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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm6 b, K r# E$ O& F
原始出处:http://www.3ast.com.cm. I+ q2 I; O9 U( {) ^ s7 _
& ]& b1 \/ _3 b8 n
看不懂的直接绕过; d* F9 M6 r# h1 ~2 u0 I
加密前为:hwy1234560 ~/ b& Q+ ~) N- B9 z b
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E. Y0 b6 F3 w: C5 z' O% i
; b6 G; K- p6 N1 U4 u
============================================
5 b/ y4 R# l* Z8 F' ? p$ _4 C上面是当时自己校内的心情。现在已经解破出来了,分享给大家+ l( X7 [' V! M2 F0 f
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
8 V# _# A9 [7 l以下是RSA算法文件' P- ]$ ~' h1 }5 U
6 X7 P" V! U* Y. j文件名RSA.ASP
7 M1 Z k' `. j( z& T3 _4 A7 j===============================================
; G- {6 {0 P$ ^0 ~4 t* s A<%
. @6 x4 t/ P) `# vClass clsRSA
2 n# n" A: ^) o$ I+ y( ~; u/ d! YPublic PrivateKey , \$ `+ E1 n8 l" x# d6 w1 x/ c
Public PublicKey 8 R+ l+ H1 E9 h) ]9 o- Q
Public Modulus 8 @% B" A7 w2 ^$ a% D
Public Function Crypt(pLngMessage, pLngKey)
2 N, J0 h* p7 z& e6 X; [ U3 @, NOn Error Resume Next ' r' W- X- b- D9 B/ _
Dim lLngMod + ^: r7 C! a6 J7 F0 ]6 Q
Dim lLngResult ) i k+ X/ H& k9 C, h {
Dim lLngIndex ) I, `& n6 n0 ]
If pLngKey Mod 2 = 0 Then % _9 I- I/ `0 V4 F* X
lLngResult = 1 . U% O5 k0 U M {* y: G; J
For lLngIndex = 1 To pLngKey / 2
$ G% k& \7 @7 N3 w0 O. f9 SlLngMod = (pLngMessage ^ 2) Mod Modulus , f; G* X [& R; F( W& @+ z \
' Mod may error on key generation / U0 K8 A5 X, R1 P+ k: G9 n
lLngResult = (lLngMod * lLngResult) Mod Modulus
& ^2 o& c( r& v" H. wIf Err Then Exit Function
2 |; [8 G7 @. z. X3 {! h* ENext : @9 ?9 S; M! |5 \% F
Else
2 J A5 G$ g7 H9 Q4 E6 plLngResult = pLngMessage " W4 M4 d% Z' U8 `) x
For lLngIndex = 1 To pLngKey / 2
( b9 F0 B* \7 F+ ^) @lLngMod = (pLngMessage ^ 2) Mod Modulus
, \2 D+ g: ?% Y+ COn Error Resume Next
5 K: _1 a+ ~" @& T' Mod may error on key generation
/ v5 {6 d. D' H8 I' e3 f* ~lLngResult = (lLngMod * lLngResult) Mod Modulus
8 b9 y% s0 x4 a" J! PIf Err Then Exit Function
5 S, ]" X6 K( e5 m2 f, G0 @Next
W2 A. X' |/ n- }# D* o. TEnd If % m) u1 d0 k. c# U' i5 f% Y: X& Y7 A# B) @
Crypt = lLngResult
+ z; J3 V5 I% h$ cEnd Function
# c, @' j" b" }" R& u5 `6 n+ R3 Z
Public Function Encode(ByVal pStrMessage)
9 F* y) |+ d8 X6 Q) l" @6 W+ QDim lLngIndex
- c5 n6 \* S: q6 [' p9 s' RDim lLngMaxIndex ( L0 Y* }1 u$ h0 k/ P A
Dim lBytAscii $ x- d; B* j" y* y5 M6 ?3 p% q
Dim lLngEncrypted
1 k- |6 H8 I+ f: X' i6 z0 J/ PlLngMaxIndex = Len(pStrMessage) ! G2 i' [4 E3 U) e4 ^) F. `
If lLngMaxIndex = 0 Then Exit Function
/ U( [. l: _9 Z) c" W. S* |5 @For lLngIndex = 1 To lLngMaxIndex
9 _; K, M; s8 S2 [lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
/ C, S4 z9 _- Z1 v R! zlLngEncrypted = Crypt(lBytAscii, PublicKey) . D5 r: b' u. t
Encode = Encode & NumberToHex(lLngEncrypted, 4) - i# A/ H; M( H: h, f5 }( i
Next
; T' N2 O5 X. v) d0 @* w! r1 JEnd Function / q: X$ v6 i" e/ x
Public Function Decode(ByVal pStrMessage) - F; U% | B u1 o& c
Dim lBytAscii
$ w H2 h$ a: @( ~, KDim lLngIndex $ h5 ^# j- [0 l, ]
Dim lLngMaxIndex 9 i3 |8 F. Z& H( \$ u7 Z4 D- Q3 K
Dim lLngEncryptedData
! C. c# ~3 D S% @5 b- P+ Q. iDecode = ""
/ j9 h# A2 `; H0 A/ plLngMaxIndex = Len(pStrMessage) , o5 k! s* Y! Y8 ^5 l; p' b z
For lLngIndex = 1 To lLngMaxIndex Step 4
: t1 }. A3 s j& u* E% x9 M# ?- r: zlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) , R: Y$ x, s% h8 ~" V1 |
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) 3 y, L3 K+ A4 q3 X
Decode = Decode & Chr(lBytAscii)
. K n' n9 g. e& b# t: `* `2 v1 aNext
' x% I$ U# w8 v8 _9 {0 U4 ]End Function $ }0 m0 s# v& v- u; |
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 6 \6 ]6 J" m$ v7 v
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
4 l! @2 J# G- R+ ]End Function
4 H+ C4 s( y; Z: i. M* Q0 ^Private Function HexToNumber(ByRef pStrHex)
2 {( Z( F/ Q# |* W' F1 kHexToNumber = CLng("&h" & pStrHex) ( h/ t0 w* M/ d: r
End Function
' z, N; D! R* k% rEnd Class ) S5 z* \" u$ ^2 t2 p! F
function Encryptstr(Message)
D1 \5 F9 r X1 p9 tDim LngKeyE
& r, k1 R* W$ N. l2 U5 oDim LngKeyD 6 H, R9 c w& l5 D
Dim LngKeyN ! B$ s$ p3 Q! f* v2 a
Dim StrMessage $ x( @7 a" T+ H; q0 {, `
Dim ObjRSA
9 V/ e% m& F, s! h, ]LngKeyE = "32823" - i Z6 S; ?4 H. F |' U' M. d: m0 {
LngKeyD = "20643"
8 w) U. |7 T1 P8 J. [LngKeyN = "29893" % c: Q/ X4 C0 F7 {
StrMessage = Message
1 ~: B1 D a# c" }, `Set ObjRSA = New clsRSA ; h. E% W& i6 A0 `* |" l5 S: l) z
ObjRSA.PublicKey = LngKeyE & |" m+ c( m, g# P* |
ObjRSA.Modulus = LngKeyN 3 j9 l7 y0 s& L0 J1 t% y$ {8 ]( p$ @
Encryptstr = ObjRSA.Encode(StrMessage)
( r- r4 [, i3 O* f' ]Set ObjRSA = Nothing
V) g: o- j2 K* hend function2 T5 D" F0 R5 Q+ t2 H
Function Decryptstr(Message) : A$ S9 J& _# v- x7 b, g; b
Dim LngKeyE 2 C, n e& J& l! i$ ?- O3 j4 o
Dim LngKeyD
; r1 ~' r8 b, _, i- |; ^& }Dim LngKeyN 1 S3 C$ C2 q' v0 i
Dim StrMessage
3 V/ c) m2 t, i4 w0 m0 ~: NDim ObjRSA
0 W9 t8 H: D$ H8 A% P2 J, p lLngKeyE = "32823"
. M, }" U7 U- \LngKeyD = "20643" , {: a' Q# }, M
LngKeyN = "29893" $ X( T# d+ l0 J+ n: |1 g% F
StrMessage = Message ! Y; t1 G# S$ e8 @2 t
Set ObjRSA = New clsRSA
7 W' e3 E2 c% G$ U/ e% {% T0 ]! y8 ]ObjRSA.PrivateKey =LngKeyD 2 ?, ]9 ?) l' t& l) u3 G
ObjRSA.Modulus=LngKeyN
- Z( e2 D/ ~( mdecryptstr=ObjRSA.Decode(StrMessage) 1 l- S: O- g) ^
Set ObjRSA = Nothing
/ _6 i5 e- Q: j0 x: k1 h6 wend function
2 E7 S j+ o. E9 t+ U. {5 z9 J9 W%>. G& ^* o( @5 W
===============================================
) q8 Z7 C, a& ^- h# s; B# V: f
* u' {4 P: V( c/ X; n还有一个用于测试这段代码的test.asp! K9 s) q$ A& `/ h. {: A
有兴趣的自己搭建个IIS测试下. h% F& V: y. `: n; e
<!--#INCLUDE FILE="RSA.asp"-->
# s$ R5 i/ a0 m<%( E" } o; G5 k( X
function Encryptstr(Message)
0 r W9 e- G1 Z9 h4 u5 i& a/ rDim LngKeyE
- @* o, P& X+ V" iDim LngKeyD 0 S; @& N+ T5 K2 T
Dim LngKeyN 6 g& ~% O$ W) y# d0 s2 ^' m
Dim StrMessage 8 j$ m: E. f% J- Z: ^5 M
Dim ObjRSA * ~8 @4 j6 i, G7 p ]3 m; q
LngKeyE = "32823" $ J2 @+ _3 {. k& d8 e! V$ b$ a
LngKeyD = "20643" ( \& K2 M7 n% Q9 g* \( I
LngKeyN = "29893" ' p/ P+ R" z: U0 m0 Y# Y% K
StrMessage = Message
8 M7 a, W+ c& q& {- ~8 ESet ObjRSA = New clsRSA " J( A+ f4 m- L! Q& d+ U o# H
ObjRSA.PublicKey = LngKeyE
~, o: K z. c; { {ObjRSA.Modulus = LngKeyN
" V+ r( c' u% ^' V5 CEncryptstr = ObjRSA.Encode(StrMessage)
! i. h# W9 \, o- cSet ObjRSA = Nothing ( T9 l& F9 B( y2 P1 p
end function ; h5 p5 _5 H) |% o, `
function decryptstr(Message) 5 k8 H* ]( D, C, v! H% I2 E- [
Dim LngKeyE
; Q/ `) i7 z! ]- A1 wDim LngKeyD 7 C! C3 h$ B; ], C0 Z$ Z
Dim LngKeyN / ^, r5 }% R) G" I( q
Dim StrMessage
]) }. L) _5 X7 t% ^& z0 O) aDim ObjRSA 3 n$ x% r! I i; C% W# n% {
LngKeyE = "32823"
& W1 ~9 T) A1 K1 SLngKeyD = "20643"
' |; t) Q& O" J. s A: bLngKeyN = "29893"
# }" {7 x, _& M2 WStrMessage = Message / Q$ l+ z3 n5 o `4 }0 k& _7 y! u
Set ObjRSA = New clsRSA 1 r1 t$ ^+ J0 ?# C8 k
ObjRSA.PrivateKey =LngKeyD
( _& h( ~& [7 z/ G, ]$ s. p) X- `ObjRSA.Modulus=LngKeyN 7 M- N5 {) v5 d
decryptstr=ObjRSA.Decode(StrMessage) % r) ]5 [ g! A8 l9 a$ R8 ^" ?5 p* f( ~
Set ObjRSA = Nothing 8 O1 n! ]" r( V3 ~1 W
end function ) {% N, t( g2 n6 |5 ~% R0 j
dim last,first
& @5 m" Q a% I2 ~# ]* ?- nfirst="!@#$%^&*()"
) G) D. g' H6 F6 L ZResponse.Write "加密前为:"&first
& v- g- \2 p' l8 H$ {5 Y$ `last=Encryptstr(first)
6 I8 s9 Z! y2 \% ?Response.Write "加密后为"&last
0 ^1 g0 O2 L- Y w g" q% GResponse.Write "解密后为" &decryptstr(last) & q3 ~$ n$ F; n$ m9 w' ~# w' L& s
%> ==============================================
9 \7 S2 S# }7 I, F/ j剩下的就是字符的对照表了6 ]1 q6 u. u% `) p
===================字符集================
6 \. a: g# Z- A I& a1_____6EBB) {# ^+ T3 X. x8 p: C
2_____5C1F
! i2 q$ d4 V' q* u$ {( j3_____4D75
( U. j1 e- N) c% n! ~7 B2 S4_____26CC8 ]$ f9 N; [4 ?$ T; E
5_____4F88
, p, R4 G1 Q4 |4 V; C+ l* I6_____3F4E
$ k' j" D- `6 ?% A, b z. d7_____0A9D5 J; x$ N: D0 H
8_____1A1C0 Z( ? W5 h7 @5 F6 R# ~7 ^8 a
9_____6D20& T* w( J" `) J7 \/ g! w
0_____1089
- t/ z4 `1 L0 ~7 X2 v" @1 ]5 Ba_____0F3E3 k8 ]5 Z8 I! |
b_____3159
' V' O# P" m. h- a9 @2 C/ I( `c_____3517
9 R6 k! b1 m0 f. Td_____419C
' C; ^2 J+ R U! ?e_____615C
/ k/ ?% s/ e7 }, Bf_____556F% T0 l+ \2 y$ G
g_____2B7F2 s0 l: f1 j5 n# i& v4 ]6 B& V
h_____0F9C
0 J8 G" K, K! n, e2 {' vi_____00FA
; b8 h( X5 h4 v0 q: z& Yj_____5A50
) ]: t" k5 [8 g3 A3 G. Lk_____2850
- [: y: g/ Y: ~1 D5 O" s0 ml_____3E7B
7 z5 W7 ?+ Y; }8 }2 ^m_____71C5* d' ~" l: o% R& D) d- C S
n_____1FC8! o# h6 x# L* d4 q
o_____74C1
* I% S; z2 U6 A3 y" i7 o) J$ sp_____5FB8* }3 x6 D& N ]3 {
q_____6085# z6 G& e0 i( {) _+ ]1 y% `
r_____3AC4
9 k+ P; @3 t, }* I ~s_____2F50( L0 S T+ i$ F/ {$ J0 w) e0 q
t_____36F8/ S& M% \! z/ i) ~( u% y
u_____7010, ^! G9 y7 @2 P8 M+ \
v_____0B42
1 B- M! ?, h9 {% p. |8 \8 mw_____1C7A
2 Z1 L4 k1 h9 D% g, q: n1 ~x_____16F8% u# k$ D# z/ n( t* l) M Q
y_____2EE7
, Q T9 A3 m9 w8 B$ A" X; l( x* Ez_____5CF3/ j( n9 s8 o* z+ s5 N1 z" Q
!_____6233( ?! J; p0 C1 z8 d
@_____3A45
& ~, g9 L9 w, `8 g( i1 d' Y- O#_____2291; y+ `0 H- z& F1 m0 K6 g( X
$_____5D5C" d" S. W, f4 X( I
%_____09B9
* n$ b. H7 l+ r^_____43EA
9 V. X5 ?! A$ g( k, a8 L&_____62B95 J! F; W1 o& n8 J5 R
*_____6301
2 I: w$ Q( [) N5 a(_____4659
; _4 F3 u! A" z! s7 L1 W, K1 Z9 G)_____5C82 |
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