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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm) F" R7 \8 i4 z0 F8 z
原始出处:http://www.3ast.com.cm" k7 s" ^. w* Z; v
/ H R7 D8 t% g& K3 F ]2 \看不懂的直接绕过2 [6 i/ B' q: f. _
加密前为:hwy123456' c" o& M V) ~# J% t, p$ f! \- p
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E% C8 N5 V- c5 [7 t% t9 U
3 q. I) M+ I' P. k( N
============================================0 R0 a) I& ]. o$ L6 a" F8 B
上面是当时自己校内的心情。现在已经解破出来了,分享给大家7 Z; }( R# `0 x3 \2 |
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法5 }& j0 w& r) |- g$ d3 x
以下是RSA算法文件/ C& W) M2 O& [" a/ P* a- @
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文件名RSA.ASP) y+ ^' ]& {% E5 p+ q( ]6 L2 l
===============================================# k! ~" v/ m: @8 r
<%
5 z% I% J- u: ?$ x. K& zClass clsRSA
* U+ E7 f, E6 C) k! e7 B7 {8 FPublic PrivateKey % E8 j" w' q; }- C4 q3 F3 s( ^
Public PublicKey ) g4 M) f4 ?, z3 p
Public Modulus y( g$ [+ j! R% H1 k+ U+ b* @' I
Public Function Crypt(pLngMessage, pLngKey)
* A' C9 ^ @4 X( ROn Error Resume Next
4 [. ]4 Y+ S; ~& aDim lLngMod 5 h: }* V3 ]: O$ q3 \
Dim lLngResult
, g4 K- S+ y; G- B6 FDim lLngIndex
5 |1 |# [ _2 l$ y6 |1 e9 e7 c+ qIf pLngKey Mod 2 = 0 Then $ ?( b. ?5 i$ e
lLngResult = 1
0 i6 Z0 i2 F4 uFor lLngIndex = 1 To pLngKey / 2 & ~/ R- R7 {% P& o1 b. h
lLngMod = (pLngMessage ^ 2) Mod Modulus
0 X: N8 [% m( z' L- F% e7 b5 ]5 W' Mod may error on key generation ' G! O' ]4 t3 a9 i U1 x" ?9 _
lLngResult = (lLngMod * lLngResult) Mod Modulus 7 c% |5 i4 B, ]8 r
If Err Then Exit Function
3 ^/ g2 Y# D) M& O- CNext + s/ k* P0 y; D. J
Else
- [/ h. G/ @3 v" n8 |& b5 g. UlLngResult = pLngMessage
; J7 O _2 R# g2 N: r; Q# G- dFor lLngIndex = 1 To pLngKey / 2
0 z4 i" X9 m7 p, l; AlLngMod = (pLngMessage ^ 2) Mod Modulus - s) S5 n) h8 S: M5 C c9 z3 Q4 N
On Error Resume Next * r- o7 q4 ]6 m5 O
' Mod may error on key generation 9 n4 J7 X x: u
lLngResult = (lLngMod * lLngResult) Mod Modulus
# |. @2 X- I* uIf Err Then Exit Function * U; V: w6 \/ @- r1 l+ Z
Next ' ]6 T9 F- N5 m& E6 K6 f: C
End If
/ x9 z( c: A) ?: A0 RCrypt = lLngResult , r. ~/ \, R0 n$ A' m, q9 j5 y
End Function
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" o. B& X. A) S9 K1 K* K8 R" SPublic Function Encode(ByVal pStrMessage)
S6 U" E$ o4 B4 KDim lLngIndex ( l) [: b" e) E) ?' L, L& [: v
Dim lLngMaxIndex
' B( h0 S( j' a' t/ jDim lBytAscii ( K5 A# r# O+ i; b
Dim lLngEncrypted
. A; j9 M! t3 B( \7 a7 c K( NlLngMaxIndex = Len(pStrMessage)
4 t# h' M* d# ~0 v$ E; DIf lLngMaxIndex = 0 Then Exit Function
9 @, F+ N9 M3 f% i+ H/ E I1 pFor lLngIndex = 1 To lLngMaxIndex
$ q0 }8 g) T" J7 _lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) & w$ E0 ]$ k; `4 r. Z& N. |" Y X0 {
lLngEncrypted = Crypt(lBytAscii, PublicKey)
/ B' Q5 z" Z" `7 }- iEncode = Encode & NumberToHex(lLngEncrypted, 4)
( x! m* u. e$ dNext 0 R" P* R0 f9 ]" v
End Function
8 Y0 F! O' {5 |" BPublic Function Decode(ByVal pStrMessage) : Y9 v. |% {/ W# o
Dim lBytAscii 9 b% ]! t1 [9 {0 M, ^8 ?
Dim lLngIndex
2 q9 C# P5 }1 J9 G( MDim lLngMaxIndex
' v3 c2 J7 T. J0 ~7 w- \. i# J0 uDim lLngEncryptedData
( \( @# ]( p; D: q$ a( RDecode = "" 6 |3 M( ]5 @. J3 x' l2 b
lLngMaxIndex = Len(pStrMessage)
* g4 U b# h9 Q/ W, OFor lLngIndex = 1 To lLngMaxIndex Step 4 % U) D, l: j. R& q! o
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) . r4 N1 v6 @8 ~1 x' N; \ x
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) : T7 B/ _ N% B6 H1 I1 A" X6 G
Decode = Decode & Chr(lBytAscii)
, L" E: w% c/ f0 r" vNext
z+ R: n- t- vEnd Function 1 ~2 I: N. c- z; o) j; b
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
+ s' H$ c# m! q) j3 i" GNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) $ E) R- ]3 c O2 [
End Function
2 K3 Y. `8 x2 u; X* l, f3 \& QPrivate Function HexToNumber(ByRef pStrHex)
' X9 D2 X: q4 x$ U: y. \HexToNumber = CLng("&h" & pStrHex) # A8 l; V; f3 M: ~
End Function 0 Q$ r3 m: N3 L( B" z
End Class
+ \2 N8 d) O5 T, Y$ W Wfunction Encryptstr(Message)
! l! _ o% y) F% V$ PDim LngKeyE * C! H9 m! J+ a6 w7 x
Dim LngKeyD 0 C S( C. [, T8 a7 Z& h
Dim LngKeyN
$ B; G+ O' U) E, {Dim StrMessage 8 T& X% ~9 D8 `7 L. }
Dim ObjRSA ; \3 M. _/ b, W% f9 ]
LngKeyE = "32823" 1 r8 H4 N) I: Y- [
LngKeyD = "20643" 1 f& u4 [+ D5 h/ e- |* j6 W
LngKeyN = "29893" : d t8 K6 A$ O) e
StrMessage = Message " U% S3 I7 ^% |3 ]) F
Set ObjRSA = New clsRSA 7 H! K. v: H2 p' s* q- ~7 I+ t0 |
ObjRSA.PublicKey = LngKeyE
. k% o0 o1 ~( G" L) A- A! l% {ObjRSA.Modulus = LngKeyN
9 I- R' q( Z: x# S: d; b, wEncryptstr = ObjRSA.Encode(StrMessage) - v2 S3 }: T: {* Z/ [! B
Set ObjRSA = Nothing 2 ?8 ]% _: m$ H9 [' f+ ^
end function
: l% C: c. Z, f. F9 sFunction Decryptstr(Message)
2 j, D) m% j- H, K9 J0 X) ADim LngKeyE * P S: L0 |4 a& ^" z: e
Dim LngKeyD
' ]' V7 j# L- C6 aDim LngKeyN 0 S# I$ @4 }7 e. ?2 u9 p
Dim StrMessage
3 T% A9 V! b0 \Dim ObjRSA
! N3 j4 V) p- `* o4 I$ l* \LngKeyE = "32823"
- R% X3 S$ t j/ g) X- tLngKeyD = "20643"
9 O @: M, ]5 \" I7 ^LngKeyN = "29893"
# l; b' M, X2 @9 a% g4 fStrMessage = Message 2 Z4 o% ^+ {0 s1 S# E8 H4 p9 {1 n& \
Set ObjRSA = New clsRSA " O& D7 l) _5 j
ObjRSA.PrivateKey =LngKeyD , e. M% s; r/ o! p' ]
ObjRSA.Modulus=LngKeyN 7 L/ n! u/ F! F+ z! _* L
decryptstr=ObjRSA.Decode(StrMessage) 1 B; V* o* K6 n! @; k3 W: G
Set ObjRSA = Nothing
- |) s3 O! i' K9 Z% P9 b+ A% dend function
: o. V& z- g" a- ^. a+ H%>+ U1 @1 n* |. \7 s6 @. b" ?
===============================================
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! t' s- V) }: y还有一个用于测试这段代码的test.asp% E' q# u. f/ {
有兴趣的自己搭建个IIS测试下+ a! b2 z. s9 V+ X
<!--#INCLUDE FILE="RSA.asp"-->
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function Encryptstr(Message) q' H3 S3 i, s! y, Z _5 N
Dim LngKeyE
. N& s. ? b9 G3 _2 Z" UDim LngKeyD
1 O; P3 H: ?% S. b, VDim LngKeyN
8 o5 g/ q# i/ x1 xDim StrMessage
8 a' ~* Z& l$ r- M. P! _8 lDim ObjRSA ) a$ A+ K* O3 D% q, k
LngKeyE = "32823"
4 R4 i4 z# r! D" }) ?LngKeyD = "20643" & N, V; J7 C Z1 d$ |4 C
LngKeyN = "29893"
; a4 w- D# n0 ~0 zStrMessage = Message * [' X. ^5 m/ G$ ]
Set ObjRSA = New clsRSA . U* I/ J) m% w6 l4 p5 K& j" N
ObjRSA.PublicKey = LngKeyE
( }: D4 Z6 i" k6 A/ LObjRSA.Modulus = LngKeyN 8 N8 @; C+ l) P' o( F
Encryptstr = ObjRSA.Encode(StrMessage) 7 B7 ^6 ?5 b' y: \! }( _
Set ObjRSA = Nothing 1 Z8 N/ }# y% h. _8 H r+ l
end function
H& J9 \$ b* O( p9 ?, M# ~& afunction decryptstr(Message)
& s" L$ O* F1 m% R- R3 Z: v) CDim LngKeyE + c% `& e2 L, ?% y5 {: {2 O
Dim LngKeyD
$ `: u% o# ^2 W( Z* O$ M' O6 MDim LngKeyN
: S) W2 K' z2 K8 E. R! q' eDim StrMessage
5 C( l* L4 _: m$ X; a0 s0 CDim ObjRSA
- I' _; P& V* C3 `. t. YLngKeyE = "32823" $ h( k9 s3 p+ }) ]3 F, r [
LngKeyD = "20643"
- }9 G3 q" X: A) \: V4 mLngKeyN = "29893" 0 D7 j) G. X: f& U7 E8 o0 X
StrMessage = Message % u, v# T" X; M8 G* ^ r* u2 o
Set ObjRSA = New clsRSA 4 q8 ]1 ]: C& R
ObjRSA.PrivateKey =LngKeyD . `0 r" _2 e) Q& e" c: Z" u
ObjRSA.Modulus=LngKeyN
3 [% T8 c/ v* H W& Rdecryptstr=ObjRSA.Decode(StrMessage) % v! l; z$ J% O$ J
Set ObjRSA = Nothing ! [7 n; x# Y6 _# i" [& K
end function
% X2 S; ?: \6 l0 Z7 }dim last,first
6 w5 S# j: K' Ufirst="!@#$%^&*()" 0 L, ~& `# O; w) @/ z
Response.Write "加密前为:"&first
* q& o; G5 P j0 p+ B) L7 Y5 ^2 u$ Plast=Encryptstr(first)
3 v7 z$ T4 {' E0 [- {; cResponse.Write "加密后为"&last # ^, C" F5 f' n7 y. l
Response.Write "解密后为" &decryptstr(last)
3 V1 `# v' V( y4 q) R" K%> ==============================================+ Y$ E6 A" | x# _$ c
剩下的就是字符的对照表了
! Z" w8 K; u! n$ h===================字符集================& j$ u- R7 w. k, F& V( K
1_____6EBB
( V2 b7 g4 h) F* `1 K/ _- D1 n T2_____5C1F
/ O& a1 G0 @9 U( _ T3 }& x3_____4D75
" G7 b8 j9 P1 m! W4_____26CC
# I2 R4 \3 i4 M5_____4F88
' n4 N. j4 F- k1 Y9 z6_____3F4E
* ]# ^+ ?5 v' M' K0 D7_____0A9D
( c, c$ I/ S1 z2 u. v/ x* T8_____1A1C' d- e6 v' D# B
9_____6D20) F9 d( S5 ^5 M4 S* l$ _ ?
0_____10893 P8 D% R1 n1 H* R' M
a_____0F3E" V. ^& W# k. {4 z. a+ |
b_____3159; d3 V- ~4 g; y% X% ]: a* H
c_____3517
% D& o( }% r) \8 p5 O: |7 \d_____419C3 G0 S& l! i' U) @
e_____615C8 s# H( o1 |6 H
f_____556F3 M: y" j0 J- A* Z$ [
g_____2B7F8 E6 K1 a7 m' b/ y9 d
h_____0F9C
! d2 `4 R; G1 y0 G. ji_____00FA$ m1 Z, z4 H5 e$ C* m' s
j_____5A50
5 w" O Z5 Y) V! `+ e7 T0 Ok_____28501 }% {! w7 q5 ^2 e& e/ W9 s
l_____3E7B
9 G5 E7 F# g& xm_____71C5
" O/ W! l3 | o! Bn_____1FC8: r- ]! ?9 t$ E+ i) @
o_____74C1- f# `! Y; j/ l7 o1 a
p_____5FB8
3 [. \. k3 p: E2 |$ E* B5 p. |q_____6085
' V0 C) C8 e; sr_____3AC4
6 P7 J, J, `5 R; F1 N% g, os_____2F50
, J3 O ~4 I; P$ n/ Qt_____36F8$ N) k' n/ o% [1 N8 c! k+ I
u_____7010
8 c0 ?* I* f% x1 U1 I ^v_____0B42) g' w6 S- E# U
w_____1C7A
2 A8 D9 s$ E& c7 e7 g- c3 j& [x_____16F8
7 d1 P- ]4 F# z2 V* Qy_____2EE7
* @# n2 L" X: z' m+ W. rz_____5CF3
1 w: K- W$ _% B1 f$ D& c2 F. K!_____6233
$ {* l3 }5 i5 t4 H( y7 x@_____3A451 s, T. a% J5 D0 c7 r
#_____2291! M8 B' [$ ^$ \: b+ P! J
$_____5D5C
8 g5 s' ?4 S' Y%_____09B9
7 _! R5 g. p6 u5 H2 b: w; u3 \% w7 l^_____43EA9 J* I$ u& _. ? u/ n7 X
&_____62B9
; q$ d- x* t( Q/ n+ U9 J9 R*_____6301
' r: W: _+ q! ~5 Q(_____46595 C7 }& P+ ?2 F X8 F
)_____5C82 |
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