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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
5 J. ~2 p0 O- h+ O原始出处:http://www.3ast.com.cm2 d0 O- g2 [8 ~# i& a. A
, `( _) J6 i; J, [
看不懂的直接绕过& o* a8 w5 X. B' n
加密前为:hwy123456
* {% V: V( U' c9 K. ~加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
) P. ?6 R% W( _; t! b
6 O6 O: B6 G8 \% c, Q' Z1 G============================================; w% i2 ]- p. e$ |, K% p# l
上面是当时自己校内的心情。现在已经解破出来了,分享给大家5 H: R) T5 @& f) V
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法- G/ D/ [( y& c
以下是RSA算法文件
. g! v7 H# `9 P1 ~; M0 O
0 j7 c- ^; G1 t# P) G文件名RSA.ASP
8 x( Z; o: X( {% y+ @, l===============================================% u$ w5 t% P$ x$ q7 g
<%
5 ^3 |- B9 a d4 }) z! \7 a2 E6 XClass clsRSA
' n; P# J$ B0 m# I9 E$ P, d% l6 tPublic PrivateKey ( R% J$ F+ Y2 G6 O
Public PublicKey $ b7 V# P0 B/ ~9 O2 k2 a1 ?
Public Modulus : r0 s% G& s' c7 r# Z
Public Function Crypt(pLngMessage, pLngKey)
& R9 `7 H. `5 t) [) _, HOn Error Resume Next
2 f" ?. {; @; {9 I9 n5 U0 zDim lLngMod
. K7 q' B9 Q1 @7 u XDim lLngResult o9 w. |5 X4 s2 q4 u
Dim lLngIndex
' I4 F) L8 z# }5 HIf pLngKey Mod 2 = 0 Then 7 H: K% z0 \ v* a1 L+ F
lLngResult = 1 ! T8 w l4 o7 h) k) K
For lLngIndex = 1 To pLngKey / 2
" C% K5 u' l) f! x v& }8 j- q$ nlLngMod = (pLngMessage ^ 2) Mod Modulus 5 V T0 \3 R4 q9 n
' Mod may error on key generation
. z; B$ _) E( y$ \1 H7 {. jlLngResult = (lLngMod * lLngResult) Mod Modulus 2 L, F1 E$ D! G7 i- r
If Err Then Exit Function : k# r5 \0 {, Q5 U: \3 x
Next
; K O4 f' H) pElse : }+ ?7 [# D+ `( l
lLngResult = pLngMessage % q& B; i) T5 f$ v$ k5 Y
For lLngIndex = 1 To pLngKey / 2
( z: }( x+ y" |, e5 S! W' @7 HlLngMod = (pLngMessage ^ 2) Mod Modulus
$ Z. t: f1 N& _8 S8 n7 s& x" `/ pOn Error Resume Next
; A* @4 f1 r7 S' Mod may error on key generation
( [( F9 o% |' j0 S# ?: I8 XlLngResult = (lLngMod * lLngResult) Mod Modulus
1 A4 f2 u/ A0 |( EIf Err Then Exit Function & k! ^% j4 U& w- j2 B
Next / o7 Y8 ]: t- i8 `
End If
3 E7 v$ f4 i( i3 N' n n3 E' y# Q0 ECrypt = lLngResult ; V* E. d. v3 S& H$ `# o
End Function
9 K4 }9 L m) m' A f& a$ Y1 q
( G3 G' j! l0 r3 F9 f0 A3 M4 QPublic Function Encode(ByVal pStrMessage) 3 ~% F) E; b1 r. ~/ C* i* o9 T
Dim lLngIndex , d0 \6 R _# u5 f, M
Dim lLngMaxIndex 3 g1 b, R9 N) g) o
Dim lBytAscii
2 n% V4 J9 x9 r3 W% q4 m" PDim lLngEncrypted 4 E8 N4 H. Z& n% P; E
lLngMaxIndex = Len(pStrMessage)
* _' e! x$ t! Y/ KIf lLngMaxIndex = 0 Then Exit Function
6 G8 {' s9 \! iFor lLngIndex = 1 To lLngMaxIndex
- ?2 S" N) d) }3 }) b% @" \+ qlBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
4 q7 i1 o r6 h$ B& W& clLngEncrypted = Crypt(lBytAscii, PublicKey)
6 F+ M0 p7 q* M( u$ C1 B `Encode = Encode & NumberToHex(lLngEncrypted, 4) 4 _/ \7 b% g' @! S$ ~& p/ n. ]" Q$ {9 i/ ?
Next
, M) L3 I" T8 kEnd Function % w4 M; B# c% I! S* }
Public Function Decode(ByVal pStrMessage)
+ H' r2 w, ~! YDim lBytAscii ) U6 P+ ~/ z- l2 C+ S0 i
Dim lLngIndex % G) P, p t- S. y8 [
Dim lLngMaxIndex - R: U+ |' M, h$ a8 e
Dim lLngEncryptedData
- X# H3 X& s& \7 w+ o NDecode = ""
: l5 z' X3 h+ X: M' nlLngMaxIndex = Len(pStrMessage)
4 |- W, |1 L' ?# q! GFor lLngIndex = 1 To lLngMaxIndex Step 4
( B2 a- s2 {9 G/ X8 |lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
: S0 Q! B1 ~3 F2 \! JlBytAscii = Crypt(lLngEncryptedData, PrivateKey) , J, E4 l( w7 e6 s+ `. o# p
Decode = Decode & Chr(lBytAscii)
) m) g2 J2 ^8 I+ X$ q) m2 {' ^Next 7 y5 X' ?" I% p# U! s
End Function
6 I6 y0 M; W+ r& dPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
, K2 c C6 }9 j; }7 K4 |* RNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) . _ \% ]% W. ]8 T( G
End Function
1 b1 H# p( ` G* S4 PPrivate Function HexToNumber(ByRef pStrHex) - Z( _3 z4 ~: u9 V# Q
HexToNumber = CLng("&h" & pStrHex) / h k8 x$ q" u- q& @; |1 O- R1 F
End Function
* B( s% o9 ~/ h* J. v$ D" rEnd Class
, T* h% S/ u8 T% ?/ n4 v) I; ?* _function Encryptstr(Message) ; S* c( V8 H" t9 }* g
Dim LngKeyE
( V" H0 t: A2 rDim LngKeyD
) L7 d1 C4 H" e) @: kDim LngKeyN ' z: _" g2 }. k, O! {! R- S" N
Dim StrMessage
% q8 r( p3 u, r- GDim ObjRSA
; k% K- S7 ^ J* A$ }* FLngKeyE = "32823" $ f4 y: O( e1 X% V
LngKeyD = "20643"
9 O, d w0 P# l9 LLngKeyN = "29893"
1 w3 B% C! D1 O" \* k6 Y/ \' R4 SStrMessage = Message
% X: ?2 V B0 u% J% z; s; @Set ObjRSA = New clsRSA
- C- @3 Q& O9 x, L- }9 @ObjRSA.PublicKey = LngKeyE 1 u; |6 l1 q/ \. s
ObjRSA.Modulus = LngKeyN * K4 D" l. C6 z# a
Encryptstr = ObjRSA.Encode(StrMessage) 6 a/ D8 p9 k, Q8 Q0 V
Set ObjRSA = Nothing
& e8 |7 P- L1 N9 E% i* vend function
! ]& b% p4 F2 gFunction Decryptstr(Message) 2 G! e& D9 S1 c2 H: n ]
Dim LngKeyE 3 O/ ~% ?+ x9 L" |( v0 z' t' w
Dim LngKeyD 7 k* P3 l/ P# E. C7 i X
Dim LngKeyN
/ w1 q q" w3 Y: ]- \) qDim StrMessage
+ n: a0 Z' p v- KDim ObjRSA
, O3 p6 `" ~8 X' |" W4 rLngKeyE = "32823"
6 t0 M" X% f/ q& Y2 D2 B. @LngKeyD = "20643"
/ p9 Z+ P; J1 T) n' j' LLngKeyN = "29893"
/ T f+ _0 V( h$ `( g yStrMessage = Message 2 q( R( Z! m+ _. I$ f) H
Set ObjRSA = New clsRSA $ e1 r+ r9 {) C: \
ObjRSA.PrivateKey =LngKeyD 7 g# w2 j( l5 d: j# v
ObjRSA.Modulus=LngKeyN # r6 E- K& q7 g5 A
decryptstr=ObjRSA.Decode(StrMessage) 8 K7 b2 i0 q8 y; t" O$ p# V
Set ObjRSA = Nothing
5 e% B1 B5 m$ nend function & a! F4 r& P5 H8 G9 U
%>& O9 K4 T3 X- [4 y
===============================================
2 j1 d5 }5 c- {4 v w2 ~2 z3 E# D* q0 D, w
还有一个用于测试这段代码的test.asp
w+ c0 F3 T; m' A7 y y* l有兴趣的自己搭建个IIS测试下
. j" [6 X6 }; I L4 |1 r<!--#INCLUDE FILE="RSA.asp"--> ( l8 [6 ~+ j5 B) [$ G
<%
- I* C# V) B4 z: j) S& T6 t' \8 Xfunction Encryptstr(Message)
/ _5 i D. c/ r: v ~$ H8 D- V! NDim LngKeyE 0 p9 n y* d) \. o4 [3 Z5 A- y6 B
Dim LngKeyD ' p- w# Q/ D1 d( y. |
Dim LngKeyN ( e! S: E* ?, p1 V1 k2 G
Dim StrMessage ! Y: {! R4 B$ T8 c3 a& y/ C) \
Dim ObjRSA 8 L A( M; E# K& W! E( q
LngKeyE = "32823" " [; `: Y8 i: [$ A: @
LngKeyD = "20643" 5 S! r4 S, _/ z% g/ q
LngKeyN = "29893"
5 X* q0 ]7 ?6 v* HStrMessage = Message
4 h# h# o+ D6 ^- w1 w0 USet ObjRSA = New clsRSA $ \* K% d4 z3 |) u# a; b `
ObjRSA.PublicKey = LngKeyE
( c8 J1 q. L% W6 O7 eObjRSA.Modulus = LngKeyN ( [* `5 V% d! s1 s2 Y1 V6 K' a0 F( {' S
Encryptstr = ObjRSA.Encode(StrMessage)
3 [( G* @) J4 l4 M% F+ MSet ObjRSA = Nothing
6 I* ?6 B9 i4 ^* n- M% wend function
4 B" u6 @, B1 C5 t& c2 R' T# `2 b7 ^function decryptstr(Message)
$ l, ]* g$ N; E: J5 VDim LngKeyE
% Q& n T8 w5 f+ cDim LngKeyD s! W9 c! P# | N3 A0 h: q
Dim LngKeyN 4 Z1 X* D+ k, v6 f+ p8 q+ ?/ g
Dim StrMessage 2 j( H/ K5 U( q3 [5 b6 `. D" _
Dim ObjRSA
4 p' M7 V2 ? |& D9 A" iLngKeyE = "32823" $ V3 {8 b4 y' y1 d G
LngKeyD = "20643"
) n- f7 e2 |8 ?4 Y kLngKeyN = "29893"
& p1 D& j- q& ^% i. }StrMessage = Message
* W; a' b3 P% E4 ] j; aSet ObjRSA = New clsRSA * F1 u0 n, W2 D% U
ObjRSA.PrivateKey =LngKeyD
( K7 `4 s9 f, I$ c6 u$ r$ @, C' ]ObjRSA.Modulus=LngKeyN
5 {# L1 ?: R" i! ^6 ddecryptstr=ObjRSA.Decode(StrMessage) + v- c! J' J* ~2 E
Set ObjRSA = Nothing
8 p! S; j3 z7 k% Fend function
L- ~' }1 |# C& q% ]9 Ydim last,first
% Q9 z- E* G" r/ D6 a) f/ Cfirst="!@#$%^&*()" 4 D3 I/ w- k' V9 j
Response.Write "加密前为:"&first # U% V6 k8 W9 y9 T) P W' Y7 P4 ~
last=Encryptstr(first)
) X) {" l( B6 sResponse.Write "加密后为"&last
, |' u, ] i" q8 t% gResponse.Write "解密后为" &decryptstr(last) * g; V5 H% L! Z G2 [0 l) [
%> ==============================================. u1 ? B" p6 f3 k/ C$ b9 m" W
剩下的就是字符的对照表了
* Z3 N) v' {$ {% S$ s, c, G===================字符集================4 g0 \. _# ]% Q
1_____6EBB0 L! _ N5 f5 E' y7 H
2_____5C1F+ t3 [: j% K: V
3_____4D754 v8 ]6 |2 n0 P. @! h' @
4_____26CC
: `; c5 P% D% d0 D5_____4F88" f+ T) O; r0 P! b w+ A, I5 r
6_____3F4E- t, c' \3 R& A2 F. @0 }
7_____0A9D
# s) o. [9 B2 C" m1 o4 ]1 t8_____1A1C
9 ]& q/ O2 ~( a% a" t+ S# ]9_____6D20! l, b2 F( d; I. O
0_____1089
6 h+ r( B; d- ~% `- \$ P* Sa_____0F3E
& n) w& A5 S- Nb_____31590 \+ e" r1 Z( a( O5 i5 }) @, j
c_____3517
2 p. T/ z% s8 D' od_____419C$ M) _+ B6 A% M/ J7 H
e_____615C5 U0 x+ t3 t5 U3 h! b6 V
f_____556F4 B" q! X* q' l5 a; W$ e
g_____2B7F/ N; L3 }0 g9 ]) Q
h_____0F9C: p. g& b' b7 p; @& K
i_____00FA
5 A6 q6 |1 X/ @5 x, Wj_____5A50: S) ^) t6 y- x4 k
k_____2850
6 `: e X0 n% C6 g" x7 nl_____3E7B! @9 z% S' }7 q7 y8 I0 h" F
m_____71C5# u- g* P- f C) x G9 q
n_____1FC8+ u' s0 F7 X, Y+ f( {8 k" n+ M
o_____74C1
$ c" O% J/ q* B! jp_____5FB8' V& G% h4 V' U4 R4 e0 E
q_____6085+ o1 U4 k) ^* _8 S8 r
r_____3AC48 i+ O4 ` ?$ f8 R/ C# d% L9 T
s_____2F50' ?/ S) B( l- M' u: [) r
t_____36F8
; l7 ^% O3 G1 e) ^' [, mu_____7010
8 R0 y& S* R/ R4 S# Q+ _: H3 {- k" P4 Uv_____0B42
; I* o5 j1 Z* O g8 W# [6 tw_____1C7A
0 \# T6 ?& x3 X" P) i" d- ^x_____16F8
2 m3 U/ V6 `( f6 Ey_____2EE7* i0 W& E: l: E8 |$ @6 Q
z_____5CF3) b. d/ ^) Q" t! p2 W" S6 }( {
!_____6233
. |) n8 E0 g p, }& I@_____3A458 N: ?# i" i, U! a+ N8 {
#_____2291
: y0 F, X% J# R% t: E9 H" Q* F$_____5D5C7 K( Z: f% L3 Q7 h& \
%_____09B9
# ]8 v% `# K8 d7 K" l+ f^_____43EA
% r1 N! t( ~- e4 U) n; Q: `5 s&_____62B91 @7 B/ D+ c# R( c$ x5 s
*_____6301
3 m: N) Y n7 Z2 n(_____46597 d* \3 L2 P; o, g
)_____5C82 |
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