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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm8 Z3 G( t, ^# j3 z7 S( Z
原始出处:http://www.3ast.com.cm3 |+ x: E( N5 |
6 H! N3 P) H# A% y! @8 d看不懂的直接绕过( Z+ S. O7 v# b2 z, s( B
加密前为:hwy123456; S* Y9 w5 t" d
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E9 z' H# C& G. d
+ x9 Q4 O! k5 i+ u* k* g
============================================
, u2 b3 } U% J. k上面是当时自己校内的心情。现在已经解破出来了,分享给大家
' P ^ V2 ^; q! R1 @! m也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
/ b6 Y" n+ U( y" e以下是RSA算法文件
& n! U$ `5 D& a& T& v) d. ?# h
) d' J9 L" ^( ?4 y# K5 W w文件名RSA.ASP
4 ^) a) g4 T3 V. @/ g===============================================" V5 g5 V/ |! I! n
<% : P/ d {2 I* w4 |5 L* Y, c8 S" ]( G
Class clsRSA M% l$ Z" t8 e( C" e- ~% }- c
Public PrivateKey
6 A3 p/ J0 H% j: D6 A& `6 t; k+ LPublic PublicKey
( R9 q0 `8 q7 L. ~+ mPublic Modulus
I( }) D) ]1 zPublic Function Crypt(pLngMessage, pLngKey)
. h }6 N) _- P' }1 W8 K0 COn Error Resume Next % O& E, T% H7 C8 q' o7 l& l s
Dim lLngMod - n0 ] [" r! p; L5 h4 s
Dim lLngResult . q$ o+ { @& R* D; h
Dim lLngIndex
* F$ v8 [. ~8 y3 `3 tIf pLngKey Mod 2 = 0 Then
y, W, \0 _! X V/ b$ r4 KlLngResult = 1
* f: p4 ?5 Q* [+ QFor lLngIndex = 1 To pLngKey / 2 ; L7 k" A9 o$ {) I. B5 r
lLngMod = (pLngMessage ^ 2) Mod Modulus
8 ~) Z/ V, D6 ~) p: D' Mod may error on key generation
, w; n: e2 e/ p! b2 wlLngResult = (lLngMod * lLngResult) Mod Modulus
5 c; Q4 z1 J0 T2 T4 X7 {9 T) A+ d- |If Err Then Exit Function 1 q+ N: E7 \5 _( w# k- S6 r: H
Next 5 M; Q% U* i; }0 L8 {" S' {
Else / K* ^- ^- o5 l3 b2 [% o0 @
lLngResult = pLngMessage 1 j, l4 l; [# |
For lLngIndex = 1 To pLngKey / 2 ; l. g( F* |, J' W8 P& ]4 ?
lLngMod = (pLngMessage ^ 2) Mod Modulus
$ \8 h, L0 s: L1 g2 XOn Error Resume Next 0 c, n9 s1 j+ y# ]
' Mod may error on key generation 8 t. H/ d8 Y+ v3 z
lLngResult = (lLngMod * lLngResult) Mod Modulus
' w4 [( V" \- {1 D( LIf Err Then Exit Function
7 X/ x0 @" L. f! aNext
/ w8 z# Z w0 `/ h6 v# cEnd If 5 c- K$ \; u* S, u) z$ ~# v
Crypt = lLngResult c" A3 L3 L4 Y9 I' M8 S
End Function
5 ?$ w( F5 d4 I# [ w" u
" _" s+ ?. n7 z9 c* f; ~Public Function Encode(ByVal pStrMessage)
5 r( W% i2 |% s |/ x6 zDim lLngIndex ' x* ~4 `5 s- Y& A
Dim lLngMaxIndex
* B, C# Z* U1 j- Q: P' V* x5 ]- CDim lBytAscii
: g( B7 p) y6 d; dDim lLngEncrypted
, E, }; @4 z7 K' s7 @lLngMaxIndex = Len(pStrMessage)
+ W# M/ [* b9 R( r5 T2 P$ k; ~1 vIf lLngMaxIndex = 0 Then Exit Function ' _8 M1 ?/ Q2 M0 h% f" @+ {
For lLngIndex = 1 To lLngMaxIndex
2 X% q; O& E6 y% x& ?( dlBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) # V( `7 q( Y$ V h
lLngEncrypted = Crypt(lBytAscii, PublicKey) 6 [1 ?7 }% R5 O/ ~8 x. T% r
Encode = Encode & NumberToHex(lLngEncrypted, 4)
+ e1 G! t/ _& f2 d. RNext
" W$ I; Y; w" p1 ?/ ~, z7 i+ b9 _1 Z4 pEnd Function
1 {1 J# G& y2 E U* E, ePublic Function Decode(ByVal pStrMessage)
, r) T6 P7 l- g; N- g& \- CDim lBytAscii 8 a+ v8 A% ~2 z( g7 e+ K
Dim lLngIndex : P* T& G2 K5 x% A# k2 E
Dim lLngMaxIndex
, G; u( y, h* E+ j" ZDim lLngEncryptedData
6 P+ w* G0 q9 l1 o, |& ^Decode = ""
) o% ^" G( x/ |; ]2 U# m" M. o. plLngMaxIndex = Len(pStrMessage) # A! t! r. Z2 |" {, F6 Z7 p4 h: N
For lLngIndex = 1 To lLngMaxIndex Step 4 ) v" P! u7 s4 Z, C- {
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
! U$ U" N$ B0 Z( ^+ t6 k0 llBytAscii = Crypt(lLngEncryptedData, PrivateKey)
; U1 h& T; F. ?1 BDecode = Decode & Chr(lBytAscii)
2 T+ c# z1 G7 _3 R: KNext 9 x' e( ~- h$ z d; d- |
End Function
% L! @+ z/ H1 Y( @+ h2 ~Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
: A6 U; c$ Q2 j, o* [: l; tNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
- Q2 s3 D2 R K9 i. HEnd Function % r7 y+ O+ L3 w
Private Function HexToNumber(ByRef pStrHex) * A, n" g& i) k! P
HexToNumber = CLng("&h" & pStrHex)
5 W3 K9 V9 [7 f GEnd Function 5 }% a+ B) b( l9 o' t
End Class 2 M0 @9 U* d, f+ b% \! z
function Encryptstr(Message)
/ ?& k5 H3 W2 g6 kDim LngKeyE
! y; s7 C1 L- I7 sDim LngKeyD
) A2 O8 N( l) {; i2 Z7 fDim LngKeyN 9 }7 i& R0 f9 K% s1 [% Q) o9 I
Dim StrMessage , S- z3 c3 ~3 u( @$ r% m% [
Dim ObjRSA
0 ^( @( s6 m, N8 v O1 C/ H QLngKeyE = "32823" ?) O/ Y- U" x
LngKeyD = "20643" . A% b9 m5 i8 A. Q
LngKeyN = "29893" ; h+ m: n4 X. G& q
StrMessage = Message . V. g" D' Z8 _0 G4 L0 L
Set ObjRSA = New clsRSA 5 @4 i {5 [' }3 n: G. d0 P
ObjRSA.PublicKey = LngKeyE
+ @2 J. p$ Y5 V. I: h7 ~( q7 _/ kObjRSA.Modulus = LngKeyN 9 i9 ~% d# }) G* g/ @$ Y0 h3 A4 F
Encryptstr = ObjRSA.Encode(StrMessage) 9 X- R0 \& Y8 M; G+ S o A( q
Set ObjRSA = Nothing % [( G: B2 D u/ @( u8 L
end function5 e2 h! \6 A& c! P, I# P0 B
Function Decryptstr(Message) 9 ~. r7 Z% @4 K, b; v8 [5 v
Dim LngKeyE
7 x" S$ e |, D( TDim LngKeyD
9 \* I: d% N* C8 j1 gDim LngKeyN
" t& T$ _! o/ c# ?% [+ pDim StrMessage
# }: v2 _% q% HDim ObjRSA
+ D+ [! I# I4 F" O9 kLngKeyE = "32823" 9 x" G1 M: U$ M5 }% P7 D- C
LngKeyD = "20643" ; y& H: E4 N; b! a
LngKeyN = "29893" $ D: |0 D7 M$ @1 A _1 J
StrMessage = Message ' V% n4 u+ X" h& y/ f
Set ObjRSA = New clsRSA - r1 S2 n: V9 {$ @5 R" {/ o# X
ObjRSA.PrivateKey =LngKeyD , T: J% C! Q8 ?& ]# h ?
ObjRSA.Modulus=LngKeyN
4 M( Z% ~% |5 U, ?2 @( q9 v& Gdecryptstr=ObjRSA.Decode(StrMessage) . r- N9 B) Y7 z, Q* G" \
Set ObjRSA = Nothing 4 T3 s+ a) `" ?
end function
) z) u* d6 d" Z! T+ H%>
$ b: ?# c; E5 n===============================================
( l" ?9 d" L8 L! C5 ^
9 U' @- u- p+ ^0 Z/ @# Z* D6 Y还有一个用于测试这段代码的test.asp
M3 h2 Y" \5 t9 v有兴趣的自己搭建个IIS测试下
4 L& v, r% l P* s<!--#INCLUDE FILE="RSA.asp"-->
; s$ d5 j, V( N6 k, D- h<%
7 r! G* S0 L2 z, a1 g; cfunction Encryptstr(Message) 0 m1 |* N7 b- b7 Q
Dim LngKeyE 4 o. \8 a4 e1 J& D' A- M$ ^
Dim LngKeyD
, O- W) L) }7 c9 R8 B( K: J8 PDim LngKeyN 2 w1 h. G# N1 }1 g
Dim StrMessage 2 {% O7 L6 w7 z8 ]. A
Dim ObjRSA ! v. M$ a. S: }
LngKeyE = "32823"
. `4 x4 h4 a' m T2 f9 T! N) ]* ^LngKeyD = "20643" ) L C4 m4 F6 ^. K& y9 L; n
LngKeyN = "29893" 7 A% r6 M" p3 O6 s- I- Y" n- o
StrMessage = Message
- j, y B- T4 [' l9 nSet ObjRSA = New clsRSA
5 U' T2 q5 w# X, ]2 MObjRSA.PublicKey = LngKeyE _- U. N" o$ F9 U
ObjRSA.Modulus = LngKeyN
( H) U8 [3 c* z, y. o1 C* ?Encryptstr = ObjRSA.Encode(StrMessage)
, V+ L1 W( W$ |" E B# \# `1 MSet ObjRSA = Nothing
[ `0 l b0 ]+ o/ iend function
) [; z3 E1 t: Wfunction decryptstr(Message) P9 Q! T& x) `" N+ O0 ?) l
Dim LngKeyE
: J; {- E( E" c5 h& R6 iDim LngKeyD 2 E3 y0 P. R, _, [/ d
Dim LngKeyN 7 g& t$ a# z- J6 C' v' C& ^
Dim StrMessage
. }, J0 [; P* t( p. p( ]5 nDim ObjRSA 0 ~0 u# n! ]5 v; B% D' |/ I3 L! ?: R
LngKeyE = "32823"
$ {5 }+ v. O" ^5 P: h- v! A, tLngKeyD = "20643" + }) A+ |7 t& F' y0 B, C1 S
LngKeyN = "29893"
% E: J- C4 p' Y0 Z. S& ^! YStrMessage = Message
4 x+ d# N; b7 n# M* wSet ObjRSA = New clsRSA
2 V( G5 P. _1 M; C" o5 b- QObjRSA.PrivateKey =LngKeyD
/ Q: G# h2 @1 d5 IObjRSA.Modulus=LngKeyN . ]8 x4 k" k0 |5 ~
decryptstr=ObjRSA.Decode(StrMessage) & O) Z- u3 w# W0 J
Set ObjRSA = Nothing
3 T6 _9 G2 ?& T) M! `. Kend function ) T! V; W# A( W# j5 x5 q
dim last,first - r4 q' o# y2 B
first="!@#$%^&*()" ; V% R- f* Z3 B ]% p, |
Response.Write "加密前为:"&first
# F& G5 {3 z F- klast=Encryptstr(first) 7 [, L8 m% U C4 c: H
Response.Write "加密后为"&last
( g, z; Q1 A" [7 H' q$ JResponse.Write "解密后为" &decryptstr(last)
: m" }% S6 K4 o+ F2 d) W%> ==============================================# h; U$ v' O0 j( H/ S/ U* X
剩下的就是字符的对照表了
7 @) S0 h5 V, P0 U V1 r1 b===================字符集================- z) P5 o3 S: k- Y8 B! F A
1_____6EBB
' [% b% I5 | |" [$ ?4 y0 ^2_____5C1F- @/ `, ~# i/ {6 c
3_____4D755 C4 e I2 u/ }0 l
4_____26CC$ C! D% u' E; M: U+ M' v5 C
5_____4F881 m. `6 A+ t' x
6_____3F4E* c$ {! i/ A* k% V. j: a
7_____0A9D
4 ]( B4 I! z, P. Y) t+ ]" w0 p1 h8_____1A1C
I8 v! L$ { w/ ?& {* Y" j- \7 {9_____6D20
8 D$ `# j1 k! V8 L( h: M# K0_____10892 h$ } d9 _1 ~( j6 E- G
a_____0F3E2 q6 w5 S6 h9 T& h" P% e
b_____3159
: B) {" \# j" r6 J/ }7 j( B& sc_____3517
9 D% e; y7 m& [& \4 ^0 t- Ld_____419C5 h( @4 {+ _% W; k& v/ n
e_____615C
$ S+ \3 H" C5 d+ U0 `f_____556F# t8 U3 @3 T8 d
g_____2B7F
4 j" N. S( s; ]- F( t( }4 q* z7 ah_____0F9C+ i; @( y0 M# d0 p3 {
i_____00FA( A' k' Y7 j9 ?5 |+ |3 j" U
j_____5A50
) a% d7 S9 H: Q) rk_____2850! v& o( I' }7 A4 `
l_____3E7B! f$ |! j3 U" B6 U) x+ T" h* y
m_____71C5
# u; f5 w1 @9 [& Q. Cn_____1FC85 ?' G. d$ [" f
o_____74C1
" i( x( g; ~3 c7 v6 ip_____5FB8# L% j4 u" Q$ [5 M7 E+ u3 E, B# B
q_____6085
& i* [ u3 k% L7 ?$ ^2 Kr_____3AC4
5 X5 s! \; U9 p/ ^! T5 vs_____2F501 e9 x$ Y$ Y9 e [+ \ J- Y
t_____36F8! z- R- M1 E" V5 Z; j7 c
u_____70106 X) G. ] F( [) Y+ ~% B" B
v_____0B42* C( d) N. A [
w_____1C7A( L) ~) c. T( W# F
x_____16F8' u; s1 r* Z7 z2 l7 y
y_____2EE7# |6 U6 A$ F; h, Q( R: |
z_____5CF37 i/ N* \9 C7 r" K
!_____6233
- f+ v1 Q) _ x7 M" n# z& p@_____3A45
7 g9 Q8 t$ P4 ?% M4 x4 T#_____2291
" a6 k( |0 v( g( B$_____5D5C
* M5 F7 ~& E6 [7 i$ i0 u+ o%_____09B9
" ^4 U4 |6 @6 z' H3 L; ^^_____43EA
* ~9 g3 M/ \3 l1 h n&_____62B9
2 `+ P7 j) \% z& [*_____6301
& l: P( h0 S7 O5 O4 E(_____4659" P: k7 o5 i3 d; j) O
)_____5C82 |
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