|
    
- 帖子
- 3852
- 积分
- 13044
- 威望
- 16780
- 金钱
- 36761
- 在线时间
- 1139 小时
         
|
原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm s$ x0 x7 {9 Z b' U* n) T
原始出处:http://www.3ast.com.cm
3 u( c% d8 Z* k* e+ J5 F
+ s- L+ h$ q) f2 Q; p看不懂的直接绕过
' V( _1 l \9 n, v/ C1 g- w加密前为:hwy123456
5 {8 u( t, W$ f& G加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
2 M: E; C$ ^9 p" Z( A
5 z1 s7 R2 R) q' g4 K6 d+ @8 ^$ y============================================
4 q9 C/ f% `/ F, j上面是当时自己校内的心情。现在已经解破出来了,分享给大家
! `" L4 w0 Q6 S) w也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法6 J/ q3 l3 m8 L( l1 _$ X3 @/ z
以下是RSA算法文件) C5 E- A4 A. k% }8 Y7 e3 q
! y4 k- e% T2 n5 o4 h* h文件名RSA.ASP
1 R# W- l, p7 Y& d g& u7 p===============================================
1 }) G$ i8 A. V1 x" y<% L Q1 W% y1 c; y: _' Q& f0 C7 T; k
Class clsRSA
, g8 T) `0 p, w* K- B7 Y4 S5 |Public PrivateKey
! {$ D1 h% d; o) w# GPublic PublicKey
5 Z( I) e! Y4 l& ^Public Modulus
0 a0 E9 O5 b+ _4 P, sPublic Function Crypt(pLngMessage, pLngKey) 0 K# T- a" \5 h# X$ d
On Error Resume Next ; j+ q) ^0 B8 _ r+ S4 y$ N
Dim lLngMod
2 h# ?$ Q% j+ r* @$ mDim lLngResult $ N" R3 ?. w0 Q/ b
Dim lLngIndex
0 B- W- X& i- B! v9 hIf pLngKey Mod 2 = 0 Then % }4 {% U$ Z$ ~5 D; w" e
lLngResult = 1 7 l; A* G7 j. {& Z" }
For lLngIndex = 1 To pLngKey / 2
' a: _# `0 ?0 l0 _+ V; MlLngMod = (pLngMessage ^ 2) Mod Modulus
8 Z" o' i _6 X N. x) g2 B9 h. @' Mod may error on key generation " \: |4 }9 p) L* u2 M, d+ z, b
lLngResult = (lLngMod * lLngResult) Mod Modulus
; M+ E0 b0 H( a7 _+ z1 XIf Err Then Exit Function
9 r1 I o1 `. |9 L/ \3 bNext
5 M2 L$ I/ n# u M- aElse 9 P' a+ @( C; l" T' o' \) I
lLngResult = pLngMessage
5 w$ S, p* f5 O+ ~. HFor lLngIndex = 1 To pLngKey / 2 3 P: y# h# h2 N; ?# `
lLngMod = (pLngMessage ^ 2) Mod Modulus # O; }, w! Z: ?( x1 j' T
On Error Resume Next ; T; x4 [1 n, Z" l* i& n+ I, N
' Mod may error on key generation
5 \6 s$ T+ C% |6 O. j9 rlLngResult = (lLngMod * lLngResult) Mod Modulus
& w0 G& Y! V4 l7 e3 |If Err Then Exit Function
: N; q8 c4 S* y$ c/ E2 JNext
+ n% g6 s* p* U" c; cEnd If 4 P; A3 `5 u; X$ t" ^" D' G1 p( S' d
Crypt = lLngResult
0 s4 z* q8 r* ]2 p6 sEnd Function8 @5 Q( W0 p. m9 D$ s( ~
- I1 e4 K R1 M$ u' o& U- SPublic Function Encode(ByVal pStrMessage)
V7 |3 L, a, Z; c0 {5 A5 z/ DDim lLngIndex
- d& l/ z; y% X8 x; o; kDim lLngMaxIndex
6 E7 |' R/ Z9 d: {1 gDim lBytAscii : {# Y) `9 V2 a5 t# m
Dim lLngEncrypted
, R/ u5 O& b/ _( q( B0 ?, y+ G2 X! WlLngMaxIndex = Len(pStrMessage)
* t8 C q: ^ X5 S+ p- bIf lLngMaxIndex = 0 Then Exit Function + }' `4 M. w+ k) s7 O$ A
For lLngIndex = 1 To lLngMaxIndex
$ M! z& h6 W) K+ i! clBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) ( b d# ]. @2 ?! ]9 b7 e2 K
lLngEncrypted = Crypt(lBytAscii, PublicKey) * {, M) o& w, z8 t8 m5 L* V% u" `
Encode = Encode & NumberToHex(lLngEncrypted, 4) - f4 n- |* ~ U. B Z% d
Next 6 u; P m3 n* O# O. E9 P
End Function
4 I% q$ n6 F0 g# P- o" Y; wPublic Function Decode(ByVal pStrMessage) : f, h1 N0 G$ n6 O) o( Z
Dim lBytAscii
. S2 t! X! M; L f+ @0 f) z7 B3 QDim lLngIndex
$ E# D( y% X2 v1 c# Q ^" n, a# ZDim lLngMaxIndex
1 I) h/ M" v1 V2 DDim lLngEncryptedData 5 M9 P9 y0 d! b( H
Decode = ""
+ d" U0 E B/ u* wlLngMaxIndex = Len(pStrMessage)
5 X. y0 v; L3 a) Y, B9 SFor lLngIndex = 1 To lLngMaxIndex Step 4 ( [) e2 h) u7 `0 B& m; n, w
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) & k( L) p1 K3 r, _3 u7 M
lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
; H1 b; g2 [0 g/ Z3 K) ZDecode = Decode & Chr(lBytAscii)
* F) z8 z- W! J$ [' o) aNext
* G0 c; o! }, p6 C% j4 h1 G( AEnd Function $ p% b8 [ t! W6 V' |8 u% f
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
) q2 G3 _' T. j3 Q/ c0 p; {) N9 hNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
! p. J. F; h3 a; q/ x+ \End Function # i( u, ?8 ]/ ] ?, t, }+ R
Private Function HexToNumber(ByRef pStrHex)
8 e0 O0 c5 D; N, N6 I7 ZHexToNumber = CLng("&h" & pStrHex)
/ f% B) O+ z, X! e$ nEnd Function
0 U2 z+ D( r3 I. |) I2 IEnd Class
+ o- } Z5 k3 y% W" c/ i# M% H6 Q3 Jfunction Encryptstr(Message)
& M" b. r+ V3 v/ \5 D3 gDim LngKeyE
5 C" h! K6 Z$ o5 @. S1 {3 DDim LngKeyD
8 [# E+ F$ f' a1 g4 P* H# s. aDim LngKeyN
$ i3 M- l; a9 [& A& Y, V" rDim StrMessage
# n/ @, o) E2 `& vDim ObjRSA
0 P; L0 ^& A# |5 h8 c# cLngKeyE = "32823" x4 o; X8 ]2 c8 S7 V4 a
LngKeyD = "20643" % K8 e6 P: t( A5 r- t6 `
LngKeyN = "29893"
8 v3 n4 P5 K7 s2 q% zStrMessage = Message & O$ E5 J5 n' R% `: N
Set ObjRSA = New clsRSA
, ]0 K% N. d9 f7 B! DObjRSA.PublicKey = LngKeyE " E/ m4 _2 `- ~: |. a
ObjRSA.Modulus = LngKeyN ) `' W/ y+ Y: o+ f" O
Encryptstr = ObjRSA.Encode(StrMessage)
; Q3 W, X6 t8 Q4 sSet ObjRSA = Nothing
" S/ s. L! H# _* aend function2 V0 l4 O) w3 V
Function Decryptstr(Message) % A/ o9 }9 d* {. o) a
Dim LngKeyE
2 t2 v: a& T7 f& iDim LngKeyD
& {" ?2 y( q' B! e9 }7 n/ v+ U' h rDim LngKeyN
. n" D- R+ m8 G" a; s1 PDim StrMessage
3 ]6 i( a) ]9 W& C/ ODim ObjRSA
3 Y6 e" W6 x8 H7 i" k' `LngKeyE = "32823" - O/ t; R; @0 [2 E
LngKeyD = "20643"
4 p9 G! w# G: W8 u0 h3 {LngKeyN = "29893" + Z, U4 b+ N; V/ I! w3 k
StrMessage = Message
; S: }3 T2 v. K) b" P/ ?& pSet ObjRSA = New clsRSA
! l$ M0 g. y0 r. `. h4 c1 ?# Q/ EObjRSA.PrivateKey =LngKeyD
1 f e# z* _9 w, e6 V+ ?ObjRSA.Modulus=LngKeyN # |# U2 X. [$ e+ m: ^6 J" V
decryptstr=ObjRSA.Decode(StrMessage)
F$ J( h+ I; @8 p3 b. l5 v% eSet ObjRSA = Nothing
# p* w# L- c* G+ Kend function : t1 G3 u' @2 x
%>
- N k& R0 M; z0 n/ U/ G7 r===============================================. j8 {, c! O, G* G+ O
8 c- T' ?4 g; }9 e/ G& m
还有一个用于测试这段代码的test.asp( t7 ^) A+ W$ {. y2 A6 B: K- Q
有兴趣的自己搭建个IIS测试下; ^( G+ b- s) w' I, T7 o
<!--#INCLUDE FILE="RSA.asp"--> 8 \3 n0 V- p! N/ S4 |8 ?
<%/ @! i0 P" _5 r. k# d
function Encryptstr(Message)
' O2 D9 k8 C1 m' _Dim LngKeyE
t! A; y+ j9 Y) z, A9 R/ g$ d/ C0 QDim LngKeyD 3 u* K4 I6 g% k k3 v' y
Dim LngKeyN . I5 u! M! h& U- X5 E8 M
Dim StrMessage
6 N4 P0 ?; n9 L4 }$ {- H1 mDim ObjRSA
; u0 n: P3 s* S+ N& e# @LngKeyE = "32823"
M8 ~5 X) f& L B# H# \LngKeyD = "20643" . m$ ^# G1 b9 p: v0 [/ T
LngKeyN = "29893" : ]; M6 `* @6 L" _
StrMessage = Message - u5 U/ X8 q% N1 e( u1 z
Set ObjRSA = New clsRSA ! t; @ U- X; I3 L7 ^4 O
ObjRSA.PublicKey = LngKeyE
r( z0 u7 s$ o4 eObjRSA.Modulus = LngKeyN
( w U$ `7 x7 X3 f0 a% q6 jEncryptstr = ObjRSA.Encode(StrMessage)
" C3 o$ p. a' P+ |Set ObjRSA = Nothing
) K7 L5 l" k/ C7 r: c3 p7 ~end function
+ m, e4 C0 T) o$ afunction decryptstr(Message)
) Z; k1 u/ ?) w+ s4 P! XDim LngKeyE
0 s+ q0 S, R+ EDim LngKeyD
2 l+ {5 t' V" f9 U5 h, y: bDim LngKeyN
+ u8 \0 y7 Q% a q$ w3 w0 W; c2 ]. A% [Dim StrMessage
3 S2 m# z, r3 W0 [) q6 I& bDim ObjRSA
1 }; Y/ l/ S% e {! kLngKeyE = "32823" 4 _# N: `3 o2 S5 p6 }
LngKeyD = "20643" 0 f# T F& l* p, A5 g* `2 D
LngKeyN = "29893"
( m5 h9 K& z& D$ SStrMessage = Message
+ g6 X! @' z7 p& `Set ObjRSA = New clsRSA 3 c9 z$ D( j( ^1 V2 P
ObjRSA.PrivateKey =LngKeyD ! L# N' l8 N4 O2 m
ObjRSA.Modulus=LngKeyN ' U$ t* o9 h1 u+ n& z; J
decryptstr=ObjRSA.Decode(StrMessage)
6 z3 r! T+ A! E! gSet ObjRSA = Nothing
M+ F7 w6 Y; V, Y* O0 x* |end function ; D5 v* d$ |% a8 ~$ R9 L
dim last,first ( d; l1 H; ?" q/ _# S
first="!@#$%^&*()" & `. b9 f1 K! T* b) j" J$ w
Response.Write "加密前为:"&first
( u7 c$ ^- Q& Z' M' C. Hlast=Encryptstr(first) / [* q" w7 i6 v& G, c' j+ t
Response.Write "加密后为"&last 8 [6 m/ I6 N K, t3 L9 t/ T% `: M
Response.Write "解密后为" &decryptstr(last)
* B, o# e8 B$ C# R! t. v1 L" n%> ==============================================* O) D6 N* C1 }
剩下的就是字符的对照表了6 `) U4 K4 y8 \: j" B, P: g
===================字符集================# z% l8 N- Y( ~3 m9 Z$ u
1_____6EBB
, R J1 O2 {- n( w2_____5C1F. L) I5 c5 @7 h
3_____4D75- }+ L1 X. l; |& e. ?3 M" v& h; B' G
4_____26CC- e6 P4 c3 b# d7 v" D a
5_____4F88- G9 T( D/ p# M4 W
6_____3F4E
+ k( L( q! f: @( e7_____0A9D2 [, K/ l* z3 A6 `, P% O( |1 P6 @7 \: J3 J
8_____1A1C
" L/ q/ R% U0 c" m `9_____6D20
# Y+ K% z9 x8 |. ^0_____1089
! W |$ J7 y, F1 W4 ~& ~2 u! ca_____0F3E
% X7 p& k$ r, b. c' A9 ^b_____3159% J2 z/ E5 D- x4 v. D) S
c_____35172 @" i/ F1 @$ t& T0 |! u e
d_____419C
$ o) ~! z. }9 w# K$ Le_____615C, k7 i* y" }& N% n1 ~
f_____556F( E5 W8 U4 j) D# P c# C# J
g_____2B7F m4 b1 ~4 Q+ e* X, g9 l
h_____0F9C# T C/ `: T( _) I3 M4 `
i_____00FA1 e1 l4 C3 ?% L2 a0 @% z! d9 j! {
j_____5A50; \5 g4 w1 B/ G' J# Z
k_____28505 o* j5 A# A% Q5 f7 c8 V
l_____3E7B
7 i+ p- _+ K$ b* Jm_____71C57 W. {: V( |9 B% J) ?
n_____1FC8
" R4 T# Z& G/ N, m: [ d& s/ Ao_____74C1
1 H$ h$ e3 X5 |" [p_____5FB8
* h( F9 x* f1 H6 yq_____6085
3 i$ \/ s1 x! E3 p$ q( Rr_____3AC4
1 r0 Q2 N% B# Ls_____2F50
9 N3 q* [/ i- w9 o% o( Mt_____36F8+ e& M$ Z' t% U
u_____7010% ` t! P8 L Y) Q, k8 s4 e, Z
v_____0B42 g6 x1 {& w4 i/ [% w: x& r; G
w_____1C7A: g) ^- c }- c4 O; m
x_____16F8
& I( M3 E/ X2 F* `y_____2EE75 l/ ?8 O: ^# `+ [& ^! b( f* L
z_____5CF34 V; @& X8 _- Z0 U# v: W
!_____6233
0 R4 m% T5 m; f/ f' {@_____3A454 P3 Y$ l6 @$ [4 ]2 g
#_____2291
+ B* L5 o7 U( R7 ]& A" q$_____5D5C
5 P: b1 I* u% R R%_____09B9# o! ?* E- J# o1 ^1 v. P+ @; J9 ^
^_____43EA* r2 X& D' ~9 q
&_____62B9! D4 Q; `) w x2 R( c
*_____6301+ \8 f$ q9 v; w( {4 {! T$ M
(_____46590 O, m) C; I( Z5 I# k# t u
)_____5C82 |
|