ObjRSA = Nothing 6 V1 w1 E( s L$ J$ ]% g
end function
8 {! W, U |- g. gdim last,first
) Q8 f* z- b" I/ |8 j1 }# |: _; Vfirst="!@#$%^&*()" 7 P7 U( O1 _' X. d
Response.Write "加密前为:"&first
( q3 o! n3 Z8 L1 Slast=Encryptstr(first)
" S" a i9 b8 M# A+ KResponse.Write "加密后为"&last : u6 d, o/ @9 T% ]2 D
Response.Write "解密后为" &decryptstr(last)
- t9 a& r5 p$ r5 B! U%> ==============================================
$ D2 j+ k$ Q! d4 c" s2 B/ O剩下的就是字符的对照表了, F5 @" Q* J) R& }/ S
===================字符集================
6 h& G* K$ u! ?5 J0 m1_____6EBB) L+ X% U7 u, j
2_____5C1F4 Y( r" k7 T% ~0 U# C
3_____4D75 h0 k: S6 b* L; E1 t" l
4_____26CC
3 Y9 {# j; H* z I- K: i5_____4F88
- I! g* q2 _' h P6_____3F4E' d; X4 E( }( w$ t
7_____0A9D' O1 w, q; e8 b
8_____1A1C! {. J, \" Q% U
9_____6D20
: z0 x" ?8 g" W" q0_____1089
# z/ o+ S) m5 [9 a7 ea_____0F3E8 j' }# g$ S N1 @2 t4 n! i
b_____3159
) w: C, v, O. ]7 q1 ?$ _c_____3517
. F: ?1 L* `: {$ d; \4 ed_____419C
- e1 P' e" n. h7 y& W8 M8 f T2 i" me_____615C
: K. i4 t+ t9 t3 f* _. `f_____556F
$ v. @; j4 Q. sg_____2B7F0 x# D& y: v/ o+ |; H
h_____0F9C8 q) @6 T4 L! O: q$ c) V
i_____00FA
4 Q1 m2 F1 H" R' X6 H- Aj_____5A50
/ a) a4 G- S) ak_____28505 E! d7 i+ |) o1 ?& r% e
l_____3E7B
' R. c: l+ w) a! Tm_____71C5
& s' A! B- R0 k$ l! Fn_____1FC8
, I2 X! u; [- _1 l1 a1 Co_____74C1
/ [8 J8 L2 q0 j+ ^2 w& D4 t4 yp_____5FB8
8 f! w4 ]; y( Z9 J n, eq_____6085& s9 v; x) {5 k }7 X( s
r_____3AC45 n- R$ x: H2 _+ j- d! p
s_____2F50
; G/ [4 _$ p- o) R, T' Tt_____36F8" h& Y; C; l1 p
u_____7010
2 b$ `7 i) q9 R) q8 K- av_____0B42- C& u$ v5 B. h) H y( u
w_____1C7A4 D# D. K' x8 ?" h- x9 @6 t
x_____16F83 {) R- \5 n; Q- K/ l8 i
y_____2EE74 P9 L3 m" _. r0 Q, D7 Q
z_____5CF3: D E5 V% U @; u: O# A+ A
!_____6233* o* ]5 a" u' M
@_____3A457 H1 G6 X5 W! M. ?$ Z
#_____22916 Q0 O( J& T7 T7 }
$_____5D5C* \3 G# p8 U7 n
%_____09B9
- Y, |$ @' h6 E# e; D^_____43EA
; ~# ^. P' o) l5 R; u&_____62B95 S1 B9 o* ~* }
*_____6301& G( |; T, H1 s' X5 e5 n
(_____4659
5 l6 w/ U+ H4 S)_____5C82 |
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