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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm$ i' ]* l' B+ E2 X @& Y
原始出处:http://www.3ast.com.cm
1 j8 r, T; U! i# m' P3 d U6 [6 C
* w# ?6 Z$ F4 c看不懂的直接绕过
' L6 m# G/ y4 C+ S加密前为:hwy123456, C+ U u! S+ F9 H0 R: }( _7 H7 j
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
/ |3 U* D2 L2 g& z8 f
& U$ Q& J3 y1 r============================================+ _# k8 `+ O) }9 ]' K' [
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
1 A9 u4 Q$ l0 `也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
. [% s/ f9 U2 o! a- H: D以下是RSA算法文件7 S6 ^6 h" \- @; A
$ {# J/ X& g- P6 X4 c文件名RSA.ASP
3 @6 \6 \0 [2 m2 h; V* C8 y: G===============================================% \$ v' q$ g9 a+ J% b% J( Y- c
<%
) T) e7 m; I, O- f+ M# WClass clsRSA ; t' C# ^: A3 s- n+ Q6 x; n% i
Public PrivateKey + A! `6 I% C5 Q3 t$ [/ ]
Public PublicKey
9 v y6 F! C; f4 x, BPublic Modulus ' |2 t- q% C/ C$ l
Public Function Crypt(pLngMessage, pLngKey) ( _" f' P5 X) O; O7 f4 a( O
On Error Resume Next 9 G# a# Z; q7 }; p1 c9 g) T
Dim lLngMod & j2 H, Y8 J/ I `/ l8 n
Dim lLngResult , W, B; ^6 T& |9 ~+ J6 W
Dim lLngIndex 3 @, |. y1 ~ h( @6 o
If pLngKey Mod 2 = 0 Then ( [0 S' ?; K/ s) G* `: |3 {3 N& o& o2 v
lLngResult = 1 * Q* z% {( Q' o+ N5 w9 T' G
For lLngIndex = 1 To pLngKey / 2 . j) R- o a; \- m6 g ^4 r
lLngMod = (pLngMessage ^ 2) Mod Modulus
0 B( E; U. j O, M+ ]* ?' Mod may error on key generation
$ u( U- t2 Z. z0 i& p7 Y+ _: s# ?lLngResult = (lLngMod * lLngResult) Mod Modulus 1 g& n9 I8 s. z, b( M L# e' l
If Err Then Exit Function ' i6 x0 n! i0 d$ N* S: Z
Next
7 V( }/ \9 @; @# V! o+ }7 \Else
+ x+ Y. n. d% g3 D3 E3 R3 RlLngResult = pLngMessage
/ n4 N4 I4 f1 B/ BFor lLngIndex = 1 To pLngKey / 2
3 k3 J- C( j dlLngMod = (pLngMessage ^ 2) Mod Modulus
; Z* s; X4 H1 N ^6 [On Error Resume Next ' D! @5 C4 c6 v- m
' Mod may error on key generation & Q9 j, x6 ~) C' {. i, f" N; N
lLngResult = (lLngMod * lLngResult) Mod Modulus
( I2 G- Q @" ~7 |' AIf Err Then Exit Function
5 f" u, ?2 K5 v a/ D2 G& HNext 0 Z, ?+ S9 }* k. G& W! Q* P
End If
$ D O; B! P0 a3 J( L! Z, @Crypt = lLngResult & [: g4 o% z) v' B
End Function
+ y6 ?( u5 o2 E1 t7 g: \6 |4 @- V0 p! H
Public Function Encode(ByVal pStrMessage)
4 t1 m% Z8 [) w1 p& m4 hDim lLngIndex 6 N' R1 I8 k" l: x" A+ {
Dim lLngMaxIndex 3 W) t: W- D( L) V% n! Y5 k
Dim lBytAscii
$ u$ e1 _& p" n# zDim lLngEncrypted * e: O% l% |7 g' E# ]
lLngMaxIndex = Len(pStrMessage)
' _3 G, }% x" } E0 i4 rIf lLngMaxIndex = 0 Then Exit Function
1 F! o4 k- q2 o+ O$ ~For lLngIndex = 1 To lLngMaxIndex % l- o) @ d3 U8 a6 \2 b
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) ' W, M3 G- D+ F
lLngEncrypted = Crypt(lBytAscii, PublicKey) 8 [* J l: e9 I* q3 H
Encode = Encode & NumberToHex(lLngEncrypted, 4)
3 k! l! q$ o/ v/ ?+ sNext * A v6 P2 W9 o7 H* r$ G5 Z: w
End Function 6 O" o* [+ L3 i! Y
Public Function Decode(ByVal pStrMessage) " J2 d2 r; y+ f) r3 U
Dim lBytAscii 2 S7 }" e4 [1 {( Y
Dim lLngIndex 9 F7 Y, e7 r9 |& J2 q7 @& Y. Y
Dim lLngMaxIndex
) N# [( z9 i: vDim lLngEncryptedData
( t% R$ G% n+ ^Decode = "" 5 \4 O) z7 l8 \: R7 s
lLngMaxIndex = Len(pStrMessage)
! J, Z' r; Y/ z" g6 G3 a% n1 IFor lLngIndex = 1 To lLngMaxIndex Step 4 $ j" f0 D; R( ~ P
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
4 B: p" B3 b) v7 x$ p6 PlBytAscii = Crypt(lLngEncryptedData, PrivateKey)
5 _ |( F% ~% E' BDecode = Decode & Chr(lBytAscii)
! d, t- i6 z/ H! v4 nNext 2 T0 ?) D- W$ o9 t1 e6 P8 _: k4 y0 ?
End Function
; W S) H) \- }% wPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
% ]! H, R7 |: w2 f& Q! }NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) # |. Y1 x- o* }1 _' u6 p# r
End Function
. R$ T. y3 E# d* T' Y, TPrivate Function HexToNumber(ByRef pStrHex) $ M$ h! r. F# o5 ]1 d
HexToNumber = CLng("&h" & pStrHex)
. V2 o) [6 ^% `. X$ i# xEnd Function 0 ^3 C- B% x. g/ H% W2 I
End Class
& [: j [/ m& `. O( ~: tfunction Encryptstr(Message)
4 Z# U# ~$ g) l- kDim LngKeyE
3 M1 Z; A& `) VDim LngKeyD ; ^9 Z7 b' ?; V& q d* U1 Q" X
Dim LngKeyN 3 m8 W0 @# U9 D
Dim StrMessage 5 \3 E5 T' D3 h
Dim ObjRSA
; _" ?; Z' G; }' V) ]! HLngKeyE = "32823"
* B: }6 |& T9 O6 `/ c! d* KLngKeyD = "20643" . q" j$ t X7 A6 E
LngKeyN = "29893" ( w5 Q* h. @& _- d* i8 G
StrMessage = Message " M) j- m- f7 i( X# P! y, g1 M
Set ObjRSA = New clsRSA
" f+ @5 H: k* v) l9 Q5 A0 SObjRSA.PublicKey = LngKeyE 7 Y# x% q* {2 D; ~% D
ObjRSA.Modulus = LngKeyN
4 e' z. t# N5 @2 s: NEncryptstr = ObjRSA.Encode(StrMessage) 2 C0 f) q8 ^4 b3 ], {
Set ObjRSA = Nothing
" N% F2 ~( K% M' fend function
- C) |1 d" F7 ?# m% _, qFunction Decryptstr(Message)
7 X6 Y1 x' X) x- T9 g6 h8 |Dim LngKeyE
0 Y& E, x) J% T, H9 ZDim LngKeyD " \+ b8 ?: k$ r4 ?. ?
Dim LngKeyN
; z m1 G# Z$ uDim StrMessage & I& m. Z' d! Z9 q( l& @
Dim ObjRSA
6 t# ]! i& n; _LngKeyE = "32823"
& M% S1 `7 d/ t) TLngKeyD = "20643" , C/ ^* c) d5 Q0 ~4 u( G
LngKeyN = "29893"
' ^2 [# e! P7 g; Y, @ p F! ]StrMessage = Message
, h9 u: r& {1 `2 Y0 u8 ASet ObjRSA = New clsRSA 5 F2 {, u' V M) z8 Z
ObjRSA.PrivateKey =LngKeyD
# z1 K1 n2 e! K1 x$ j& jObjRSA.Modulus=LngKeyN
" v; m; o" M" f6 kdecryptstr=ObjRSA.Decode(StrMessage)
& P# u* ~) Y9 K' T, ]9 @Set ObjRSA = Nothing
! \8 j, ?. r# x( P4 u3 B+ Oend function
. M% @9 y/ Z0 n3 Q; d1 ^' S%>& M4 k X, u2 {; i' j
===============================================
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还有一个用于测试这段代码的test.asp2 @5 ~5 B- {& a4 n8 a- M, F+ M3 b8 R% z
有兴趣的自己搭建个IIS测试下
! `+ O i( [* b9 @<!--#INCLUDE FILE="RSA.asp"-->
$ i$ `% x& c- h5 a' R<%
+ S* W+ S/ F+ F- r! U/ yfunction Encryptstr(Message) * g+ V3 X9 m2 O( r. T
Dim LngKeyE & o& K& y8 ~" b! \& T, b
Dim LngKeyD # W+ v1 @# ?7 `6 v$ I- e; V
Dim LngKeyN
. a7 ?1 O: [+ U- DDim StrMessage
; P# F* ^1 h# z; a/ @) FDim ObjRSA ' ?$ `: z( E' `, O, C
LngKeyE = "32823"
& z c% s9 D$ f! O/ }6 }6 jLngKeyD = "20643" + L/ t9 W) |" L; q
LngKeyN = "29893"
: u- D8 a+ V- k" TStrMessage = Message |2 _+ K& h- C' q
Set ObjRSA = New clsRSA : _% S) ?3 c, p5 h
ObjRSA.PublicKey = LngKeyE 4 m" G) p/ |' Q% J
ObjRSA.Modulus = LngKeyN 4 H5 }) U# Y; k, [+ B: d* q( Y
Encryptstr = ObjRSA.Encode(StrMessage)
% v+ q- d$ w+ m/ t, pSet ObjRSA = Nothing
0 r# \- ^) Q& B- r: Mend function
7 G ?" U4 Y; b4 [/ {4 Z( ^/ {3 ~function decryptstr(Message) 3 }& @- K& B( f9 ~7 ?, P; j
Dim LngKeyE 3 F8 v, \# N' ?% Y: a9 C* V# U2 O! D
Dim LngKeyD
$ [$ P& r4 h" p0 g1 ADim LngKeyN 0 t) i7 I, r+ V1 d$ R: [
Dim StrMessage
2 N f- m3 `, B( m' z. R9 t) z# v$ RDim ObjRSA / F- _$ P6 W; w# b
LngKeyE = "32823"
/ K, _6 J* q$ @% t, ^LngKeyD = "20643" - a, ]1 s+ Q+ j+ q9 B% c' E
LngKeyN = "29893"
- ~2 ^: l: j1 _9 d9 H. u) @StrMessage = Message
F8 F1 I4 N1 F8 f2 kSet ObjRSA = New clsRSA * u+ |) r4 y4 B H9 M
ObjRSA.PrivateKey =LngKeyD 7 n; \4 E% z5 a0 G7 s8 m
ObjRSA.Modulus=LngKeyN % s. [5 v8 C5 ?* l% n
decryptstr=ObjRSA.Decode(StrMessage)
: ?2 X( Y- o9 h3 n% t! G# lSet ObjRSA = Nothing
6 V9 x/ @% n' Z1 T& F# ~# {! qend function
: A. p4 k) g; B9 x! q7 r2 y. M a/ Mdim last,first
0 _# s9 m. A7 [" Kfirst="!@#$%^&*()"
0 g2 Y* W9 P0 Z/ AResponse.Write "加密前为:"&first
* y' |6 m5 k$ Glast=Encryptstr(first)
3 [8 F- u( a+ k8 EResponse.Write "加密后为"&last
' A# T( R) r; N+ f$ @( ?# X3 wResponse.Write "解密后为" &decryptstr(last)
( g- q9 U; u3 r' S1 `) b( \%> ==============================================
+ [8 D5 d7 O& F+ e q* J m剩下的就是字符的对照表了
, S6 D1 e# C% ~===================字符集================) h6 {/ \+ L L4 J
1_____6EBB4 S0 _: o" f; e$ M
2_____5C1F
; K" k2 d: O. o0 C1 |. E3_____4D75- p; p$ k X/ n" @3 i) J
4_____26CC |7 {; Y; U; s, ^, v6 z9 T
5_____4F88
& y' o# e7 E1 B; u2 k6_____3F4E
1 o# C+ k4 \5 }' `7_____0A9D: m0 o8 N' z. ^9 z5 h# w0 ^6 C
8_____1A1C8 Z. ]' a1 Z. ^8 W1 G, _
9_____6D20+ W# r7 K7 a! E# D0 y- t% h+ s" u9 n
0_____1089' ^ ^ @# R2 u z3 f
a_____0F3E
4 j U# a; C5 |& Rb_____3159
7 P/ z# {8 F+ H: Y3 m. A( P8 ic_____3517
3 b3 `( L& O. j4 V) t5 Pd_____419C; G1 d8 f, o* S: T
e_____615C
" N: k) A5 G, if_____556F
2 D ]0 ?/ U. j, i6 Ag_____2B7F
6 C4 S3 H3 |& `, `: u/ `! r2 A- U& sh_____0F9C" S/ }/ o* i: d, Z U7 ]8 ]
i_____00FA
8 w% Y" r; o. q2 [0 W. |& H0 Bj_____5A50
& F4 {) f+ ~. b8 A/ i- Hk_____28500 I! M) |1 d; t4 Y
l_____3E7B& r! h! B- f% f8 ?' t
m_____71C5
; W4 [7 D& A+ ]4 y$ h& ln_____1FC8
6 O" k6 u: r" b+ zo_____74C10 M2 S8 x6 l# K4 K1 Q3 m3 y
p_____5FB8
8 g8 p- T, Y3 c8 y4 A+ Z# a" B; kq_____6085
+ J: Z- \4 I" Y" C$ Y* S; r' e) rr_____3AC4( Z* e& L2 F9 x' G8 t
s_____2F50
I2 E2 m3 s2 B/ Yt_____36F8
! t G6 d8 a* z4 \/ ru_____7010
B6 U7 D2 i! m3 S# o+ q( K5 b( lv_____0B42
: G3 M7 r' P/ {( Aw_____1C7A
/ J' w- n/ k2 A( f* Q% S/ {x_____16F8
# y0 s( ^& U; @y_____2EE73 T. x6 v' `: Q' w5 i8 ?
z_____5CF3, J# }$ N1 ?0 }" l) n
!_____6233
2 V( |* r3 G; y0 Y@_____3A459 t* H! O! |4 ?( ?- v- ^5 S
#_____2291) e8 |# m( G# W6 W! W
$_____5D5C1 n' F/ n& M4 X7 [; t C" r
%_____09B9
0 [+ E h1 c! N: R! s^_____43EA
5 n4 o% O! i: D6 B6 l& U4 ^&_____62B9
1 c7 F/ h/ K/ P3 g# x5 g*_____6301! u6 z5 ?; N9 A7 J
(_____4659
# @( V/ g+ D8 @/ R9 h)_____5C82 |
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