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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm5 c; ?% h! Y3 h5 q) r7 s! K
原始出处:http://www.3ast.com.cm
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% e1 K0 j1 S: p" t. i看不懂的直接绕过, q" f0 `( q r* A; C L
加密前为:hwy123456
7 |" V0 |" W4 m% y0 O加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E0 u O& ]* |! ~ [
# e! f* k1 W- [! L3 Y% m: a8 p
============================================9 F/ f4 L4 z+ q+ d& d6 O0 V5 h
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
( h5 o* z W8 H X9 H- ]也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法2 h: |( h$ l- A7 D
以下是RSA算法文件- M7 a) m4 g# {2 N4 H) g! M* O
( y" O0 `/ |/ c文件名RSA.ASP
: p) C( [+ V8 F1 Q/ z/ D===============================================
% o/ q" ]/ l# A; X6 \7 X8 z$ j<%
; h! U5 ~! \. p' Q( JClass clsRSA
# M$ }- ?0 Z, i4 c' ? APublic PrivateKey
) o5 ~- f/ f% I: U# `Public PublicKey
, U% _# w$ p x' Y4 C7 P8 v! M" IPublic Modulus
8 k2 v% i( m4 `! ]& s% _( NPublic Function Crypt(pLngMessage, pLngKey)
i* W( r* r' d& [On Error Resume Next d5 Z' M1 z9 ^( i
Dim lLngMod 6 U' x* F" E- K# Z
Dim lLngResult ( K2 Q. ^: t5 s
Dim lLngIndex
, j- w6 E7 a1 R- v) x. Q6 `If pLngKey Mod 2 = 0 Then
! ~1 @6 H$ {7 g ^, ylLngResult = 1
" I1 t4 J* C9 \. i X! {* }6 LFor lLngIndex = 1 To pLngKey / 2 . V% Y* D8 y1 }4 H
lLngMod = (pLngMessage ^ 2) Mod Modulus 8 z- p% C' z( A) n1 h# j0 S0 m
' Mod may error on key generation
! s' G) m+ F- N; h! x7 o3 X' ]6 R: SlLngResult = (lLngMod * lLngResult) Mod Modulus
' T$ E) C( m- k8 zIf Err Then Exit Function
0 X" B9 f9 c" Y& w8 T3 lNext
8 }7 U8 j0 H1 Z C8 \7 XElse ! |+ _; s: U. T, [- I" W
lLngResult = pLngMessage $ \+ t8 I' _& ]
For lLngIndex = 1 To pLngKey / 2 ' F4 H. V5 h0 k7 s' k
lLngMod = (pLngMessage ^ 2) Mod Modulus - w' W( {4 {5 h9 ?
On Error Resume Next 7 w3 h8 m" G- z* Y% b- I& A
' Mod may error on key generation
7 G0 L! A, H* b" S& mlLngResult = (lLngMod * lLngResult) Mod Modulus 3 a$ V8 j& N! M2 ^, V% H) c2 O
If Err Then Exit Function 5 R) w4 J; [) _" R3 z5 P
Next & J$ n3 L& T1 e+ e
End If . M! F9 ?# c: M4 ]# S+ |3 w; M
Crypt = lLngResult
Y1 m" `* ?: WEnd Function
4 l7 X/ ?) g6 |
7 e2 |# P7 P# _& Z* b1 P5 T# L2 SPublic Function Encode(ByVal pStrMessage)
$ z5 O2 e9 e+ \1 S vDim lLngIndex 3 `1 w) F' Y6 d6 u2 L
Dim lLngMaxIndex
, L4 W" g; n+ u" x: KDim lBytAscii 2 c7 r* _& }# S, ^: S
Dim lLngEncrypted ! V. K( N1 c6 W# Z+ d. h
lLngMaxIndex = Len(pStrMessage)
; n0 W6 P9 n6 `. R5 Q5 P& L- IIf lLngMaxIndex = 0 Then Exit Function 9 S2 r$ D1 N5 V7 e0 g9 X& U
For lLngIndex = 1 To lLngMaxIndex
8 I0 ^6 S( U6 l" L7 n6 slBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
( M) P, c( x% G# o5 d# z$ D2 xlLngEncrypted = Crypt(lBytAscii, PublicKey)
9 n. U9 d; i' q! v& \- q* f! y+ d2 fEncode = Encode & NumberToHex(lLngEncrypted, 4)
2 ~# `7 h, t/ a: B2 e! I0 CNext
# }" K5 x3 B. iEnd Function $ y j8 t4 X% O$ Y, _
Public Function Decode(ByVal pStrMessage)
" l, B' J: @% I& g' qDim lBytAscii
# _7 E, G) Z* E3 R2 yDim lLngIndex
/ P! q8 W2 x& xDim lLngMaxIndex ( C! x3 n" _) T
Dim lLngEncryptedData - ^" v6 [6 u, g. r1 B
Decode = "" 3 g- w6 `, }7 z' K g3 l X: K
lLngMaxIndex = Len(pStrMessage) - X8 z1 ]4 L" C0 [: \* f
For lLngIndex = 1 To lLngMaxIndex Step 4
) t% ^* y1 W* f9 _* F) e4 m% ]lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
2 C" Z* v" p E3 ]! olBytAscii = Crypt(lLngEncryptedData, PrivateKey)
8 \9 q; k/ |" b4 I8 z% [" EDecode = Decode & Chr(lBytAscii) / o% e2 R7 x Y
Next
Q, |3 ~' Q5 M) `: a, y5 OEnd Function
1 c, U7 K3 ` x! wPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
( s4 A+ @6 a/ H& k" }; nNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) " C8 k+ j" w8 V3 C( ~. |* w
End Function 9 s/ C1 i; l& Q& D B
Private Function HexToNumber(ByRef pStrHex) $ H' w6 b" s& E) p
HexToNumber = CLng("&h" & pStrHex)
3 \( I' h7 M5 M0 f4 A6 b4 `End Function
+ G8 {! ]- H2 D- U8 O% ~+ k2 ^0 |End Class
4 y) Q) x! P6 q/ I( gfunction Encryptstr(Message) Z/ H5 X) X; G$ d- A
Dim LngKeyE # \( ~6 l$ y, e2 w( o* z8 x3 u
Dim LngKeyD
% w- E+ J! r) s( nDim LngKeyN 1 v$ Q. s- Q3 F, i: I
Dim StrMessage
6 Q4 l5 }7 ^$ O9 C% \# l1 f( e, eDim ObjRSA
% o' s. L: |. H% |LngKeyE = "32823" # S( s4 I2 t- S0 |* h( Y: e
LngKeyD = "20643" $ `, v7 i0 v2 f6 x( O
LngKeyN = "29893" ! S/ g' Y" S, q& N; B
StrMessage = Message
1 |; p$ ~ f9 P8 q8 T. ^7 ]Set ObjRSA = New clsRSA * e) o% n$ v4 R M- A$ C3 c
ObjRSA.PublicKey = LngKeyE 9 K, Z' S$ B1 V9 T/ `0 j
ObjRSA.Modulus = LngKeyN / f' w# F% Z; M( z1 I' I- Y
Encryptstr = ObjRSA.Encode(StrMessage)
- b& [# `: p5 V' {! \* {0 R6 zSet ObjRSA = Nothing
# n6 h7 Y! e {end function4 V! B$ z6 \$ Z# a, N s
Function Decryptstr(Message)
$ y8 o W" A9 `5 e QDim LngKeyE
0 `0 ?5 [, }! q' k* U# w- ~Dim LngKeyD ; m2 ?& U) M N* G& n
Dim LngKeyN 7 p' s2 v6 N) |( }
Dim StrMessage
1 _: ]& n0 G0 J' ?Dim ObjRSA
) H$ P1 A( C4 I" {LngKeyE = "32823"
b- t/ Q5 x( I, u6 @1 c hLngKeyD = "20643" , v7 ~5 ]' ~& C/ W" ` k8 r2 m
LngKeyN = "29893"
' D5 q# R L. h! h2 {& j" q5 b$ u9 VStrMessage = Message
! X$ @( j1 J5 j5 x; @Set ObjRSA = New clsRSA
; T/ m- {) z1 x3 _+ n+ IObjRSA.PrivateKey =LngKeyD
+ O" l9 _* R: F2 }& |4 v9 X3 a" DObjRSA.Modulus=LngKeyN # `0 q! e1 m: y. Z& R
decryptstr=ObjRSA.Decode(StrMessage)
3 l, |, {- h1 }- j/ MSet ObjRSA = Nothing
# V( _* L+ Q2 ~8 f- f7 }; bend function
3 ~( M+ j( Z9 q$ `%>
?7 Q5 I/ _! o- c: u( C) k0 ~===============================================
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' {& H' ^2 t4 d+ W9 C3 k还有一个用于测试这段代码的test.asp- T* I5 C" e2 m1 N) j
有兴趣的自己搭建个IIS测试下( k% ~% o8 N5 X. y+ p+ z/ e6 Q g
<!--#INCLUDE FILE="RSA.asp"-->
V3 {& Z6 _5 ]1 G" n+ b' Z# ?9 z<%
1 ?/ _' o# Y1 l# Y7 Vfunction Encryptstr(Message) ; L5 g. y3 @ w
Dim LngKeyE 1 d9 g) K/ I2 q; A& p$ U( X
Dim LngKeyD 1 }0 [0 l$ w4 T2 G
Dim LngKeyN
4 F2 s% l. s/ Z8 h" Q& V. p9 m& rDim StrMessage
6 {, w" `/ y+ G0 UDim ObjRSA
x# N# w4 S- Q/ y8 |. hLngKeyE = "32823" / L/ z8 m6 t! Z4 ?+ k
LngKeyD = "20643"
3 q( ~$ M* o/ x3 Q" Y% S( ILngKeyN = "29893" ( |1 j- N2 v) }+ V r; n
StrMessage = Message
7 ~( n; U5 {$ i$ _Set ObjRSA = New clsRSA
( y9 y- F R9 C0 T3 ~7 WObjRSA.PublicKey = LngKeyE , {/ {" ^5 T6 Y6 B
ObjRSA.Modulus = LngKeyN % T7 ^! A$ l' z. W' _
Encryptstr = ObjRSA.Encode(StrMessage)
b( X8 t1 E- V4 X8 K2 gSet ObjRSA = Nothing
/ ?6 g0 p; P8 j& G* ]% send function
# r4 j4 `( l7 `function decryptstr(Message)
2 a. w* _+ t* H! p' x7 w6 gDim LngKeyE 1 x Q8 ]. f, b4 I3 \
Dim LngKeyD $ T7 ~: \# L2 |6 G+ B5 F. d! {8 _1 N
Dim LngKeyN
) e9 l/ {/ O; m3 X" MDim StrMessage
: y1 W- m ^$ |4 `- X2 e! PDim ObjRSA $ A. E0 G$ ^: M+ j) v
LngKeyE = "32823"
; a% a& H$ d: _$ m: H' D' CLngKeyD = "20643" $ K4 ^% w4 @) G) G" i
LngKeyN = "29893"
( G1 A8 S! f7 ]1 ~; aStrMessage = Message
& }% r2 U. j/ ~4 s$ D% X9 hSet ObjRSA = New clsRSA . l: b- x1 R' B$ s1 f
ObjRSA.PrivateKey =LngKeyD
5 R5 d/ k% l; I# v n% pObjRSA.Modulus=LngKeyN
5 D' v% g1 @* q! q5 m0 hdecryptstr=ObjRSA.Decode(StrMessage) 8 m( f( |3 | v7 A4 e( \: u# i; p" r
Set ObjRSA = Nothing 3 a+ n g, ^0 F! c: F! M
end function - q0 A) b) B6 c8 j* _
dim last,first % ]9 B( U9 |9 g3 m3 N/ n
first="!@#$%^&*()"
, U4 ?$ O# {9 gResponse.Write "加密前为:"&first 3 H" v0 z, X) s2 l7 j7 A
last=Encryptstr(first) 3 Y, c, G$ C( x; D( S/ \
Response.Write "加密后为"&last
/ y8 `' @ f- E+ R2 o7 |7 ZResponse.Write "解密后为" &decryptstr(last)
$ t2 P& p0 X! A* |%> ==============================================9 I; }8 [1 |! j* t: w
剩下的就是字符的对照表了: `; N! M( I3 }, o; D
===================字符集================' p7 f$ n6 \) j+ _' R- K8 J
1_____6EBB0 b4 G2 E* D1 d0 ]- D( S; E; h
2_____5C1F
+ W7 P, Q! s# a: P3_____4D757 k( A/ U8 o* t, U
4_____26CC2 z l0 E/ ?( C5 N3 \1 V
5_____4F889 z: Y; z7 X8 T: N! t
6_____3F4E
* A5 ^, c. Z8 d+ J# g7_____0A9D
6 s( m6 V9 m; D4 R! z8_____1A1C% k+ }* ]+ W2 n$ l! Q" Y- x! i
9_____6D20
8 s) C% ~) f+ E, N7 S0_____10894 C( A) Y2 Q7 g; G
a_____0F3E
! r d; ]8 j+ e ~3 C$ C+ K5 g, Mb_____3159! \0 U0 y: V1 i) i0 V
c_____3517 [- |- y0 f ^; h4 A
d_____419C
. l+ r- b% |+ ?( he_____615C
' P; h- k1 z0 |& Nf_____556F- T# |" ]4 o! b
g_____2B7F; t K" ~1 n \! G$ R* f
h_____0F9C; J, u* G' ~) o! J# t
i_____00FA
7 {- _$ J2 S `j_____5A50; _. g3 B6 T+ r6 y" R
k_____2850- B* W2 d/ C/ T" E( q
l_____3E7B
( w* t1 d {$ O* I5 `! dm_____71C56 A" \8 n" u4 c: K2 p" \5 b+ k
n_____1FC8* J4 B6 ~1 R( K* _$ ]* a
o_____74C1
& `- s# r* R$ q4 P/ Gp_____5FB8
1 h" H/ C+ D5 I; n. L2 x) T- }q_____6085$ f- ~2 Q0 J* c1 I9 i( T
r_____3AC40 r# A5 h4 p( e- d
s_____2F50- x9 G2 m6 O% k* H& ^4 M
t_____36F8
. {( j; f7 U; T; R( Au_____7010
8 D8 r( j5 T+ T9 fv_____0B42" [7 w% x9 p2 q- x$ w# y% n4 }4 _1 m
w_____1C7A
* l, n0 \& U4 K' F$ j" hx_____16F8
$ { F) H% h# L$ a% Sy_____2EE7
t" {$ t4 E# W& }3 r; uz_____5CF3
( y; Z" n4 {+ j+ I!_____6233$ ]+ q# E; N$ i" s( F+ I
@_____3A45
2 x/ g" ]- d" Y7 _. @#_____22917 Q o6 g# S* M
$_____5D5C( _! J, l) v9 F: R( l3 `& a
%_____09B9
2 ]" W7 W" F1 Y; \( B^_____43EA
" L2 T {& V* |; H+ U2 e/ `&_____62B9
% [+ ]$ Z& E' M( M& y% i1 ]; T*_____6301
& d2 G0 | x: M7 L7 j2 d! U(_____4659
+ _: ]3 ~; q' K9 ]) ?# T' @1 o; h/ P)_____5C82 |
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