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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
* D, l2 A2 O$ c0 c$ D原始出处:http://www.3ast.com.cm" E* \3 b# \ x$ X2 g7 x
" x2 p, E- r( T3 [8 F
看不懂的直接绕过8 y4 ~9 J3 G, k Q9 E
加密前为:hwy123456
$ M O$ A8 E# \. A- z# ^8 N加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
0 F. ~) K" r3 {5 `1 Q& o1 f# w
) h: e8 s5 E; M/ h============================================
% Z! R# i. h; f( ?+ ~0 U1 |+ N上面是当时自己校内的心情。现在已经解破出来了,分享给大家
7 J" Y Q' F9 k8 |5 J& q6 ^也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法* }* S- F% ?7 W# _% F5 y0 w2 X1 {
以下是RSA算法文件) B$ p1 i7 O9 T
5 W/ B. I) Y$ n7 `5 |. d文件名RSA.ASP
/ n. i# w2 x1 S8 U, J* b: Z3 C===============================================/ r; B5 ?) |' a1 p5 D* b
<%
r+ e( t3 d& a$ V/ }* VClass clsRSA 3 q2 m7 i- B+ w$ P
Public PrivateKey
( S$ C0 N d' Z4 `4 a2 |+ `Public PublicKey
6 }# q0 j: }2 K2 |4 J1 @3 T( FPublic Modulus
& k1 ~ l; ^" pPublic Function Crypt(pLngMessage, pLngKey)
: s* B8 M, g+ {8 w- ?, lOn Error Resume Next : f% `; @7 f# c
Dim lLngMod + ^: D* ^$ Y: a6 e* x N, D. K% U
Dim lLngResult 9 l- Q5 ^" ^. g' }; d
Dim lLngIndex
# j" c: Z; `# C( ?; G5 WIf pLngKey Mod 2 = 0 Then
; F" Z5 s7 K! w9 O6 O flLngResult = 1 8 Y% Q+ W3 X/ T" X* K- v
For lLngIndex = 1 To pLngKey / 2
9 Y/ v! v7 E* QlLngMod = (pLngMessage ^ 2) Mod Modulus * a8 h& b' U( ^' K
' Mod may error on key generation
# U& _- y6 ]- ^) M _# F; B: ]lLngResult = (lLngMod * lLngResult) Mod Modulus ( p5 f0 [% O. ]/ P
If Err Then Exit Function : q& s* U/ W5 E; O) e+ I3 S- i& ]
Next
9 ^ q+ |3 ?$ s( ?5 dElse
- Z2 v0 O, [2 glLngResult = pLngMessage 3 L7 h' `7 J: S: Y; F5 {
For lLngIndex = 1 To pLngKey / 2 ! k8 v8 N+ v8 ~0 X7 d
lLngMod = (pLngMessage ^ 2) Mod Modulus 1 R* I5 {* |1 L2 a$ Y
On Error Resume Next
4 K9 P5 q' q1 \7 e7 T# z* Q/ A& S, N' Mod may error on key generation 2 [6 ?( }9 G6 S# j8 e& r/ E
lLngResult = (lLngMod * lLngResult) Mod Modulus
7 x) G4 q0 O7 |. Y f; v" E/ B1 F1 g- _If Err Then Exit Function & f: Q( Q7 E* U! f
Next . o/ k* t& D6 R/ B% P+ u
End If $ c& ], r/ Q& y5 Y* a9 l2 Q6 e. s
Crypt = lLngResult $ w2 z4 u" t4 H- e$ @
End Function
0 @* [/ g- g$ T" d, L% M: q: C" d' [; [$ m: A' b2 Z' y) W
Public Function Encode(ByVal pStrMessage)
4 {+ j* ~) T' P/ Q- sDim lLngIndex
+ Y3 g. k$ n) p. rDim lLngMaxIndex
* X# M0 X1 k6 f8 z- vDim lBytAscii 2 c7 l' m& _1 n( ?* J- Y% X
Dim lLngEncrypted C1 `5 D( V' T! J! O
lLngMaxIndex = Len(pStrMessage) : B0 C" |2 X1 Q' m( |' b9 O
If lLngMaxIndex = 0 Then Exit Function
# ^, N3 u! ` r kFor lLngIndex = 1 To lLngMaxIndex 4 @2 M$ H( _0 |2 V, O
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) # b9 {2 d" s9 u- D9 H% E+ T2 Y
lLngEncrypted = Crypt(lBytAscii, PublicKey) # q" }0 s7 X8 R" P, d
Encode = Encode & NumberToHex(lLngEncrypted, 4)
9 I; U$ S, n/ R- HNext # g' U- G1 ]: T+ W4 j
End Function
* {7 H% \, E- j. Z0 j3 G, N5 X( VPublic Function Decode(ByVal pStrMessage) / r7 l: |7 y2 ]. K# A
Dim lBytAscii
2 |. T( t8 V p: {Dim lLngIndex + I/ F! D: F7 U. L
Dim lLngMaxIndex ( U+ G3 C% m3 f+ y7 K* M
Dim lLngEncryptedData
. k8 u- g6 O, b% M* d$ ~Decode = "" ( j1 o9 V4 `; Y
lLngMaxIndex = Len(pStrMessage)
* J2 U, ~$ r5 S1 m. _( ^$ S: XFor lLngIndex = 1 To lLngMaxIndex Step 4 ; P9 P. j, |, G2 H2 p
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) & A, H. W7 s" p# K0 K% k/ e2 [
lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
+ z( D, F* X( I' T; y4 \: ^Decode = Decode & Chr(lBytAscii) " _$ |6 p0 ^8 b. _( R" f
Next
% O6 F8 ~! |4 U" X0 _End Function 5 H% a& H5 O0 j
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 3 n: n- s7 l. Q: r& }
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
. @2 t' f! w3 Y# ^6 Z9 ?1 FEnd Function ( h/ R- |$ L# k1 m, Z" K# l
Private Function HexToNumber(ByRef pStrHex)
% p2 H; @ k ~) J# ~1 uHexToNumber = CLng("&h" & pStrHex)
3 y$ f+ x; S) T% |" d: J* h, c4 ~' IEnd Function 4 G9 x. g- ?4 I# u' V7 a1 \6 @
End Class
* M6 q0 T- }. n( pfunction Encryptstr(Message) 3 Y$ s) D7 S/ i/ j7 I% r8 m
Dim LngKeyE 5 F7 H5 B% O3 \1 I- a
Dim LngKeyD
8 D" J) E) z6 G9 b: ?/ l$ }( o8 mDim LngKeyN ( z# A+ U2 D$ H
Dim StrMessage 6 H6 B! t" A }3 J2 y6 m
Dim ObjRSA
1 H9 k/ V( H q6 YLngKeyE = "32823"
/ ]2 t; |6 [# l" h! u$ TLngKeyD = "20643" * \# ^1 V$ e* @* u
LngKeyN = "29893"
0 S; U; c8 a0 J* T6 h Z$ QStrMessage = Message
$ @9 [& }% |" @( k0 ^6 kSet ObjRSA = New clsRSA
; n/ d7 r* T! o+ zObjRSA.PublicKey = LngKeyE 8 G3 U) o8 C" i$ }* Z
ObjRSA.Modulus = LngKeyN
: G$ i6 Y+ I! }4 j6 ?1 l* NEncryptstr = ObjRSA.Encode(StrMessage) 5 _. R- H- l, T
Set ObjRSA = Nothing * U) ~8 p! `' l6 \
end function! A9 U+ N' n# q" }) j1 X
Function Decryptstr(Message)
. D5 j2 {5 U* [: c0 `6 Y2 H7 UDim LngKeyE
0 c$ _2 y8 F; C# t) k7 c, ^Dim LngKeyD B& E/ H# V1 d/ C; S y
Dim LngKeyN
$ F4 j p# j; Q1 C+ D7 LDim StrMessage
$ y$ p9 O& \* F4 nDim ObjRSA 4 O8 X5 S# ^% q, ]7 Q2 H0 M
LngKeyE = "32823"
' ^4 o7 h m' H# BLngKeyD = "20643"
+ j! r7 Z8 I B+ d1 E m# LLngKeyN = "29893"
5 V0 c- ^: f! Q8 j; S* f) ~& [4 HStrMessage = Message
- g7 Z7 J0 I+ d& y4 jSet ObjRSA = New clsRSA Y+ Q, A0 l( y; ]" Y- V5 ]
ObjRSA.PrivateKey =LngKeyD
5 E7 R5 g# R V/ _4 WObjRSA.Modulus=LngKeyN
' h" W6 b1 k1 M4 L! `- ^: Edecryptstr=ObjRSA.Decode(StrMessage) - Y- G5 Z: ^# ]6 Y* ~
Set ObjRSA = Nothing
: x& Z1 |: Z, w* V- [end function + m! ` h0 L) u! H1 s$ ^" ]
%>
0 ?# ~0 U; U+ p4 y" I===============================================; c) H+ `2 h! t# f) Q: \
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还有一个用于测试这段代码的test.asp
( A+ ^0 Q3 a) U4 P有兴趣的自己搭建个IIS测试下3 Z1 m w' i8 J; B' i$ b+ a" t! R
<!--#INCLUDE FILE="RSA.asp"--> , C" f; Z0 k. c' y
<%: H/ o6 m: C4 f: p) z& `- c' X
function Encryptstr(Message) 1 v4 D$ p1 D( \! |9 T; d
Dim LngKeyE 0 w, v0 w- M( F M: \$ Q6 {' Y2 t1 p
Dim LngKeyD * {5 {! Y4 O; S
Dim LngKeyN , X* _' @; a% }! i- W+ L
Dim StrMessage - C$ z( N: m0 r: H9 h/ F
Dim ObjRSA
- T8 g4 U- v- e# ALngKeyE = "32823" z' V _4 t0 n6 `+ T* }- |3 |5 v( {
LngKeyD = "20643"
) b& s" P2 Y' D$ A% DLngKeyN = "29893"
- q" M( _. J7 T0 R' t- ~StrMessage = Message # k1 C' m$ E& j- G, N2 I
Set ObjRSA = New clsRSA
6 J7 `* X5 F: Z8 |/ k; o* fObjRSA.PublicKey = LngKeyE
7 ~0 ]( |( `0 E* IObjRSA.Modulus = LngKeyN 1 P% \2 {. q" Y6 D8 ]1 p
Encryptstr = ObjRSA.Encode(StrMessage)
6 `; K6 A0 j* P7 z: T( sSet ObjRSA = Nothing % ?! U% l! s: \# A$ @0 g
end function
5 g% g# ]1 g+ D" n( M$ {function decryptstr(Message) ; y! ?; s5 L! l- o( i
Dim LngKeyE & P; `9 A4 F$ a) p! P" A0 Y4 k/ G
Dim LngKeyD 0 z% `! W$ }2 u& E! H- p) Z
Dim LngKeyN 3 D4 j: C9 [+ S2 |+ V. t
Dim StrMessage 4 \7 Q9 U& e% e$ v8 b! D- r
Dim ObjRSA
" B: K: y# X; v: w6 GLngKeyE = "32823"
+ Q/ E1 ?$ _+ |! S% cLngKeyD = "20643" 0 y5 D+ `# o/ J2 Z: o
LngKeyN = "29893" / g; H$ U1 e( e4 n# J% D) m* [- Y
StrMessage = Message
' }7 [; {6 G. u+ f' I& tSet ObjRSA = New clsRSA : x. O' M \9 x" P7 c4 _" ^
ObjRSA.PrivateKey =LngKeyD ( s8 z8 [. V( K% v: Y1 @) m# v9 U
ObjRSA.Modulus=LngKeyN 4 u3 i% _& s8 p3 X0 i7 N. Y
decryptstr=ObjRSA.Decode(StrMessage) ) S6 z, Y" I3 G6 f2 ]+ V
Set ObjRSA = Nothing
- H/ @/ Y! L) n2 e2 Iend function
6 i. ?' \. F# t5 {5 x; cdim last,first
: ?7 I* T, |# ?/ ffirst="!@#$%^&*()"
. m: h5 d% [9 h/ I5 `* V! JResponse.Write "加密前为:"&first
, N# L& p+ G: E) klast=Encryptstr(first)
. \6 b( h9 X2 _# J! F) ? r, pResponse.Write "加密后为"&last 4 e+ ?( `7 r* `; d. u6 Y* O
Response.Write "解密后为" &decryptstr(last)
7 z, H, |! M- ~; f2 J%> ==============================================2 q. ?$ Q2 u8 P
剩下的就是字符的对照表了
& k5 R$ x+ o2 W5 k; D- n===================字符集================+ s3 ~2 r% R4 D( }2 P; c) O
1_____6EBB
4 N; _ I; t! U6 c; \2_____5C1F
9 \6 D0 V, [- R% @4 @3_____4D75
# J0 A1 P; x3 h' b! o _! c4_____26CC2 |. H& \( M8 q: Y! F- E
5_____4F88
3 t7 m% s% Z K, |1 d" B% l6_____3F4E
, T# u# p& b! {3 S6 a X" f7_____0A9D5 ?2 M7 c4 E5 t" X
8_____1A1C
- |+ \1 d; \8 @ W- s7 N W5 D9_____6D20
: I- d; `7 A1 c' _0_____1089
- _5 T( S/ d) f Z) F# s8 h0 T$ Ta_____0F3E
; E2 j% }- E2 m/ V lb_____3159
5 a; W1 T- z; ec_____35171 L- I1 R5 G' Z/ Z( d8 n
d_____419C! Q# t% P. c1 h! g6 P" c0 T
e_____615C8 d/ E5 j! E! u1 p8 d4 I
f_____556F5 x$ j% D! Y- Y* F
g_____2B7F
3 G% L! o' h6 ^h_____0F9C
, j) W" m# l# i/ ?& c& Si_____00FA
h' D5 ]3 e) Q6 }# u1 G9 O$ A" `j_____5A50; f* `6 |! E4 ^3 C1 y% Y
k_____2850% Y0 H' T8 c# Q* ]! @9 _# b
l_____3E7B
, J, x3 c( l0 A C- E4 h+ Pm_____71C54 X: e' K) X4 Z
n_____1FC8- _% C5 E7 `! A8 h9 L4 @
o_____74C1; N( w" K/ g" [; A* |0 D2 Y$ u# X
p_____5FB8 N4 ]8 n- O! E6 |
q_____6085$ K; u. A/ a: U
r_____3AC4) Y: W9 E. T- i% H3 R/ n
s_____2F50
; S0 h; S7 I1 @" Xt_____36F82 P' f: p6 Z( b+ Z# P Q
u_____7010
* |4 B. r( e/ |) av_____0B42
' w% E x& l( Y, g0 I2 R3 Nw_____1C7A# {# ? P& u0 f g7 c5 ]! R
x_____16F89 _$ k' I, T7 \( o5 G3 m
y_____2EE7
: O6 ]( t$ d/ {z_____5CF38 `( L. i! A7 `1 v
!_____6233, S) w: T6 b6 c+ y
@_____3A45, O7 l: [: X. X
#_____2291
- u, l0 F- M6 y+ r2 k. F1 U$_____5D5C* D$ ]0 v' z: ]8 E4 Z
%_____09B95 S L' v# t! A4 U0 n5 E& G I
^_____43EA6 R3 v- M4 O7 c3 |; Q% a- `3 A
&_____62B9. [, V, @' T8 h6 ~0 a
*_____6301
, Z# V2 |! u7 Q* _" w; L: H(_____4659
6 A& t! O: Q2 W* k( h& ^8 f)_____5C82 |
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