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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
F8 i7 j2 m5 G" D原始出处:http://www.3ast.com.cm* h2 B$ F0 u J7 Y, s. f* Z6 I
0 R- m# v: h) l- ^看不懂的直接绕过
6 ?# W1 E" F8 c: T" y加密前为:hwy123456/ L! a$ H' ]4 c8 _
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
% d/ h/ e6 H; u/ s e2 }$ r' R$ f% H5 f: q
============================================
2 z! C- A+ ~" b4 S9 e0 I- [" T' N上面是当时自己校内的心情。现在已经解破出来了,分享给大家3 H* y8 w, x4 k, v5 A5 z7 W$ ^
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法$ \) E: j0 [, O
以下是RSA算法文件& o3 D; X- f: U
, S0 |: O0 S( g9 m# X文件名RSA.ASP
0 j3 v/ V9 H* P4 ?+ k===============================================' Z) h4 t3 k3 q& t
<% ( t( L( s6 `! X, `9 l* b: H" s
Class clsRSA
' G' [! h1 m% {0 ^Public PrivateKey
+ R, X+ \% P7 r. f* }7 lPublic PublicKey . M+ Q+ t; u; e( k9 f Y3 L' z% a. K5 J
Public Modulus
[( S( ~% I& q) wPublic Function Crypt(pLngMessage, pLngKey)
5 u* \$ g. y7 w3 S, D( k. ?) zOn Error Resume Next
; r3 ~; M; G! J: dDim lLngMod * a1 V+ O9 Q% V* e6 _0 @; i
Dim lLngResult
% p3 C0 x; }# k+ W/ f6 h) ^Dim lLngIndex 8 j8 |( m& k2 h" Q7 U
If pLngKey Mod 2 = 0 Then
8 R4 [- X) d4 q- p- t+ rlLngResult = 1
; V" p1 X D) j' h& M$ X: XFor lLngIndex = 1 To pLngKey / 2
8 h# @- ^7 z+ k, }9 J2 k+ _- IlLngMod = (pLngMessage ^ 2) Mod Modulus 0 p, u0 O& B6 O# e, K, T
' Mod may error on key generation
" l2 h( h" q6 J& c) VlLngResult = (lLngMod * lLngResult) Mod Modulus
( T) C. w8 C6 s: |% M/ |1 xIf Err Then Exit Function % ]9 A+ ]* k' v) A! z) E
Next
7 i( P8 P) @1 b& VElse
8 Y( U2 e1 f9 o2 S* w$ n, z5 klLngResult = pLngMessage ; Y5 O: U7 J4 G3 a% B
For lLngIndex = 1 To pLngKey / 2
\8 @1 ?) W0 d4 ^ z" U+ PlLngMod = (pLngMessage ^ 2) Mod Modulus : Q2 A$ T& b6 }6 R+ I& b
On Error Resume Next
2 t6 Z8 u1 A! ~- f- d' Mod may error on key generation
) ^1 Z- |3 B" y+ u; G( x7 \) I1 k3 GlLngResult = (lLngMod * lLngResult) Mod Modulus
( [$ _) q* I, P# d" D% pIf Err Then Exit Function ' [2 ^1 e( h8 i/ {4 l0 |- U! Z
Next & T" ?( s5 k# R! `. Q
End If 4 |% p8 b6 W8 q2 q8 ], l
Crypt = lLngResult 9 ]5 M, O8 W" C; T6 B6 _. j- \/ a q
End Function
& V8 a8 S, o7 j- B+ \) ^
! v! J3 r$ K* S* _$ j2 FPublic Function Encode(ByVal pStrMessage)
2 I* i" ?) J: P- MDim lLngIndex
6 l/ A0 H& i) J9 S* w) @" \4 L* x7 s. N4 hDim lLngMaxIndex
) u! f; R: M, B) l- LDim lBytAscii
4 C2 x$ `7 P8 p' J4 N6 LDim lLngEncrypted
! F/ i+ i5 r. e& D8 ^7 ~lLngMaxIndex = Len(pStrMessage) . I& N, F: J3 M, N* p2 W
If lLngMaxIndex = 0 Then Exit Function
, p2 p# u/ t; k' HFor lLngIndex = 1 To lLngMaxIndex
5 }* l; g2 s! q" p# HlBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) : E' b7 a! x( Z( T3 x
lLngEncrypted = Crypt(lBytAscii, PublicKey) 5 q+ n9 T: j) j J# W, t% Q
Encode = Encode & NumberToHex(lLngEncrypted, 4)
' F/ R; f6 _4 BNext w6 |6 ~% O. p- a! f( t
End Function ( R6 u" @) Z& @
Public Function Decode(ByVal pStrMessage)
( L$ I$ M R6 ]9 x4 n6 i- yDim lBytAscii
- Z5 F8 z6 I, S& `" d ADim lLngIndex % o! j2 L2 B1 h7 w, v& l+ k
Dim lLngMaxIndex 4 y6 I3 K+ b- s6 m2 a
Dim lLngEncryptedData
( Q5 C: B3 y+ |, V) LDecode = ""
! S" m. ~( e9 q/ v# X. J* I% ZlLngMaxIndex = Len(pStrMessage) 3 `. n9 m# x2 ]; @. P5 K: P$ r6 c
For lLngIndex = 1 To lLngMaxIndex Step 4 F# W+ e2 z1 w% U) b9 m
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
" ~! I3 ~) ^9 @lBytAscii = Crypt(lLngEncryptedData, PrivateKey) 8 U. U. H. h& r4 Q
Decode = Decode & Chr(lBytAscii) ' d8 y; Z. Z' n n: W m
Next
$ v/ H6 x. ]0 KEnd Function 9 T2 u% g& k# h: ?# `# B
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
) d2 N$ R/ _1 H9 o( u T! L8 nNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) # i9 x* a. e/ S5 O! I
End Function ' ^3 ~5 a* i# A
Private Function HexToNumber(ByRef pStrHex)
" @6 @; q9 I f' K& x2 i3 x- z5 cHexToNumber = CLng("&h" & pStrHex)
) E& @- Q4 s o2 F& {1 N; M* eEnd Function
6 g' K7 W" c9 [; j& pEnd Class # J$ E; {* P) L$ K
function Encryptstr(Message) : k; a4 L, C) c( C) S# P" P
Dim LngKeyE 9 p' w6 b# r# D6 u, X. L
Dim LngKeyD
9 F' Q& Y7 l9 H0 P$ U0 _& _* sDim LngKeyN
" A4 m a0 Q% @5 P( S# YDim StrMessage
' J) L& N( r3 F n" F7 {2 IDim ObjRSA ) ?% U( G0 g7 ?* p
LngKeyE = "32823"
2 I* G9 l k8 R8 z& tLngKeyD = "20643" 1 w; y* V3 Q5 N8 D
LngKeyN = "29893"
% w+ S" {9 F2 F- Z# QStrMessage = Message
( Q+ i8 q3 \4 i+ ?. vSet ObjRSA = New clsRSA & P- o/ `8 S- W. G0 D& d# ?
ObjRSA.PublicKey = LngKeyE
1 F5 W+ D) u) J) g7 f- PObjRSA.Modulus = LngKeyN
9 y& V: Y" N. V+ CEncryptstr = ObjRSA.Encode(StrMessage)
' e" Z" Q- \1 hSet ObjRSA = Nothing
* j" p& A: A; Aend function7 D* y9 {0 l' K( j$ K% I6 F4 J
Function Decryptstr(Message) $ g* n6 s6 g- D+ U
Dim LngKeyE 1 i; v8 N! e2 q5 Q0 H
Dim LngKeyD
" U5 u7 s8 c# z0 `# K$ p; sDim LngKeyN 0 V4 a; H0 n0 \3 M6 m) d6 M
Dim StrMessage 0 C5 x$ E' _5 z: }1 V* c
Dim ObjRSA
% r. A. ~5 Z/ G9 f2 sLngKeyE = "32823" 7 t$ t; f/ K+ |3 s1 y3 G
LngKeyD = "20643" 0 |( `- D* T, i; E
LngKeyN = "29893"
% _1 R# u; R* M. }3 }StrMessage = Message % w4 d3 b* h6 C9 w
Set ObjRSA = New clsRSA ) m" c$ X( S( h" y
ObjRSA.PrivateKey =LngKeyD
2 |/ P2 B0 g; y9 @& DObjRSA.Modulus=LngKeyN
$ _) X" x2 o" {! C+ zdecryptstr=ObjRSA.Decode(StrMessage) 8 s! c: ]& {0 [2 [; c* x% w3 E6 ]$ k
Set ObjRSA = Nothing A7 U1 q r: x( C* p" @- }
end function ) V9 P2 R2 ^5 Z' Q* N* w- k
%>
3 L g- l- K) ~- S% x9 U2 ~- w% `===============================================
" M3 T, K! d$ V5 Z$ |
% J" M+ t. B) |$ |; l7 {- ?还有一个用于测试这段代码的test.asp
. A: C7 a) R3 L9 R0 X7 H有兴趣的自己搭建个IIS测试下
8 y2 w* l- V. c" r3 ~9 v6 Q, D- i8 }<!--#INCLUDE FILE="RSA.asp"-->
; M) q4 e1 Z5 N* E<%, }% \- |6 J7 Z' I/ G8 t- M6 J6 W
function Encryptstr(Message) . F. F4 Y) G V# W$ G) P
Dim LngKeyE 9 S3 p" ]2 E0 h- m. B
Dim LngKeyD 9 f8 Q2 Z, M$ d( V c' {
Dim LngKeyN
/ c" r; y2 s: l; T, oDim StrMessage
3 G% x0 P$ y ~' U: W ]" NDim ObjRSA
- G; O& d C. T2 f! ?LngKeyE = "32823"
* _& g6 D+ ~0 h1 ]1 ELngKeyD = "20643"
2 R- C! ~+ U0 `LngKeyN = "29893"
$ k( i5 m) J2 B( x* wStrMessage = Message
; T6 `, K# K) L8 X7 sSet ObjRSA = New clsRSA
, w& d8 V1 `1 Y( Y1 gObjRSA.PublicKey = LngKeyE / G9 @ E! P, T! |3 {; e
ObjRSA.Modulus = LngKeyN $ B& G. C% P) H/ P' A/ b( h
Encryptstr = ObjRSA.Encode(StrMessage)
6 ?' U& H- p: ESet ObjRSA = Nothing
+ u# r- c* I& ?0 ?4 \* C& Iend function 4 ~7 w1 b/ k6 O3 f& F4 A0 I
function decryptstr(Message)
( I9 i! @8 {0 m5 Z% I b- F4 JDim LngKeyE
, Q" G4 } y |5 x2 O# `) {( j: kDim LngKeyD
, B; I+ _5 c i$ VDim LngKeyN
u, u" s" z2 V9 s# _/ f6 h$ @$ eDim StrMessage 7 H5 s% @ H3 ~- V: D. Y) F9 {
Dim ObjRSA / q" c1 a! n6 v$ H6 F# }
LngKeyE = "32823" , V0 Q2 d$ @# s) M3 h( b) G
LngKeyD = "20643" 4 J0 l l5 h! |0 f2 `6 ^1 I6 s
LngKeyN = "29893"
+ H3 ^+ L9 }7 GStrMessage = Message * \/ _( _! b) ?+ P/ Y# K( j
Set ObjRSA = New clsRSA " B9 D6 H1 R! R
ObjRSA.PrivateKey =LngKeyD
1 @# S$ Z+ N, h, ~ObjRSA.Modulus=LngKeyN 0 f1 e+ c# X2 | Q3 U' @: V/ q, ~
decryptstr=ObjRSA.Decode(StrMessage) * O* f9 w: y0 v
Set ObjRSA = Nothing - ^0 o# }2 u6 U9 C, Z0 o/ j9 i
end function , s+ k/ z/ X' G1 M
dim last,first , f8 R- X5 W* ~+ m& t# x; t
first="!@#$%^&*()"
' q5 b; b/ [$ r/ ^/ z% S% tResponse.Write "加密前为:"&first $ d6 V0 }9 y8 Y; ^! h
last=Encryptstr(first)
, u9 Z3 n0 c+ OResponse.Write "加密后为"&last
$ ^5 n- {" _8 L0 d5 E2 lResponse.Write "解密后为" &decryptstr(last) $ y% j5 m! R7 L* P/ n
%> ==============================================
4 {- j9 @! i' ?) m' p剩下的就是字符的对照表了# I$ x' f6 r4 Q0 ?: u8 x& v
===================字符集================
$ \; Q! `0 E: M# A$ ^. W$ g9 b8 |3 L1_____6EBB
' ?9 ^0 x1 W3 [* d# u2_____5C1F; _1 O2 }$ L ]7 I
3_____4D75
; J8 I( X1 i5 j& K0 h; b, p; H- I4_____26CC
_% V( n5 m2 y0 p# O5_____4F88
+ O7 }1 v$ `8 V2 \8 z4 L6_____3F4E
8 N9 Z W6 [/ y7_____0A9D1 }7 G8 e" |% M4 H
8_____1A1C1 N9 e0 T+ t$ V+ f
9_____6D20
# D, {7 v4 Q* z0_____10893 T6 k9 J6 L, o; G" k" e% T! h
a_____0F3E
1 j* f6 Z8 T i- G! o( Gb_____3159
4 M1 W3 n9 u& ^- Xc_____3517
" e' O' V D) M4 s g+ ~d_____419C
p4 i3 y7 L' o5 F0 ?8 N2 X# }- y0 R' ue_____615C
2 R- F) ]% p, _3 ff_____556F
# m! D) s: b% a* X: n1 |' ^# F: pg_____2B7F5 X3 r2 @8 B. N! U V
h_____0F9C5 `" {$ X0 n" w2 s' w3 p
i_____00FA% s8 ?4 S) G+ s% q7 A, \" ?
j_____5A503 }8 \/ x4 J. H$ a( t
k_____2850
" s2 M- z- ], O z5 Hl_____3E7B
$ A# h/ `+ { o. d2 D% bm_____71C54 c" C' |2 E- m
n_____1FC8
* k8 v& t1 {' }. w5 n1 g# O4 Q5 B3 mo_____74C1
) B. M2 l$ u V5 x- O5 Ap_____5FB8( L+ x% F+ j# x
q_____60852 d$ t* I, m* n7 A
r_____3AC4
7 c: a) N/ |9 U9 Ws_____2F50
. P" A7 Y2 w% H. [t_____36F8% f2 z& ?) k4 f7 g2 Z
u_____70100 E3 Q3 r6 ?& Y0 d, Z$ R3 O" e
v_____0B42, m( Y3 _% \. f/ W
w_____1C7A+ P9 D8 F; K ^0 T& {8 k+ Y& {
x_____16F8
6 Z0 k# w* F& L* N' B+ sy_____2EE7
6 F& h% j- p; Q v" Gz_____5CF3
/ N2 m. J4 ^2 r( T4 c+ O5 H!_____6233
+ V: g8 M ?% n9 d8 q4 }@_____3A45
& \( }5 b7 D. N* _/ {" t#_____22917 Q8 `. O& \4 V' d% ]/ X$ D' ]
$_____5D5C( Y4 E5 f; S% f6 t$ V6 E" N1 U: W
%_____09B9
1 P/ W6 `% Y3 S* C0 }^_____43EA4 V! }9 N [0 r9 K' A: _1 s7 u
&_____62B9
$ a K3 Q; h' R. x4 B" I$ Q*_____6301
h1 `! C; d$ e0 D3 m) w4 z# U1 I+ R(_____4659
+ R5 |3 Q- Q. |1 S0 ?- M' _)_____5C82 |
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