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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm8 r& ~1 f8 ^* ]
原始出处:http://www.3ast.com.cm
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看不懂的直接绕过8 N5 S: k9 f# ~( P9 }
加密前为:hwy123456
- V( w# h9 G8 |加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
" l% _3 h" Y% ?/ f1 C' j; Q9 `+ U( |6 L
============================================1 X& I, S1 F1 N6 e- P0 s4 ?
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
/ h, n0 m! ^- o! T! J也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
1 w, E0 @- K. z以下是RSA算法文件
9 x& B" T' Y5 H6 A: G$ n1 }1 S# x2 c" c% ^0 m: s' }# f
文件名RSA.ASP) m% N2 u1 q2 R) ^4 B0 W
===============================================
" ]$ d: A, O$ b! J<%
( O. Z4 i0 X6 YClass clsRSA
& S w Q0 e1 g/ ePublic PrivateKey 0 N: k, A4 h$ R
Public PublicKey
2 C7 x1 z: Q! Q/ ]Public Modulus ! M$ u- Z# r" B1 @8 e. { g5 A
Public Function Crypt(pLngMessage, pLngKey) 4 _! O( h7 S' w& t) M
On Error Resume Next
5 q5 W1 D3 p7 `Dim lLngMod 7 s. h# O6 d" w
Dim lLngResult
2 u2 K) \. H$ RDim lLngIndex 4 _" `# o9 Z/ V
If pLngKey Mod 2 = 0 Then
/ B4 |; }" @( W1 b: z3 z# nlLngResult = 1
" i, f6 C& X4 @4 K# Z; h% OFor lLngIndex = 1 To pLngKey / 2 * j! n2 [$ ]5 ]. U% s+ |* {8 i6 p
lLngMod = (pLngMessage ^ 2) Mod Modulus
5 r2 a6 {4 B+ `) u0 T! {5 `' Mod may error on key generation
% R( R' m- W9 M) L8 y9 y3 flLngResult = (lLngMod * lLngResult) Mod Modulus ! ~# E- |3 d! s4 }4 b0 t: E2 Q
If Err Then Exit Function
7 t! ~ l- p ?$ [5 Q3 G& hNext " C6 u" O8 J. m
Else ' X/ Q5 N+ b& N j' }+ j8 V- \
lLngResult = pLngMessage ) ] O' X! k3 f2 `
For lLngIndex = 1 To pLngKey / 2 * ?: D8 q* U, ^1 p9 d$ l! ]
lLngMod = (pLngMessage ^ 2) Mod Modulus 9 g' ?7 I$ h- `+ V; [1 B7 }) ?
On Error Resume Next * r' |- p d/ W5 H: q* q
' Mod may error on key generation
8 a5 P' l8 D" wlLngResult = (lLngMod * lLngResult) Mod Modulus
2 R* K1 n# O! K. jIf Err Then Exit Function ) m+ U, N2 B, ^- v
Next
6 N! o( g6 m: O5 n" d$ v* A% BEnd If - K6 U3 w; y1 D0 L8 B7 A; |
Crypt = lLngResult 2 S8 ~- }# P2 T5 r% h
End Function
0 f8 I0 K& i1 O+ `7 |0 T$ q" V6 Y8 o& ?3 G5 r; d N
Public Function Encode(ByVal pStrMessage) ' c; p4 ^% L' w+ G( E9 W/ t' m5 V6 |
Dim lLngIndex , T, m" z: c; k8 g
Dim lLngMaxIndex
. X9 u W+ `1 @& W4 sDim lBytAscii & h; ]. I7 g! J8 `7 T
Dim lLngEncrypted
( H2 ^/ {% R/ M* blLngMaxIndex = Len(pStrMessage) 5 c1 I2 T0 K V. t( M% u6 r
If lLngMaxIndex = 0 Then Exit Function
5 f# [* V" a$ B4 n+ ~# j. z1 a; AFor lLngIndex = 1 To lLngMaxIndex
' n$ e7 l$ k2 [lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) $ ?* o4 i% ?' Q) k
lLngEncrypted = Crypt(lBytAscii, PublicKey)
2 N0 X; V \( ` i r. w6 L SEncode = Encode & NumberToHex(lLngEncrypted, 4) : g G e( U3 \4 a) p y4 P& I
Next 3 X, n% g/ S% ~ H
End Function
, f, g: R5 L- O. c, wPublic Function Decode(ByVal pStrMessage)
( K+ ?; H9 _) j+ X, D/ |( ^0 ZDim lBytAscii / y3 ]! s- e7 @
Dim lLngIndex % [' c4 P$ w9 `5 s- ?* K) }
Dim lLngMaxIndex
* _% N0 P- ~$ N: E; \Dim lLngEncryptedData
" z: E: ? D, e* ^) y7 ~1 vDecode = "" ' A3 f6 Y7 @& J( q+ Z g
lLngMaxIndex = Len(pStrMessage)
* t7 X( X& l( ^8 hFor lLngIndex = 1 To lLngMaxIndex Step 4 1 X. A }7 T9 Q5 f
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
( H4 N+ t0 \$ ~+ d9 dlBytAscii = Crypt(lLngEncryptedData, PrivateKey)
9 i/ v% ^ l) e9 V* L2 N6 F1 k1 n) MDecode = Decode & Chr(lBytAscii)
. ?; @( E, S' A a8 UNext
7 E: t( N4 B/ z; X" [' z, T" h( OEnd Function - _$ m# l/ B* h" g
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 0 a0 [) J0 z; j" _8 [
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) 8 T( P: ?9 q. F" M$ Y: m
End Function 7 o) \- }! l0 v7 G% O
Private Function HexToNumber(ByRef pStrHex) ' s9 {1 S; ?7 X2 C0 R
HexToNumber = CLng("&h" & pStrHex)
" y4 }" `' y! ~* `1 t a7 LEnd Function
( @, Y* u, Q; {" q/ K8 @End Class 0 }- P& k$ n5 C/ Z1 D5 W, r, A( B
function Encryptstr(Message) 1 x4 o4 h1 s5 [- s9 ` _+ m: s6 |
Dim LngKeyE
- a% `* u# ^) \% xDim LngKeyD
: v4 L) ^& F3 x/ q Z+ P$ eDim LngKeyN 4 a5 C c+ H5 @) Z8 F; l
Dim StrMessage " O1 O& R" s/ ]8 k0 }3 E
Dim ObjRSA % k& Y8 x6 c$ Q ?% [( T+ E1 b7 _6 g
LngKeyE = "32823"
3 L& O" P8 T7 ~, U4 w% m% R. cLngKeyD = "20643"
+ O, ~1 H2 e: V( B+ C" X: ~LngKeyN = "29893" 9 t* {. [6 k e9 h* r
StrMessage = Message 0 b! x% a+ b/ p8 H1 z* ~
Set ObjRSA = New clsRSA ' ?4 J6 k7 Y$ u5 E6 x
ObjRSA.PublicKey = LngKeyE
+ r* [& I* \) s* J7 a" VObjRSA.Modulus = LngKeyN
n- f* k4 m/ n( yEncryptstr = ObjRSA.Encode(StrMessage)
% F( l0 ^8 [% m' k3 H3 m4 z# qSet ObjRSA = Nothing
5 m( A" {6 q$ K/ r5 Wend function0 H. x" e, v8 \% N- a; G# Q l" u
Function Decryptstr(Message) ! o0 t, O, c% b6 o
Dim LngKeyE ( ^ \% I5 J% s% v8 C1 W
Dim LngKeyD
Y. C) \+ ~, `- F! ADim LngKeyN
: d* _$ B4 n* p# {Dim StrMessage # T( V! P1 r" f7 o! e* b
Dim ObjRSA
: P2 ]. g* l" `) H0 D2 u- o% ZLngKeyE = "32823"
. V' \% l2 }2 _& t/ M, O7 dLngKeyD = "20643" ) t* O- w: A( B5 ?
LngKeyN = "29893"
: W% H3 r3 g6 a/ }+ ?7 b( y3 ?StrMessage = Message + O& I/ h. q1 Q, t
Set ObjRSA = New clsRSA * V C: r- ?1 E# R
ObjRSA.PrivateKey =LngKeyD
: \ |3 M+ m( c9 c: q; CObjRSA.Modulus=LngKeyN [0 G" c% o2 |/ w" @% e9 m
decryptstr=ObjRSA.Decode(StrMessage) 6 t' d9 E1 N; u) p
Set ObjRSA = Nothing
- x$ R% s- g6 x% Y9 _7 t* {+ jend function 1 g$ y) E6 G/ C9 X5 L
%>. W0 b, a' F" {! l1 ~
===============================================
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还有一个用于测试这段代码的test.asp
7 u w4 z) [1 g2 O& d# z有兴趣的自己搭建个IIS测试下
1 {; b: v: M( p9 m4 h<!--#INCLUDE FILE="RSA.asp"--> / I: _; r/ s; u. o, e
<%
( h" D" L: b# Q2 ofunction Encryptstr(Message) ! P( b5 |0 m4 i' M" u
Dim LngKeyE ! U; F/ f! ?2 }' `( i
Dim LngKeyD ' g* t5 ~( V! c6 Y9 S* c5 R. U
Dim LngKeyN 0 l7 N7 Q8 n$ A" ^# S( \* L1 |
Dim StrMessage - R n, K- b' x/ X6 F7 l
Dim ObjRSA
5 N' L8 S9 Z! z" V3 jLngKeyE = "32823"
1 o; t! @$ W0 JLngKeyD = "20643"
( E5 y u1 }! F6 ? `6 \LngKeyN = "29893" 0 E8 `% z; k4 c9 j6 W. ?
StrMessage = Message
8 X* _+ c# [) U( p/ H6 oSet ObjRSA = New clsRSA
? o3 Q+ ?, V! h, bObjRSA.PublicKey = LngKeyE
$ w7 i: D! o# d# P/ f: s$ `) ?ObjRSA.Modulus = LngKeyN 2 e- j- ]/ @' R5 ?7 F
Encryptstr = ObjRSA.Encode(StrMessage) 8 M8 H( x6 q; h
Set ObjRSA = Nothing
# p% }7 B- c' }* L! S! ~end function 5 z" r1 y. K9 v. N6 t* o+ ]8 a
function decryptstr(Message)
8 k5 }$ F) O9 f& k e- w2 b6 WDim LngKeyE
a6 Y- c) y7 q- ]$ B+ HDim LngKeyD , L- e3 X. M% Q: q. E4 s4 |0 S
Dim LngKeyN 1 ]8 R. t, q+ Q0 J
Dim StrMessage 2 S3 \4 J$ X! T8 |0 P* [
Dim ObjRSA
+ w5 ^% h0 s& r' l, N4 S7 a$ P+ YLngKeyE = "32823"
8 d- v T5 O b; J9 c1 ILngKeyD = "20643"
5 i4 |" @# G+ X+ [2 j: k4 SLngKeyN = "29893" % D. v! ]" v! c) q
StrMessage = Message
8 @, `3 f7 l; r( NSet ObjRSA = New clsRSA
- w; \, y/ F$ U; ~2 wObjRSA.PrivateKey =LngKeyD # ]0 U$ e. n0 D2 k/ a' s
ObjRSA.Modulus=LngKeyN 4 y' T7 V* @# x
decryptstr=ObjRSA.Decode(StrMessage) 9 H- A: S3 R# m' d/ d; i* y
Set ObjRSA = Nothing
2 |8 }3 U0 k2 Z' Q( h' o7 {6 I# z- J3 }end function # U; Q' o+ b' \) {& z U0 S. E
dim last,first , t' f7 n7 r Q: F- |3 W1 w( T
first="!@#$%^&*()"
6 U5 X4 r) U0 o+ [; ?, UResponse.Write "加密前为:"&first
2 o3 g% g$ _+ Y+ e; ylast=Encryptstr(first) 8 x" Y' U, p( ^
Response.Write "加密后为"&last
- y7 A9 X* S; T8 i _Response.Write "解密后为" &decryptstr(last) & v7 }$ D9 ^' J- j1 E
%> ==============================================- d3 p0 _9 y* D% w0 e! N
剩下的就是字符的对照表了$ p; g& e( e& m+ Y/ l2 O9 b
===================字符集================7 Z. E; D9 R* U
1_____6EBB
1 i6 ~5 F7 N! F* ~( Y, g2_____5C1F0 c# e( m- F# O" B- Y
3_____4D75, j5 c$ h8 F3 p0 ^. H8 q# m
4_____26CC
/ v5 g5 M: J* q+ ]0 w+ p0 g5_____4F88
: q* [2 _ y+ D: u6_____3F4E0 o, S( |% A3 I2 P
7_____0A9D
! b9 P. I$ s1 a( s0 U* P C8 O8_____1A1C
9 V% P# d2 C0 e+ R9_____6D20
9 `6 l+ j" x$ I* E9 ~; F, \4 k0_____1089
. x6 y: x& J. J1 e) |' h0 x' La_____0F3E
8 m" W! D- W- D$ e9 R3 N2 u3 j* v. pb_____3159
3 ]1 U! P) n( }c_____3517 {/ `; \' z v* }, S! M9 x
d_____419C
' s$ k/ }- y$ }, c- l% Y6 O' q5 @e_____615C
, l3 w! t, \9 ]f_____556F, I5 {* b/ b; W' b' S
g_____2B7F
, B+ g* G+ l4 O. r+ U. D1 qh_____0F9C4 f2 ~' P; E2 _* ^3 Y4 C9 k
i_____00FA
9 }! G& X+ X' rj_____5A50
+ k& ~/ `9 ]4 v6 M% U: ^3 Wk_____2850
; Y) ~8 d; R, T) v+ E' U' a- ]- l( I5 Yl_____3E7B3 T- E2 Y7 r1 P7 Y8 e% d, d
m_____71C5
- c: g7 D1 X3 d# d; A! sn_____1FC8
- ^; E+ w0 F- J9 T" _8 W) Ko_____74C1
0 l0 i O: W1 s; \p_____5FB8
/ J' L. e/ o$ ?6 hq_____6085
% j1 d+ Y, r/ q# Z& W/ cr_____3AC45 s. `! s, x/ x* M/ R3 s+ A
s_____2F50
3 T1 Z- D a& x* Dt_____36F8
1 k, }5 p: J4 ]; G4 fu_____7010+ d. q- { `" f( D3 |
v_____0B42
% g- i" P' s2 s% b- Sw_____1C7A
2 R. w# p* k: b# P% J& H' J2 Lx_____16F82 n+ S9 j5 n& c7 q- [" w
y_____2EE71 e$ X8 s/ y6 t4 R
z_____5CF3" _4 h5 F, B$ h( n( @0 s
!_____6233
$ T4 I; Q8 \6 S: w8 H1 n8 t, @@_____3A45& l+ y* w/ k$ D1 @1 `- q
#_____22914 ~6 Z5 ?+ x8 Y/ A" P+ Z/ e
$_____5D5C9 m% z# g0 v. l& |* a8 ~
%_____09B97 ~3 e! R# E% H; d, w0 D' m3 q& W
^_____43EA; g6 x$ ^8 T) I5 Y% q ~
&_____62B9
7 P, n: C* c0 X*_____63011 |% h$ S& G U1 x4 _
(_____4659
; p: P! Z3 [9 A5 {! L+ m4 n)_____5C82 |
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