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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm# C0 y; w1 t& O% d2 ^/ T
原始出处:http://www.3ast.com.cm
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看不懂的直接绕过; b1 }1 A2 c! q+ e6 c! [0 O
加密前为:hwy123456, C* E/ O" L3 Q2 f2 l
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E' l. c* q" n4 e2 k- _6 k
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============================================
. b, h+ d' p0 m上面是当时自己校内的心情。现在已经解破出来了,分享给大家
~4 L) V# W# r9 K) u$ @# v# c也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法" G/ k" k9 R. h
以下是RSA算法文件
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文件名RSA.ASP
$ a; h3 d) s) C===============================================
1 ~! n% Q6 J$ b* b<% / p6 p8 {$ X' z+ c3 y6 y6 K
Class clsRSA * \2 v& }8 M2 h0 l9 e# I1 e& }) G
Public PrivateKey
/ @8 i @- L6 o4 Z: H# U6 @Public PublicKey
% C$ T" D. s t3 p' ]/ NPublic Modulus
! \7 A' K/ C3 l( ~0 L: m4 oPublic Function Crypt(pLngMessage, pLngKey)
9 N# R1 q W, y& m- G; g6 i7 ?, ?2 IOn Error Resume Next - j" S% E' {7 t4 a/ W/ B% a. }
Dim lLngMod
4 u& k$ C% w, VDim lLngResult $ ]9 J2 t5 L" K2 b4 I, G
Dim lLngIndex # F) ?, a1 b: \6 z3 V8 h
If pLngKey Mod 2 = 0 Then # T, E F1 h0 K6 ~
lLngResult = 1
0 w0 d0 _" A# C. v% U9 E' `' `2 O$ IFor lLngIndex = 1 To pLngKey / 2
* K: w! {! V; ]0 E" \( s D5 M& MlLngMod = (pLngMessage ^ 2) Mod Modulus
/ ?7 c% V7 p. Y' g2 w# x, J. `' Mod may error on key generation & Z$ u- R" j2 R- u! ]4 w2 `
lLngResult = (lLngMod * lLngResult) Mod Modulus % B t* e. s. B: X9 f. D* G
If Err Then Exit Function X6 ]- `& P0 M' W
Next ! B( l7 i3 }! G" A. @3 u
Else % Z+ K. m( L* j
lLngResult = pLngMessage ; `* q' L) o" D. u8 j+ |; M
For lLngIndex = 1 To pLngKey / 2
3 f: }+ g# j( O1 k1 BlLngMod = (pLngMessage ^ 2) Mod Modulus ' t' F( A& s* e& n" T+ p
On Error Resume Next
: r9 u' w: l/ W7 c! |$ C3 F% T- y' Mod may error on key generation
/ Z$ r; Z# n% n: P" E( u" ?( tlLngResult = (lLngMod * lLngResult) Mod Modulus
' z+ i$ n! k. xIf Err Then Exit Function 7 g- j& e6 l" v) a/ D$ W5 Y
Next
( w: P7 E+ z$ T/ @End If
: Q, l1 L8 d4 [3 a) w" eCrypt = lLngResult
5 q9 D2 s5 _3 U* N. O, S1 z5 C8 XEnd Function
x* o. u7 C8 c# @ m
# g1 i9 d2 u I6 i1 c OPublic Function Encode(ByVal pStrMessage)
$ m7 j6 M* y, Z; J7 x# ADim lLngIndex
0 o. p7 D) Q! U5 R3 m- QDim lLngMaxIndex 1 x; Y, P; x% h* `* k+ v
Dim lBytAscii 3 E* b7 f* c1 P
Dim lLngEncrypted
2 B& ]' I% I% ?% F( alLngMaxIndex = Len(pStrMessage)
# p9 M z$ [3 ?6 d( H6 U1 oIf lLngMaxIndex = 0 Then Exit Function
, f; j6 z8 K& N1 lFor lLngIndex = 1 To lLngMaxIndex ( V9 t% x7 |$ [
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) , F% @6 w* R* A2 l
lLngEncrypted = Crypt(lBytAscii, PublicKey)
6 W5 [5 E* Y" t: NEncode = Encode & NumberToHex(lLngEncrypted, 4)
4 S1 r7 N2 K( P+ `6 C# x- M( Y! ?Next
/ P0 T9 v4 @% M9 W/ W; t" ZEnd Function
* A, C$ {2 x6 W( Q. oPublic Function Decode(ByVal pStrMessage)
. |5 Q) ~9 m& a' ~/ ^: k( l. x. vDim lBytAscii ! W1 a! ]* m9 o! i( g
Dim lLngIndex / a: q0 q8 x' v- Z" m
Dim lLngMaxIndex
0 C; j) {; n+ z/ gDim lLngEncryptedData " v$ } ^3 P5 n2 D8 _3 C
Decode = ""
8 v% ]" W6 `) ?$ x5 t: l- m$ T, ~2 hlLngMaxIndex = Len(pStrMessage) 9 R4 l: V- Z/ J U* k: f
For lLngIndex = 1 To lLngMaxIndex Step 4 ' m/ V) j+ ~5 b4 U* `7 t
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
1 X9 C$ ^9 ?1 {lBytAscii = Crypt(lLngEncryptedData, PrivateKey)
4 }1 H6 J' I% c1 f% [) _2 C2 ODecode = Decode & Chr(lBytAscii)
* o# d$ U3 I; L& k8 r! CNext
$ e/ m) \8 @5 P& R- nEnd Function 8 ]5 ^$ r/ J& w S3 @
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) ' T! O6 d% Y6 x$ c, s0 ~" O
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
+ V' M3 D! E' e$ @ u+ U( XEnd Function
J) x" ?- D8 G1 r6 s q. iPrivate Function HexToNumber(ByRef pStrHex) * s- s7 ]! K( t/ M$ I+ y
HexToNumber = CLng("&h" & pStrHex)
, |5 l4 J, w# l [" NEnd Function ! C6 V+ u; T0 Y1 M. X; F
End Class
: A- I" o9 [$ a' G, [2 i8 V0 pfunction Encryptstr(Message) ) D h J. {* d
Dim LngKeyE $ O& M6 {" R# J$ R3 ~+ l+ K
Dim LngKeyD 7 x( w7 @/ f' G. K! Z* H' u f& f* _
Dim LngKeyN 7 Z$ v! ?! Z* I: W0 y4 f
Dim StrMessage
% M9 U: x7 a6 l3 c- xDim ObjRSA % z U3 w C" T4 ]" [7 H) q' u
LngKeyE = "32823" ' F) l+ j% d, ]& a4 n
LngKeyD = "20643" . W p- m; H( F) O
LngKeyN = "29893" ' @0 w# y; u; E
StrMessage = Message
+ |/ B. J& m) [- kSet ObjRSA = New clsRSA
( x" j) T7 V% n5 ?( i: a( xObjRSA.PublicKey = LngKeyE
2 B) c, }3 D. c( y- MObjRSA.Modulus = LngKeyN
8 C# v* W* V, W# W- e0 kEncryptstr = ObjRSA.Encode(StrMessage)
+ q+ h, M' f5 u4 U; x4 }: n( kSet ObjRSA = Nothing
2 ~8 t% j& }. q: l% j7 S0 wend function: f% f# {- B) Z" ?( K1 M2 p: [
Function Decryptstr(Message) & e1 E7 y: a- k
Dim LngKeyE 5 W) t0 k* w: i) w0 h4 n: w
Dim LngKeyD
. R3 h9 s& e- _, i. `5 P5 QDim LngKeyN ! @2 h# M2 F1 R; p2 J) S
Dim StrMessage
% b0 k( ?) l3 m2 }Dim ObjRSA ( \0 U2 `9 D0 z4 b' b. y) p
LngKeyE = "32823" & J% a9 m$ ?/ Z& L
LngKeyD = "20643" $ H2 V. S( H: R$ R: K9 ^: Z
LngKeyN = "29893"
; M% f3 H% A& u2 IStrMessage = Message
: s6 F! O* h7 C6 z- ?Set ObjRSA = New clsRSA 2 Z+ r+ ]; o/ m
ObjRSA.PrivateKey =LngKeyD . f4 c A( }* a7 t
ObjRSA.Modulus=LngKeyN , W, k. |4 M/ J/ x: q6 w/ D3 p, [
decryptstr=ObjRSA.Decode(StrMessage) 5 Q, P5 s: S V
Set ObjRSA = Nothing
' A/ K% A* N+ wend function
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===============================================
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6 G* v0 L* J s& `" H$ e; S还有一个用于测试这段代码的test.asp
: ]7 N& z6 N& A: m# F4 l有兴趣的自己搭建个IIS测试下
! U+ |. m' Y& ]. B3 P2 p<!--#INCLUDE FILE="RSA.asp"--> 8 Y% s* J: ?' b- G0 p- L, B; o7 O7 r Y$ i
<%( e5 M0 w9 u' @" T
function Encryptstr(Message)
7 I8 t) N' q2 m }5 d& GDim LngKeyE 1 F6 u) C! y/ C& j8 E }
Dim LngKeyD
. m1 _3 v) {& ~9 e5 ^& NDim LngKeyN ' W6 D7 h* J; d
Dim StrMessage 9 [, J9 E- U" z, N/ t/ Y) {
Dim ObjRSA 6 {- x! G5 C/ S7 V
LngKeyE = "32823" $ F$ G- ]- ] i. }8 \. F( {
LngKeyD = "20643"
% a6 t3 z( q0 R9 A" {3 e+ GLngKeyN = "29893" ; u; L, l8 f: j+ D
StrMessage = Message
7 a% U! p! u" U2 v7 |9 c! \Set ObjRSA = New clsRSA # u. }& f9 S1 W# n5 A2 q6 f
ObjRSA.PublicKey = LngKeyE
- M% \) Q$ k) JObjRSA.Modulus = LngKeyN
9 n/ e8 A$ k2 _Encryptstr = ObjRSA.Encode(StrMessage) + M8 |. D6 F! V3 j! ]* s
Set ObjRSA = Nothing
I' I E7 N! _) i2 |end function ; e, `: |5 }1 k- f6 r
function decryptstr(Message) 1 q0 k. m4 _# F2 g' I0 A' G! _. g5 X; F
Dim LngKeyE
) h, e* p, }8 v, O: C4 h% LDim LngKeyD
, L' [9 x* E7 t" k* lDim LngKeyN
; u* I7 \ l/ NDim StrMessage / g& T: n% `; P5 k4 F
Dim ObjRSA 6 `& F5 [# a1 Y3 b( U
LngKeyE = "32823" 2 h+ p- u! T2 x" ] L4 q# i
LngKeyD = "20643"
5 T4 ^* N( K( }, }# h/ s" RLngKeyN = "29893"
% h! s0 H7 c# a2 y# y# vStrMessage = Message
1 h5 i+ M5 B7 v' o1 |' l1 i% qSet ObjRSA = New clsRSA
* v+ Z) m4 o0 v# x/ n i4 gObjRSA.PrivateKey =LngKeyD 7 Q- T, ]. P8 ~6 V5 ?' L0 g( Q4 _* ^
ObjRSA.Modulus=LngKeyN 5 }& X4 G% w) L+ C9 V; a, S. {
decryptstr=ObjRSA.Decode(StrMessage)
0 a o& g/ p% B' |( q" M0 {Set ObjRSA = Nothing
" V. ~/ h6 ?. L' [$ d8 E* {end function # J3 M6 m# w8 {" J. B o
dim last,first / d. O. k* a+ `7 W' ~: R* O% E1 k
first="!@#$%^&*()"
6 ~) j6 V7 q5 i, _5 q3 lResponse.Write "加密前为:"&first
9 h5 p0 i7 a8 o# x" V! @- }8 ~last=Encryptstr(first)
! D9 W: p7 n% `: v7 _: w1 f J5 gResponse.Write "加密后为"&last
! x( N& I; ?6 v. d$ t: H) `5 qResponse.Write "解密后为" &decryptstr(last)
; i2 m/ G0 ~$ T( n1 \8 x%> ==============================================
: F( O8 P4 o1 o$ `* i剩下的就是字符的对照表了
& N' J! g2 G/ I7 v; w* u===================字符集================7 U" p' f, }1 o( _; z
1_____6EBB9 Q5 X7 Y4 J0 ?- T5 ]8 h9 {
2_____5C1F
' b+ y/ c' h5 [* I% H3_____4D75
& q+ x+ Z1 g: | d9 v- r4_____26CC
5 b- T8 d9 c/ [4 e$ k5_____4F883 }* ?: h: s0 T4 _- u
6_____3F4E
; Q, O- Q- {% M6 \7_____0A9D
9 p- H/ q5 r' c8_____1A1C
2 {4 O( q+ r1 ]+ @9 Q9_____6D20! H! ?8 `8 N q! q
0_____1089$ Z" ~* w* ~0 n, w+ L
a_____0F3E: z1 U; f( w! ]& D' {
b_____31591 A$ h+ ^/ @3 J C' u
c_____3517
8 @# w) T; @# d9 k0 N- Gd_____419C6 g) R) j8 }4 a2 U! Y7 |1 r# f
e_____615C
8 k' Y0 v8 ?: {f_____556F: h! W9 g6 Q; [& m' {: M
g_____2B7F
% W, y4 }" e& H- Z8 ^h_____0F9C# a; Y+ Z% q& Q& Z' c( }2 Z
i_____00FA) K+ F$ W$ _, [* Z% z; a7 W$ r- A
j_____5A50; {4 t$ W6 }% w# h
k_____28500 f6 X: S9 `! B
l_____3E7B
9 b4 K! O4 S. K$ J) I0 O1 K- tm_____71C55 W7 ]% x3 z2 q; v+ E% L- B/ v
n_____1FC8
8 Z4 P6 t k+ Y* `6 Mo_____74C17 U z0 }& w0 ^. X4 u: I+ H) R
p_____5FB89 w: R7 e' @+ y& g: o: p
q_____6085* B; ^$ ]' h' P1 W4 A- z, U
r_____3AC4
) P9 X4 H: I6 y$ Ws_____2F50
. t [0 C6 x: L$ St_____36F8
# {9 t% m0 a' i' `/ \* s) Xu_____70104 c m1 Z6 o. w
v_____0B42( m- q4 p( k1 i' N3 {
w_____1C7A
; N, @6 A: a# Wx_____16F85 s. M- Y: a' R8 I
y_____2EE7
) f# Y7 n* ^& q# `z_____5CF3, Y) e8 J/ R% n6 E% i3 G* K
!_____6233
$ S1 {: a# x! r. G; \: V$ A/ F, [@_____3A45$ g' V8 B8 U3 L/ [
#_____2291
; Z* N- t. T- {9 Z" l5 A! r$_____5D5C. Q+ x& V# ?) t: J
%_____09B9; @5 G- Z2 w3 O' B7 D
^_____43EA
2 g2 z7 B0 v1 P9 m# n* f5 _5 n&_____62B9/ M7 ?3 m" I% ~6 V. j" R
*_____6301
# \9 n# s8 g' ~& V% C/ V. g: b(_____4659
- E$ C- H4 \: H. a4 `)_____5C82 |
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