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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm# e9 [5 i* T( P- b& x9 F
原始出处:http://www.3ast.com.cm
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看不懂的直接绕过, w8 d" S# B5 S, Z% g
加密前为:hwy123456& }+ X" c" b2 x$ N
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
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============================================ z" e5 b9 V/ u
上面是当时自己校内的心情。现在已经解破出来了,分享给大家 {- q" } D4 Z5 @2 h9 }: W
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
7 o, H2 S8 X- K以下是RSA算法文件1 T& G' C3 m. z8 O1 o6 }9 E
( N" w3 w3 S5 W7 H文件名RSA.ASP
# \1 [) [6 b1 @/ P5 r& B===============================================
4 U7 A, D! K6 C) Z<% . m. k+ @9 V: E( p3 K3 S) s
Class clsRSA " W/ c% W o- u M* C
Public PrivateKey
E0 l2 [2 | T# L2 A( _Public PublicKey : c& }8 T# R" n, t0 a
Public Modulus : z3 E3 G0 i9 Y+ c1 r7 V6 F
Public Function Crypt(pLngMessage, pLngKey) 6 Z L4 F4 l& B- B
On Error Resume Next
4 L( [, o2 Y! Y, RDim lLngMod
! ?/ [% R5 w7 x( W! FDim lLngResult u( b7 E" u% j6 @9 ]) q, e/ `) G# V
Dim lLngIndex 3 C. v% k8 n2 w. d. s+ x
If pLngKey Mod 2 = 0 Then
5 [9 Q# E0 Q5 _0 E, I" PlLngResult = 1
5 c) ~. ^( i* `" b) {5 A1 L( z+ SFor lLngIndex = 1 To pLngKey / 2
2 X( Z/ j2 [% h# klLngMod = (pLngMessage ^ 2) Mod Modulus 7 g% Y1 Y8 B' n0 f J& `
' Mod may error on key generation $ G& u) |) |# d) @2 C7 ^
lLngResult = (lLngMod * lLngResult) Mod Modulus
$ {8 [6 x. s$ Y5 nIf Err Then Exit Function
Y# y1 r' g# [6 {0 ]9 P0 gNext
/ Y8 z: h( |$ H+ y0 TElse
- X) g) e. |5 G0 Q6 M% KlLngResult = pLngMessage + E1 ]6 C+ R2 j9 J
For lLngIndex = 1 To pLngKey / 2 , j, b) `. J+ G( F) f4 Q% v6 y6 @
lLngMod = (pLngMessage ^ 2) Mod Modulus 0 N* r' f/ z$ ~4 x: j
On Error Resume Next
. }; b- g- G8 i/ e' Mod may error on key generation
3 b9 a9 C$ [) l5 b4 _lLngResult = (lLngMod * lLngResult) Mod Modulus
$ ]. k6 ?( I& R) `3 O) R) U2 z! \If Err Then Exit Function 7 [0 p7 |) W, g% B
Next * y! R: ^& u1 r4 s) J) S* ]* h6 ~: \
End If
3 p' I2 R8 o- k4 w1 f/ v" uCrypt = lLngResult
) `* Z4 k7 d; V5 {End Function) c/ X h# J# Z
( p1 m, r4 Y/ @5 M# i8 G9 uPublic Function Encode(ByVal pStrMessage)
" c9 A0 ?) Q# |4 v( uDim lLngIndex
: O7 c% q1 k2 m) eDim lLngMaxIndex
) g# |9 j8 C4 C/ f' \+ i4 |: `Dim lBytAscii
6 @( |/ i* o! H* K0 x* ~9 pDim lLngEncrypted
% T* C. P$ }$ E' Y0 I5 FlLngMaxIndex = Len(pStrMessage)
/ O3 g1 G; K- T1 A( lIf lLngMaxIndex = 0 Then Exit Function
9 V( Y. C# i d9 p; y9 oFor lLngIndex = 1 To lLngMaxIndex 8 w5 K7 i- T% V. v) I0 B9 Q
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) * C' w9 ~" p$ E. s! P7 Q5 y
lLngEncrypted = Crypt(lBytAscii, PublicKey)
$ e6 K4 t! l8 ^ t+ M+ PEncode = Encode & NumberToHex(lLngEncrypted, 4)
; t9 S! F {, o/ |( nNext
: `3 x+ T E2 A; n6 e GEnd Function $ i+ A, A3 R$ R. v5 L6 M
Public Function Decode(ByVal pStrMessage)
Y7 i: D& P ^1 S! kDim lBytAscii
$ D; a* L1 y0 M3 p1 ?7 ODim lLngIndex
2 y! L, i4 s- I$ C1 _3 EDim lLngMaxIndex . F- m+ c+ r0 W# [
Dim lLngEncryptedData 2 ^: y& `2 W) r; r# Y5 T7 u
Decode = ""
- _7 B/ V8 P9 k5 l9 p- e+ BlLngMaxIndex = Len(pStrMessage)
9 I- E, I, f; {1 YFor lLngIndex = 1 To lLngMaxIndex Step 4 8 b" T# [) W$ C5 U4 A8 b
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
3 ?- p8 G' l0 S2 H* F! vlBytAscii = Crypt(lLngEncryptedData, PrivateKey)
9 p; g N! V( B# G4 tDecode = Decode & Chr(lBytAscii) $ F# X) @7 N2 C5 Y
Next
x0 @' z7 C8 F. T! Y$ w' F5 r! nEnd Function 2 U! Z% D l; X5 n
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
/ u6 y: b: V7 y: pNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
0 u" H6 ^6 }# }$ kEnd Function
- }) z9 Q. x5 HPrivate Function HexToNumber(ByRef pStrHex)
. H6 n! t5 G( jHexToNumber = CLng("&h" & pStrHex) l5 \! F {( U/ T7 ~
End Function
9 [' y$ [ g( M3 ]* ^) y$ J8 KEnd Class . D k. d! G; X# y7 A. [
function Encryptstr(Message) v& U: g% Y- D% h w; P# U1 U- ^* X
Dim LngKeyE
# v$ h: g9 w, ]Dim LngKeyD
/ y, [* q1 n* ~, ^Dim LngKeyN " y; u* @, g8 e4 J& X5 n2 q
Dim StrMessage
1 @( x2 A6 B5 U. |( tDim ObjRSA
2 g4 ]! [0 n; E6 Y% T0 Y& Z8 }LngKeyE = "32823" 7 j/ V% d# w1 f$ b# Q& ]+ S
LngKeyD = "20643" 6 ^: v: l3 Q, @6 b y
LngKeyN = "29893" ) s# H0 ]) a8 C+ M3 f
StrMessage = Message
0 ~7 b; n% c2 S% u% Q1 {' uSet ObjRSA = New clsRSA
8 b+ L& Z' p1 P( k* H9 _ObjRSA.PublicKey = LngKeyE
2 H) p( `4 |3 X1 ~( }# WObjRSA.Modulus = LngKeyN 3 T3 ~2 ~* J0 u
Encryptstr = ObjRSA.Encode(StrMessage) ; h2 _& z" L @# v+ q
Set ObjRSA = Nothing
( `; |; W3 ]" D; D' Q8 Send function+ ^6 t6 y8 a3 E5 |0 o+ m g
Function Decryptstr(Message) 5 \! @! V- ]; w4 T; Q/ L! i; p
Dim LngKeyE
- P& Z6 i A3 t6 r, h, G! v2 YDim LngKeyD
; _4 V- x9 B' A4 n3 @& qDim LngKeyN # ^# Q& ]8 w" m6 j3 v$ x7 {
Dim StrMessage
7 n `- n" O6 L9 n6 s9 I5 j- g! kDim ObjRSA
% q# k; M' m3 O0 ZLngKeyE = "32823" 2 h- r# w! v$ w" J+ H
LngKeyD = "20643" 7 \$ M( p+ G6 h) j% D9 O7 H
LngKeyN = "29893" 4 b% L* n& y+ V! ~- P
StrMessage = Message
% ]8 [3 h! \4 S/ @7 }; S5 ]$ QSet ObjRSA = New clsRSA % O! m: ]( r4 Y& I2 K- d% a1 \
ObjRSA.PrivateKey =LngKeyD / j% Q/ \4 p# Y9 ?
ObjRSA.Modulus=LngKeyN & {# E; V: ?6 c( y2 o' k- J
decryptstr=ObjRSA.Decode(StrMessage) 6 o' M) Q0 E8 F& ~
Set ObjRSA = Nothing 0 `2 C0 E( }) m- H. ?2 p& n
end function + u5 Y: e H, R$ o0 H
%>
' a# @& w( M; b; {===============================================
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还有一个用于测试这段代码的test.asp6 ^6 s s. M& V$ p
有兴趣的自己搭建个IIS测试下! r) }0 _ i, ?
<!--#INCLUDE FILE="RSA.asp"--> % p7 e3 h* o/ D& }5 o: Q" |. w
<%
# Y6 h7 Z$ u2 Q( M2 L' i) @8 w; Pfunction Encryptstr(Message)
1 n9 R% ?: R3 ^8 @: K9 QDim LngKeyE : w8 o$ }4 b1 \
Dim LngKeyD
: \% v3 [: @/ b# w: d6 iDim LngKeyN }+ E& T/ u, X$ u: U$ v
Dim StrMessage
. P; M( e- v; iDim ObjRSA ! Z* F! R# c# D: Y C
LngKeyE = "32823" ( }7 D. h0 ~7 F5 _6 s& S: Q, @, r
LngKeyD = "20643"
( B) r/ |* L( w$ u! N; lLngKeyN = "29893"
7 t t/ f! {) w, b: U. XStrMessage = Message + t( q, t; R% T/ m0 z
Set ObjRSA = New clsRSA
+ q5 w7 n# c+ k8 a: Q6 j% S$ QObjRSA.PublicKey = LngKeyE
; G$ W9 U ?; f$ N `" ^. z' oObjRSA.Modulus = LngKeyN 5 H6 S. N0 A* S# B6 N# F
Encryptstr = ObjRSA.Encode(StrMessage) ( i4 G" |0 [9 C% R f3 b- e3 @
Set ObjRSA = Nothing
8 z9 u0 `1 |2 v* s' D: k! q$ g6 Fend function
% ^6 [; s. g t, @- y9 E' Hfunction decryptstr(Message) " m$ I3 z% P3 L3 ~+ }" {2 y# s
Dim LngKeyE 1 q G, m- ` H! V! y1 b/ P8 y' }! B
Dim LngKeyD ) R. J/ C" \/ q0 a
Dim LngKeyN
7 D% E1 l6 X9 ?% uDim StrMessage
+ |. {# B' R3 i! X4 V- G/ [Dim ObjRSA
" t( d* X' X, \9 w5 X; w4 h F( HLngKeyE = "32823"
3 ]& f" |$ O w8 DLngKeyD = "20643"
) O6 ]' a+ K+ W# a2 z! s0 sLngKeyN = "29893"
, h+ P& X" A7 S" ]' Q. qStrMessage = Message $ e8 M- V1 {' O' l8 I) J6 `; {) Z- j6 Q
Set ObjRSA = New clsRSA
0 Q4 N2 g& n7 oObjRSA.PrivateKey =LngKeyD
" |/ u" s0 g( _& m4 g. ?ObjRSA.Modulus=LngKeyN
6 u& |5 d- M L% q9 Jdecryptstr=ObjRSA.Decode(StrMessage) ( ]/ B+ V4 |; p: j, T
Set ObjRSA = Nothing
( ?+ x3 A( V6 ~- r0 tend function 7 b, O' F5 A/ }8 d
dim last,first - \; h7 z( q; P* T' i
first="!@#$%^&*()"
/ S A5 z! ?) H7 o; m L oResponse.Write "加密前为:"&first n; f2 G" Q; j# s9 _4 G `0 Y7 b' r
last=Encryptstr(first) 8 c( ?/ h% W, w& U/ `: N. G, p/ I
Response.Write "加密后为"&last
. f" W' \' V7 f3 J5 DResponse.Write "解密后为" &decryptstr(last)
7 p5 Z" Q9 O# g) H+ v U%> ==============================================
% G4 i- y! l' Z6 j8 G剩下的就是字符的对照表了
/ x4 N/ |0 M6 Z" \===================字符集================
+ m6 M: O3 y5 w' J3 O1_____6EBB
8 M4 Q. l v3 i" I2_____5C1F
' _3 F% o F' w; H+ B3_____4D75 F }, z0 i- s' F8 z( ^6 l) I
4_____26CC
. C3 k3 Q( f- w& k* j) C6 D5_____4F88
2 F, ~& B! N+ q5 a6_____3F4E- o/ H0 {+ F* |( j# T$ `5 j. V6 A
7_____0A9D: r# ^. j- s! H; v5 Y
8_____1A1C* n/ E5 p' ^8 B3 j; v' \; d3 H
9_____6D20( X o5 n) l6 [3 ^+ b: @0 t
0_____1089
, L; G. S& l# B+ O$ n6 ~a_____0F3E" }3 \+ S8 _$ K$ g/ [' c% ?
b_____3159% b) i. _) X; F5 a/ V4 o" |
c_____3517( e& m3 s h( n. L4 }
d_____419C
0 Q% P* j0 ?# }e_____615C
2 S& {6 n2 M1 O8 I) D: Q0 ~f_____556F
5 t0 N+ K. f& {9 Zg_____2B7F
' o$ ]$ T- J4 M4 a. O5 u/ Mh_____0F9C: F3 T" i2 g7 F, y. E" g1 {
i_____00FA
4 y3 ]; k; I# s* A* G! n8 }) O. }j_____5A50
0 ?" t* _" V lk_____28509 @/ S6 o$ y( R+ r7 A7 Z2 }: o
l_____3E7B
9 |8 c) f. R: z7 Hm_____71C5
6 o/ E) H# u. l7 Tn_____1FC8
6 q7 p& `1 Y/ V q/ q, d' ~o_____74C1, H0 N& n/ _9 n+ c
p_____5FB8& }# e, M& h8 l+ Q5 x1 z
q_____6085 P0 i8 B) Q, B$ N& n$ Y
r_____3AC4
8 d1 s8 y+ q% H Q7 Cs_____2F50, B; ]$ x1 S( z6 P3 b5 A" V
t_____36F8
) [5 N9 q+ |! [4 H: fu_____70104 c" N9 |/ ?0 D+ B- ]: ?
v_____0B42
9 f0 z( ^, d! z* |3 vw_____1C7A
& D/ U% O" K5 L+ V$ j3 g/ ]# Kx_____16F8, @; U% l; i$ D2 p* n4 C: P' T
y_____2EE7
' i" d( j* e5 a$ @0 Ez_____5CF3
# M9 y4 L" O$ C a' |9 A( F!_____6233
. P5 J2 Q# c$ k/ W@_____3A45' @$ T7 n$ g3 N) U
#_____22910 Q; q) Z, ]! s0 @
$_____5D5C/ u' @& {) l/ x' c& s% w+ G
%_____09B9
$ k5 J& X4 X* ^& {7 R' J0 A^_____43EA: f9 { ]+ U# M9 m" V
&_____62B9
/ {9 F$ k7 ^3 k2 t*_____6301
+ Y$ M S/ M. ^# I+ x5 [(_____4659
; {0 r; f# Q3 G. i+ [)_____5C82 |
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