    
- 帖子
- 3852
- 积分
- 13044
- 威望
- 16780
- 金钱
- 36761
- 在线时间
- 1139 小时
         
|
原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm, J2 y0 B8 u3 ~( a
原始出处:http://www.3ast.com.cm( o' h3 l4 v! O# y" v5 q; `
* G2 J. e7 a0 T& f6 Y1 c" ]
看不懂的直接绕过
8 @" m% ?1 @ d2 l. |/ k1 r加密前为:hwy1234566 E5 O4 r9 K+ `$ @0 t
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
J+ }7 F3 p- ?& x& G
t [* X- J T/ q1 C============================================. B( \7 o7 S- q$ b9 ~# w
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
- G) Q4 H5 D N8 B也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
6 R( s! \$ M4 x' g- h Z( E以下是RSA算法文件+ T( k& X& }, l: t
- A, Z) r& k5 \" t! I: k
文件名RSA.ASP' k0 M' Q5 k4 s2 j. T9 S
===============================================1 T, {& B1 B- X5 X9 a! q: H
<% ) I0 j7 g" d# b8 r) h
Class clsRSA # p( i/ ^7 }- n4 {- _
Public PrivateKey
8 } L d: g& H# Y( [, @; \- ZPublic PublicKey % \$ u2 X: a+ {# p7 R0 b
Public Modulus
/ i& i" @/ m2 j& w2 H3 u* h* TPublic Function Crypt(pLngMessage, pLngKey)
1 ^1 g$ r( V2 x6 xOn Error Resume Next : z, A3 O; P5 `. {" t
Dim lLngMod 0 a$ g- x& M' u# G- k6 B4 f! f: G
Dim lLngResult
+ G' f8 }1 `4 U9 z GDim lLngIndex
; T2 k( X; E Q8 r- L6 ?If pLngKey Mod 2 = 0 Then
. L. A3 I! c. g# wlLngResult = 1
3 @: Y: f+ k! [0 O" LFor lLngIndex = 1 To pLngKey / 2
' `; ?9 m. _+ u1 k' UlLngMod = (pLngMessage ^ 2) Mod Modulus , ?! G1 ~. I: v2 n
' Mod may error on key generation
* ]5 z9 m8 f( glLngResult = (lLngMod * lLngResult) Mod Modulus
- ?4 ^/ h$ g9 y% aIf Err Then Exit Function $ }, c& `+ ~$ F; v( o
Next 2 L3 l' S6 J5 u. R! C1 T8 z
Else
9 j8 e! U, k# U+ e: alLngResult = pLngMessage
' \8 A1 j/ B5 e1 pFor lLngIndex = 1 To pLngKey / 2
9 a/ L! M; O$ B1 g. V1 F4 @$ A- ?lLngMod = (pLngMessage ^ 2) Mod Modulus
' I/ w; p. V! F/ uOn Error Resume Next
& p* b/ Q* W2 x* A' Mod may error on key generation
: P) B1 N6 Y; e0 Y3 C8 clLngResult = (lLngMod * lLngResult) Mod Modulus
$ b( a0 Y4 Z( M0 D! qIf Err Then Exit Function ) m1 ?1 E- v' _2 {6 |
Next 9 g# K* Q) B3 M( O+ H
End If 3 l2 i T2 Q, f7 R4 r4 m j
Crypt = lLngResult
+ n" \9 T# c7 c4 ]( rEnd Function+ S! ]- D, @" T6 {' n% P" X
4 |( ^0 N, z3 @3 `: T# vPublic Function Encode(ByVal pStrMessage)
6 ^! Y4 B2 j# o: U7 CDim lLngIndex 0 V$ h# R; {1 g _( z0 U+ i4 ?. Q( u
Dim lLngMaxIndex
& T5 }9 }' ~4 a% O# ^# n1 N# pDim lBytAscii
( d$ U) n/ I) J4 s! x3 _2 r% VDim lLngEncrypted
& {5 ^# I( q' N9 v% \4 t" D3 ]1 I# klLngMaxIndex = Len(pStrMessage) 5 |! C! p. b; ~; t0 t" \1 \
If lLngMaxIndex = 0 Then Exit Function
0 q9 l. }& H( Y5 I3 Q3 rFor lLngIndex = 1 To lLngMaxIndex
7 t \; Y0 L8 g" k7 W3 T8 ClBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) : b& B3 z7 T2 K! l
lLngEncrypted = Crypt(lBytAscii, PublicKey) * U/ j* ]7 j) l3 n6 c
Encode = Encode & NumberToHex(lLngEncrypted, 4)
2 k# x" m0 B6 l8 G- U- XNext
# ]( {4 Z0 ~, x% T' Y) mEnd Function
: G" Q# }3 u5 Z0 u+ s6 H! F. f GPublic Function Decode(ByVal pStrMessage)
2 _" o. ?9 Y( q6 r$ Y6 NDim lBytAscii
( ~; h+ F9 D$ g% P8 _! b; w* {Dim lLngIndex
8 A) O$ [' @( W. v8 jDim lLngMaxIndex
# k% q* ~& t$ lDim lLngEncryptedData 2 s% Y: V8 V+ Y; ]: J& M t/ i1 t
Decode = ""
0 W# ^/ O: I1 A) SlLngMaxIndex = Len(pStrMessage)
% w- e+ t! T9 {/ }0 M+ N) I. q8 ~For lLngIndex = 1 To lLngMaxIndex Step 4 : `& j' e) j8 R$ ^+ p! z( Q# o
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) - J, C) W0 G# u5 F) K; _
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) 6 p5 e. E4 L: I5 K" {+ x& Y0 E
Decode = Decode & Chr(lBytAscii)
4 B+ R6 J: {1 u8 }. {# D+ ENext
- J( h, w3 O& G$ M( DEnd Function , c8 h* s% Q3 ^* m% V7 h
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 8 y- w+ N$ t+ \5 L
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
y8 u6 O3 h$ [5 iEnd Function ! @% E: I2 m. M3 m0 |* w0 m, ~
Private Function HexToNumber(ByRef pStrHex)
+ R* @* _8 l6 c6 Y! R7 s2 pHexToNumber = CLng("&h" & pStrHex) * I4 h4 n% w9 S. O. P5 g
End Function
$ r5 p; p: m) e, r' q. [End Class 6 P+ c2 ]1 f: Q- r! o5 o" ?
function Encryptstr(Message) 6 e" }& H( x1 i7 E5 c) m3 \
Dim LngKeyE 9 E, t% r8 N% T
Dim LngKeyD
; {( o3 m% ]# R9 O5 Z. WDim LngKeyN 8 C6 Z8 N0 B& E
Dim StrMessage
% g( b6 [1 ~9 i4 U0 cDim ObjRSA g5 n' E; k# h
LngKeyE = "32823" / r! s' |4 T9 K! X/ b( \
LngKeyD = "20643"
( ]( y9 u' s/ z5 u3 i. f$ tLngKeyN = "29893"
" O# f5 a8 t8 n9 M! s1 s- KStrMessage = Message 8 D' f- E1 N/ t' G1 f
Set ObjRSA = New clsRSA " S' K9 ^% k2 k6 j. k1 A! K% S2 R
ObjRSA.PublicKey = LngKeyE : e: E) N4 v2 g
ObjRSA.Modulus = LngKeyN
7 B+ D: J% F# z1 R) E6 G6 f7 lEncryptstr = ObjRSA.Encode(StrMessage)
2 Z9 ~& a8 R' x5 D2 U" Y& pSet ObjRSA = Nothing
5 ]" Y& q% n0 C4 Yend function5 e/ X; B. D/ h% `* l. d7 C& P c* k
Function Decryptstr(Message)
@: D; T3 X" X1 w; |& wDim LngKeyE
7 n8 ~! y+ _+ q5 ?4 h" eDim LngKeyD
5 s( M0 D+ z3 x. H+ gDim LngKeyN 2 w, p% v) I5 L! D% G0 `
Dim StrMessage ! t- S- w" W5 S7 E. S$ `- h% U
Dim ObjRSA
! F6 ]6 Y4 K( _, g+ D3 w3 j$ ^LngKeyE = "32823" ( a/ U2 j& Q% _* I' \$ e
LngKeyD = "20643" ) h. _9 ~ X7 U0 \
LngKeyN = "29893" . }- U, f8 o5 p
StrMessage = Message 4 D' X8 F7 m& V$ S
Set ObjRSA = New clsRSA
0 q/ {' C1 e. r8 S0 [ObjRSA.PrivateKey =LngKeyD
Z1 b+ H% S: yObjRSA.Modulus=LngKeyN 5 u4 a% L& Z! w% p
decryptstr=ObjRSA.Decode(StrMessage)
7 o T7 U( J. x% v2 v# vSet ObjRSA = Nothing ' `/ P# P& z) c/ J; o
end function
! B( h/ M$ J2 Y- j%>
* p4 b$ k6 j* j1 n& h7 ^===============================================- F; j0 p- J; f* a! e
- b6 e5 U# K% _- q! j还有一个用于测试这段代码的test.asp/ A' N( t2 D+ k `- ~9 ~
有兴趣的自己搭建个IIS测试下
2 |4 ?3 T9 O! c) n' {5 j5 Q<!--#INCLUDE FILE="RSA.asp"-->
# s$ B& g; X9 r# I<%+ H# J1 E6 v9 ]( {8 D \
function Encryptstr(Message) 6 c+ B3 U1 s; N/ j; u
Dim LngKeyE
5 O b4 @% V+ d* W5 k; {Dim LngKeyD ) l; u: U" b- E/ Y
Dim LngKeyN
, n+ \7 `/ n* W+ RDim StrMessage
' u2 r1 k6 V# U+ @9 j& WDim ObjRSA
0 c: Z6 V1 H# q9 t! U5 lLngKeyE = "32823" ; e. p3 O- v o* w i$ p7 b
LngKeyD = "20643" ' L) k/ C0 p5 D& @5 c# ]
LngKeyN = "29893"
1 E" l( H, B; U- A! kStrMessage = Message
7 A& }1 I1 u6 DSet ObjRSA = New clsRSA 5 R, @9 q+ F2 F& K3 ^2 D( y
ObjRSA.PublicKey = LngKeyE
1 v& k0 v; H4 b- O6 a+ yObjRSA.Modulus = LngKeyN
, x- S3 ]0 n8 ^& j/ L/ h1 w$ ]/ sEncryptstr = ObjRSA.Encode(StrMessage)
; k+ A" @4 n; ^8 uSet ObjRSA = Nothing
/ L, V9 M4 B6 wend function
' h2 X$ @8 R" K% Q) ?0 i4 J9 yfunction decryptstr(Message)
4 S- ?# |+ i1 s/ ^6 |Dim LngKeyE
3 M: w4 {9 f1 b# ZDim LngKeyD
! D* U% F# }7 t8 J7 a7 W! Y( V) fDim LngKeyN 8 a# t$ h. o5 Q6 d. s, v9 P
Dim StrMessage 9 o) W. J& Z# S7 N" H
Dim ObjRSA
4 c# C0 I& g" \: ^8 s2 @) r, [LngKeyE = "32823"
+ @" }: e6 A: D: f8 U, T8 TLngKeyD = "20643" ' t/ {6 {4 F$ ^% ~* U
LngKeyN = "29893" 1 L; @8 A5 F k- f4 J) \! L
StrMessage = Message % }( u" m# j% r; Q4 x
Set ObjRSA = New clsRSA
. Q$ F- E: E% t+ v' z. |ObjRSA.PrivateKey =LngKeyD ( z- m+ I" V* x1 y7 R* H
ObjRSA.Modulus=LngKeyN
5 j' R q8 W4 ~. x- ydecryptstr=ObjRSA.Decode(StrMessage) . x8 ~' q6 S2 Y: U4 F* j1 B
Set ObjRSA = Nothing # t/ m1 ` |8 [" N0 `1 C$ w/ k5 L# V
end function
: A0 J" D! _# `* h4 ddim last,first
- f) r& m6 L1 h k" hfirst="!@#$%^&*()"
7 H0 g& b4 ]4 G1 _5 |Response.Write "加密前为:"&first & H+ U3 _: p# w3 f8 J
last=Encryptstr(first) 9 Y2 ], [0 P; Z, X
Response.Write "加密后为"&last
+ @ P: O% u# Q7 `' n! ?8 G. QResponse.Write "解密后为" &decryptstr(last) 8 V# ^4 @6 m' H- q% k
%> ==============================================; a3 a- l6 H" F' [
剩下的就是字符的对照表了
0 C6 Y* t2 n* Y" c+ [$ z3 t, S" u' y% c===================字符集================: g }& c: g8 \7 K
1_____6EBB+ {3 A' F0 |5 v& a
2_____5C1F1 O' y9 H; r3 q1 ~: ?9 R" p* [
3_____4D75
7 f) Z0 D! l5 L5 n6 Z' c4_____26CC+ q$ q1 u* ?4 T# @- p$ U7 x+ k
5_____4F88
, x- J9 h/ {6 V3 a; d5 F8 V5 e. ]( i6_____3F4E
' P, O8 k% y/ \, P) g' e7_____0A9D1 p: q: @5 h$ V0 I
8_____1A1C
+ D7 k; b F5 |! ~! {9_____6D20 n/ w, l; L3 [5 p" C
0_____1089
: d4 A% m1 M( Wa_____0F3E4 N; d0 u- W5 s' s
b_____3159
, {; e" ]. e- W8 C" O% E) Wc_____3517
5 M5 R) o* V8 h& cd_____419C
) I# h. A/ n: K& o# Ve_____615C
1 f' p6 J3 L$ g; sf_____556F/ a, K5 Y. N; W( @
g_____2B7F
! M# p# _3 ~* \) _3 Ah_____0F9C5 R- s7 _% K- ?6 Y% B
i_____00FA
9 |9 z9 x! q6 g q2 zj_____5A50, q6 Y3 C! [1 {% }# J8 I1 |( E
k_____2850
4 w# ~! W/ k/ O l' Tl_____3E7B3 d3 ?- P& b" c
m_____71C5' T3 m0 {7 N# P$ v' ]9 X/ n& C
n_____1FC8
! X) R$ ^5 R4 {o_____74C1
, D) l5 U: s; X4 _p_____5FB8 V+ H2 w- W1 K$ @- l- R$ C
q_____60859 L9 c. O$ G* ]% G: D4 A& Q
r_____3AC4
% O' c# O" {) M1 @3 ms_____2F50+ L O8 l! q( B5 T/ ~
t_____36F8
, G% H$ t/ t v: k' [5 w2 au_____7010# L6 h( o5 |: [$ M
v_____0B42: k/ v4 a# n2 H1 ~' A1 U
w_____1C7A& K; r9 d' n4 _/ x1 k
x_____16F8& J2 b$ I0 x |% J+ Z) s
y_____2EE7
' t: E" N$ R, Yz_____5CF3) ~, ?$ W8 k4 k6 y
!_____6233/ l1 P. @) g6 X6 o( Q( u+ V+ A
@_____3A45
4 k# a# k. ?5 ]' L2 C8 l#_____2291+ x" z7 F+ E4 w$ b3 K, J
$_____5D5C
, U4 B) A: F; J9 _6 r%_____09B9+ Q% E- X2 N4 ?: t
^_____43EA/ o+ k9 Q3 ^( a# b. e8 Y
&_____62B9
2 g& i+ P! ^4 h x9 J! G+ r*_____6301
! Q0 X2 h/ h' J% |(_____4659/ j* L( H2 \4 N4 d ?
)_____5C82 |
|